(a) If a standing wave on a string is given by

y(t)=(3mm)sin(5x)cos(4t)

is there a node or an antinode of the oscillations of the string atx = 0? (b) If the standing wave is given by

y(t)=(3mm)sin(5x+p/2)cos(4t)

is there a node or an antinode at x = 0?

Short Answer

Expert verified
  1. The given standing wave has ‘node’ at x = 0
  2. The given standing wave has ‘anti node’ at x = 0

Step by step solution

01

Given

  1. The equation of a standing wave on a string is, y'(t)=(3mm)sin(5x)cos(4t)
  2. The equation of a standing wave on a string is,y'(t)=(3mm)sin(5x+ττ2)cos(4t)
02

Determining the concept

Determine the node or antinode using the value of amplitude.

03

(a) Determining the node or antinode of the oscillations of the string at x=0 if a standing wave is y'(t)=(3mm) sin(5x) cos(4t)

The given equation of a standing wave on a string is,

y'(t)=(3mm)sin(5x)cos(4t)

Now, usingin this equation,

y'(t)=(3mm)sin(0)cos(4t)=0

As the amplitude of the wave becomes zero at this position, a standing wave has node at x=0.

Hence, the given standing wave has ‘node’ at x = 0.

04

(b) Determining the node or antinode of the oscillations of the string at x=0 if a standing wave is y'(t)=(3mm) sin(5x+ττ2) cos(4t)

The given equation of a standing wave on a string is,

y'(t)=(3mm)sin(5x+ττ2)cos(4t)

Now, using x =0 in this equation,

y'(t)=(3mm)sin(ττ2)cos(4t)=3mmcos4t

This is the maximum amplitude possible for the wave, so at x=0 the given wave has an antinode.

Hence, the given standing wave has ‘antinode’ at x = 0

Therefore, the nodes and antinodes can be determined using the equation of amplitudes.

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