A disk, initially rotating at 120rads, is slowed down with a constant angular acceleration of magnitude 120rads2.

(a) How much time does the disk take to stop?

(b) Through what angle does the disk rotate during that time?

Short Answer

Expert verified
  1. The time required for a disk to come to rest,t=30.0 s
  2. The angular displacement of the disk while it comes to rest,θ=1.8×103rad

Step by step solution

01

Determine the given quantities

The initial angular velocity of the disk,ω0=120rads

The angular acceleration of the disk,α=4.0rads2

02

Determine the concept of kinematic equations

Use the kinematic equation for constant angular acceleration to solve for time and angular displacement.

ω=ω0+αt

θ=ωt12αt2

03

(a) Calculate the time required by the disk to take stop.

Kinematic equation for angular motion is:

ω=ω0+αtt=ω-ω0α

Substitute the values and solve further as:

t=01204.0=30.0s

The time required for a disk to come to rest, t=30.0 s.

04

(b) Calculate the rotation angle of disk

Consider the formula for the rotation angle as:

θ=ωt12αt2=0×30.012×(4.0)×30.02=1.8×103 rad

The angular displacement of the disk while it comes to rest,θ=1.8×103rad.

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