Two vectors are given by,$\stackrel{\mathbf{\rightharpoonup }}{\mathbf{a}}\mathbf{=}\mathbf{(}\mathbf{4}\mathbf{.}\mathbf{0}\mathbf{}\mathbf{m}\mathbf{)}\hat{\mathbf{i}}\mathbf{-}\mathbf{(}\mathbf{3}\mathbf{.}\mathbf{0}\mathbf{}\mathbf{m}\mathbf{)}\hat{\mathbf{j}}\mathbf{+}\mathbf{(}\mathbf{1}\mathbf{.}\mathbf{0}\mathbf{}\mathbf{m}\mathbf{)}\hat{\mathbf{k}}$And$\stackrel{\mathbf{\rightharpoonup }}{\mathit{b}}\mathbf{=}\mathbf{(}\mathbf{-}\mathbf{1}\mathbf{.}\mathbf{0}\mathbf{}\mathbf{m}\mathbf{)}\hat{\mathbf{i}}\mathbf{+}\mathbf{(}\mathbf{1}\mathbf{.}\mathbf{0}\mathbf{}\mathbf{m}\mathbf{)}\hat{\mathbf{j}}\mathbf{+}\mathbf{(}\mathbf{4}\mathbf{.}\mathbf{0}\mathbf{}\mathbf{m}\mathbf{)}\hat{\mathbf{k}}$In unit-vector notation, findrole="math" localid="1656159321000" $\left(a\right)\stackrel{\mathbf{\rightharpoonup }}{\mathbf{a}}\mathbf{+}\stackrel{\mathbf{\rightharpoonup }}{\mathbf{b}}\mathbf{,}\left(b\right)\stackrel{\mathbf{\rightharpoonup }}{\mathbf{a}}\mathbf{-}\stackrel{\mathbf{\rightharpoonup }}{\mathbf{b}}$and a third vector$\stackrel{\mathbf{\rightharpoonup }}{\mathbf{c}}$such that$\stackrel{\mathbf{\rightharpoonup }}{\mathbf{a}}\mathbf{-}\stackrel{\mathbf{\rightharpoonup }}{\mathbf{b}}\mathbf{=}\mathbf{0}$

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