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Chapter 19: Q26P (page 578)

Question: What is the average translational kinetic energy of nitrogen molecules at 1600 K?

Short Answer

Expert verified

Answer

The average translational kinetic energy of nitrogen moleculesis $3.31 \times 10^{- 20} J$ .

Step by step solution

01

Given data

The temperature of the nitrogen gas molecules is 1600 K.

02

Understanding the concept

The expression for the average kinetic energy is given by,

$K_{a v g} = \frac{3}{2} K T$

Here K is the Boltzmann constant, T is the temperature, K_avg is the average kinetic energy.

The value of k is equal to the $1.38 \times 10^{- 23} J / m o l e c u l e \cdot K$ .

03

Calculate the average translational kinetic energy

Using the expression of the kinetic average energy,

$K_{a v g} = \frac{3}{2} K T$

Substitute $1.38 \times 10^{- 23} J / m o l e c u l e \cdot K$ for k , 1600 k for T into the above equation,

$K_{a v g} = \frac{3}{2} \times 1.38 \times 10^{- 23} \times 1600 K_{a v g} = 3.31 \times 10^{- 20} J$

Therefore the average translational kinetic energy of nitrogen moleculesis $3.31 \times 10^{- 20} J$ .

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Most popular questions from this chapter

Suppose 4.00 molof an ideal diatomic gas, with molecular rotation but not oscillation, experienced a temperature increase of 60.0Kunder constant pressure conditions. What are

The energy transferred as heat Q .
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The work W done by the gas.
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In the p-V diagram of Fig. $19 - 17$ , the gas does $5 J$ of work when taken along isotherm ab and $4 J$ when taken along adiabatic. What is the change in the internal energy of the gas when it is taken along the straight path from a to c?

Question: The temperature and pressure in the Sun’s atmosphere are $2.00 \times 10^{6} K$ and 0.0300 paCalculate the rms speed of free electrons (mass $9.11 \times 10^{- 31} kg$ ) there, assuming they are an ideal gas.

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In a certain particle accelerator, protons travel around a circular path of diameter $23.0 m$ in an evacuated chamber, whose residual gas is at $295 K$ and $1.00 \times 10^{- 6} t o r r$ pressure.

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See all solutions

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