What is the momentum in MeV/c of an electron with a kinetic energy of 2.00MeV ?

Short Answer

Expert verified

The momentum of the electron is 2.46MeV/c.

Step by step solution

01

Lorentz factor:

The result of the postulate of special relativity is that the clock runs slower for a moving object when measured from a rest frame. The factor by which the clocks run differently is called the Lorentz factor.

The relativistic kinetic energy relation is given by

K=mec2γ-1

Here me is the electron’s rest mass, and γ is the Lorentz factor.

Using this relation to determine the Lorentz factor,

γ=Kmec2+1=2.00×106×1.6×10-19J9.1×10-31kg3×108m/s2+1=3.91+1=4.91

The Lorentz factor is expressed in terms of speed parameter β=v/c as,

γ=11-β2β=1-1γ2=1-14.912=0.979

Hence, the electron is traveling at a speed,

v=βc=0.979c

02

Relativistic Momentum:

The expression for relativistic momentum is given by

p=γmev=γβmec=γβmec2c

The rest mass energy mec2 of the electron is 0.511MeV (Table 37-3).

p=γβcmec2=4.910.979c0.511MeV=2.46MeV/c

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Most popular questions from this chapter

Figure 37-27 is a graph of intensity versus wavelength for light reaching Earth from galaxy NGC 7319, which is about 3×108light-years away. The most intense light is emitted by the oxygen in NGC 7319. In a laboratory that emission is at wavelength λ=513nm, but in the light from NGC 7319 it has been shifted to 525 nm due to the Doppler effect (all the emissions from NGC 7319 have been shifted). (a) What is the radial speed of NGC 7319 relative to Earth? (b) Is the relative motion toward or away from our planet?

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