Ten particles are moving with the following speeds: four at200m/s, two at500m/s, and four at600m/s. Calculate their

a) Average speed

b) Rms speed

c) Isvrms>vavg?

Short Answer

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Step by step solution

01

Given data

  • Four particles have speed200 m/s
  • Two particles have speed500m/s
  • Four particles have speed600 m/s
02

Understanding the concept

Average speed is calculated by adding the speed of each molecules and then by dividing the total number of molecules.

The RMS speed of molecules is given by,

vrms=v2N

03

(a) Calculate the average speed

Average speed is given by

Vavg=1Ni=1NVi

We have total of10particles, soN=10

Four particles have speed of 200 m/s.

So,V1=4×200=800

Two particles have speed of .400 m/s

So,V2=2×500=1000

Four particles have speed of.600 m/s

So,V3=4×600=2400

Vavg=1N(V1+V2+V3)

Vavg=110(800+1000+2400)=420 m/s

Therefore the average speed is .420 m/s

04

(b) Calculate the RMS speed Vrms

The rms speed is given by

Vrms=1Ni=1NVi2

Vrms=110[4(200ms)2+2(500ms)2+4(600ms)2=458 m/s

Therefore the RMS speed is 458 m/s.

05

(c) Figure out if Vrms>Vavg

Yes; Vrms>Vavg

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