The uniform rod (length0.60m,mass1.0kg)in Fig. 11-54 rotates in the

plane of the figure about an axis through one end, with a rotational inertia of0.12kg.m2

. As the rod swings through its lowest position, it collides with a0.20kg

putty wad that sticks to the end of the rod. If the rod’s angular speed just before

collision is, 2.4rad/swhat is the angular speed of the rod–putty system immediately after collision?

Short Answer

Expert verified

Angular speed after collision isω=1.5rads.

Step by step solution

01

Step 1: Given

m=1.0kgI1=0.12kg.m2r=0.60m

02

Determining the concept

First, find the total rotational inertia. Using the law of conservation of angular momentum, find the final angular velocity.According tothe conservation of momentum, momentum of a system is constant if no external forces are acting on the system.

Formula are as follow:

I2=I1+mr2

Initialangularmomentum=Finalangularmomentum

Where,Iis moment of inertia,m is mass and ris radius.

03

Determining the angular speed after collision

According to law of conservation of angular momentum:

Initialangularmomentum=Finalangularmomentum

L1=L2I1ω1=I2ω2

I2=I1+m×r2I2=0.12+0.2×0.62=0.3192kg.m20.12×2.4=0.192×ω2

By solving above equation for ω2,

ω2=1.5rad/s

Hence,angular speed after collision isω=1.5rads.

Therefore, angular speed after collision can be calculated by using conservation of momentum principle.

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