Suppose that you intercept5.0×103 of the energy radiated by a hot sphere that has a radius of0.020m , an emissivity of0.80 , and a surface temperature of500K . How much energy do you intercept in 2.0min?

Short Answer

Expert verified

Energy interprets in 2 min is 8.6J

Step by step solution

01

Identification of given data

  1. Radius of hot sphere,r=0.020 m
  2. Emissivity of the surface,σ=0.80
  3. Temperature of sphere,T=500 K
  4. Time, t=2.0minor120 sec.
02

Significance of Stefan-Boltzmann's law

The total energy released or radiated by a blackbody per unit surface area across all wavelengths in a given period of time is inversely proportional to its thermodynamic temperature to the fourth power.

Using the values given in the problem and the formulas for energy in terms of power as well as Stefan-Boltzmann's law, we can get the answer.

Formula:

The energy radiated by the body in the given time, E=Pt …(i)

The power radiated per area of the surface using Stefan-Boltzmann Law,

P=σεAT4 …(ii)

The total surface area of the sphere, A=4πr2 …(iii)

03

Determining the energy

Using equation (iii), the total area of the surface is given as:

A=4(3.14)(0.020 m)2=5.024×103m2

Using equation (ii) and the given values, we can get the power radiated by the surface as given:

P=(0.80)(5.67×108 W/m2K4)(5.024×103 m2)(500 K)4=14.24W.

Now, the energy radiated by the surface body using equation (i) can be given as:

E=(0.005)(14.24 W)(120 s)=8.54J8.6J

Hence, the value of the energy is 8.6J

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