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Chapter 10: Q96P (page 293)

Beverage engineering. The pull tab was a major advance in the engineering design of beverage containers. The tab pivots on a central bolt in the can’s top. When you pull upward on one end of the tab, the other end presses downward on a portion of the can’s top that has been scored. If you pull upward with a10 N force, approximately what is the magnitude of the force applied to the scored section? (You will need to examine a can with a pull tab.)

Short Answer

Expert verified

The magnitude of forcethat acts on the scored sectionis25 N .

Step by step solution

01

Step 1: Given

i) Distances,r1=1.8cm,  r2=0.73cm

ii) Force,F1=10 N

02

Determining the concept

As the tab is in equilibrium, the net torque exerted by both forces must be equal. Therefore, by using the formula of torque, find the magnitude of force that acts on the scored section.

The formula is as follows:

τup=τdown

Where, τ is torque

03

Determining themagnitude of force that acts on the scored section

For torque in equilibrium,

τup=τdown

F1r1=F2r2

10 N×1.8 m=F2×0.73 m

F2=(1.8 cm0.73 cm)×(10 N)

F2=25 N

Hence, themagnitude of force that acts on the scored section is25 N .

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Most popular questions from this chapter

In Fig.10-31 , wheel A of radius rA=10 cmis coupled by belt B to wheel C of radius rC=25 cm .The angular speed of wheel A is increased from rest at a constant rate of1.6rads2 . Find the time needed for wheel C to reach an angular speed of 100revmin , assuming the belt does not slip. (Hint: If the belt does not slip, the linear speeds at the two rims must be equal.)

A rigid body is made of three identical thin rods, each with length,L=0.600mfastened together in the form of a letter H (Fig.10-52). The body is free to rotate about a horizontal axis that runs along the length of one of the legs of the H. The body is allowed to fall from rest from a position in which the plane of the H is horizontal. What is the angular speed of the body when the plane of the H is vertical?

Two uniform solid cylinders, each rotating about its central (longitudinal) axis at 235rad/s, have the same mass of 1.25kg but differ in radius. What is the rotational kinetic energy of (a) the smaller cylinder, of radius 0.25m, and (b) the larger cylinder, of radius 0.75m?

In Figure a wheel of radius 0.20m is mounted on a frictionless horizontal axis. The rotational inertia of the wheel about the axis is 0.40kg.m2. A mass less cord wrapped around the wheel’s circumference is attached to a6.0kg box. The system is released from rest. When the box has a kinetic energy of 6.0j,

(a) The wheel’s rotational kinetic energy and

(b) The distance the box has fallen?

(a) If R=12 cm ,M=400 g , andm=50 g in Fig.10−19 , find the speed of the block after it has descended50 cm starting from rest. Solve the problem using energy conservation principles.

(b) Repeat (a) with R=5.0 cm.
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