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Chapter 18: Q91P (page 547)

It is possible to melt ice by rubbing one block of it against another. How much work, in joules, would you have to do to get1.00gof ice to melt?

Short Answer

Expert verified

The work to be done to melt 1.0gof ice is333J.

Step by step solution

01

Identification of given data

a) Mass of the ice,m=1.0g

b) Latent heat of fusion,.L=333KJkgor333Jg

02

Understanding the concept of work 

The work done on the ice by rubbing is given by the amount of heat released by the body due to the melting of the ice, Thus, the heat is defined by the latent heat of the ice with the amount of ice melting. Using the equation for the latent heat of fusion, we can find the work required to melt ice.

Formula:

Heat transferred by the body due to thermal expansion,Q=Lfm…(i)

whereLf is the latent heat of fusion andm is the mass of the substance.

03

Determining the work to melt ice

Using equation (i), we can get the required work in the form of heat to melt the given amount of ice as

Q=333J/g×1.0g=333J

Hence, the value of the required work is 333J.

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