Chapter 37: Q51P (page 1148)
Question: What must be the momentum of a particle with mass m so that the total energy of the particle is 3.00 times its rest energy?
Short Answer
Answer
The momentum of the particle is 2.83 mc.
Chapter 37: Q51P (page 1148)
Question: What must be the momentum of a particle with mass m so that the total energy of the particle is 3.00 times its rest energy?
Answer
The momentum of the particle is 2.83 mc.
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Get started for freeA meter stick in frame makes an angle of with the x’ axis. If that frame moves parallel to the x-axis of frame with speed 0.90c relative to frame , what is the length of the stick as measured from S ?
In a high-energy collision between a cosmic-ray particle and a particle near the top of Earth’s atmosphere, 120 km above sea level, a pion is created. The pion has a total energy E of and is travelling vertically downward. In the pion’s rest frame, the pion decays 35.0 ns after its creation. At what altitude above sea level, as measured from Earth’s reference frame, does the decay occur? The rest energy of a pion is 139.6 MeV.
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Question:As you read this page (on paper or monitor screen), a cosmic ray proton passes along the left–right width of the page with relative speed v and a total energy of 14.24 nJ. According to your measurements, that left–right width is 21.0 cm. (a) What is the width according to the proton’s reference frame? How much time did the passage take according to (b) your frame and (c) the proton’s frame?
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