When1.0molof oxygen (O2) gas is heated at constant pressure starting at,0°C how much energy must be added to the gas as heat to double its volume? (The molecules rotate but do not oscillate.)

Short Answer

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Step by step solution

01

Given data

Number of moles of gas isn=1.0

Temperature;

Ti=0°C=273 K

02

Understanding the concept

The expression for the amount of energy transferred to the gas is given by,

Q=nCPΔT

Here Q is the amount of energy transferred to gas, n is the number of moles, CPis the specific heat capacity at constant pressure and ΔTis the temperature difference.

03

Calculate the amount of energy that must be added to the gas as heat to double its volume

The equation;

Q=nCPΔT

But, for diatomic gas,CP=72R

Substitute 72RforCP

Q=72nRΔT....... (i)

At constant pressure, Boyle’s law gives,

TVTfTi=VfViTf=2TiΔT=TfTi=2TiTi=Ti

Substitute1molfor n, 8.3145J/molK for R and 273KforΔT into the equation (i)

Q=72(1)(8.3145)(273)=7.945×103J8.0×103J

Therefore, the amount of energy that must be added to the gas as heat to double its volume is8.0×103J.

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