Use the definition of scalar product, ${}^{\stackrel{\mathbf{\rightharpoonup }}{\mathbf{a}\mathbf{.}}\mathbf{}\stackrel{\mathbf{\rightharpoonup }}{\mathbf{b}}\mathbf{=}\mathbf{a}\mathbf{b}\mathbf{}\mathbf{c}\mathbf{o}\mathbf{s}\mathbf{\theta }}$and the fact that${}^{\mathbf{a}\mathbf{.}\mathbf{b}\mathbf{=}{\mathbf{a}}_{\mathbf{x}}\mathbf{}{\mathbf{b}}_{\mathbf{x}}\mathbf{+}{\mathbf{a}}_{\mathbf{y}}\mathbf{}{\mathbf{b}}_{\mathbf{y}}\mathbf{+}{\mathbf{a}}_{\mathbf{z}}\mathbf{}{\mathbf{b}}_{\mathbf{z}}}$to calculate the angle between two vectors given bylocalid="1654245592038" ${}^{\overrightarrow{\mathbf{a}\mathbf{}}\mathbf{=}\mathbf{3}\mathbf{.}\mathbf{00}\hat{\mathbf{i}}\mathbf{+}\mathbf{3}\mathbf{.}\mathbf{00}\hat{\mathbf{j}}\mathbf{+}\mathbf{3}\mathbf{.}\mathbf{00}\mathbf{k}}\mathbf{}\mathbf{}$and${}^{\stackrel{\mathbf{\rightharpoonup }}{\mathbf{b}}\mathbf{=}\mathbf{2}\mathbf{.}\mathbf{00}\hat{\mathbf{i}}\mathbf{+}\mathbf{1}\mathbf{.}\mathbf{00}\hat{\mathbf{j}}\mathbf{+}\mathbf{3}\mathbf{.}\mathbf{00}\mathbf{k}}$.

Unlock Step-by-Step Solutions & Ace Your Exams!

• Full Textbook Solutions

  Get detailed explanations and key concepts

• Unlimited Al creation

  Al flashcards, explanations, exams and more...

• Ads-free access

  To over 500 millions flashcards

• Money-back guarantee

  We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!