In Fig. 17-46, sound of wavelength 0.850 mis emitted isotropically by point source S. Sound ray 1 extends directly to detector D, at distance L=10.0 m. Sound ray 2 extends to Dvia a reflection (effectively, a “bouncing”) of the sound at a flat surface. That reflection occurs on a perpendicular bisector to the SDline,at distance dfrom the line. Assume that the reflection shifts the sound wave by0.500λ. For what least value of d(other than zero) do the direct sound and the reflected sound arrive at D(a) exactly out of phase and (b) exactly in phase?

Short Answer

Expert verified
  1. The least value of d for which the direct and reflected sounds arrive at D exactly out of phase is,2.10 m.
  2. The least value of d for which the direct and reflected sounds arrive at D exactly in phase is 1.47 m.

Step by step solution

01

The given data

  1. Wavelength of sound emitted isotopically by point source is0.850 m.
  2. Sound ray 1 distance to detector D,L=10.0 m.
  3. Reflection shifts the sound wave by0.500λ
02

Understanding the concept of interference 

We can find the path difference between the direct and reflected waves. Then using the conditions for constructive and destructive interference, we can find the least value of d, for which the direct and reflected sounds arrive at D exactly in phase and out of phase.

Formulae:

The cosine law for side c of triangle,

c2=a2+b22abcosC …(i)

The linear expansion formula,

L=L0(1+αΔT) …(ii)

03

a) Calculation of least value of d for destructive interference 

Path difference between direct and reflected wave using equations (i) and (ii) is given as:

Δx=L2+(2d)2L+0.500λ=(10 m)2+(2d)210 m+0.500(0.850 m)=(10 m)2+(2d)29.575 m

For destructive interference, the least value of d is given as:

Δxλ=0.5,1.5,.(10 m)2+(2d)29.575 m0.850 m=0.5,1.5,.(10 m)2+(2d)29.575 m=0.425 m,1.275 m,.(10 m)2+(2d)2=10 m,10.85 m,..(10 m)2+(2d)2=100 m,117.72 m,...d=0,2.1 m...

Hence the value of d is,0,2.1 m....

Excluding zero, the least value is found to bed=2.10 m.

Therefore, the least value of d for which the direct and reflected sounds arrive at D exactly out of phase is 2.10 m.

04

b) Calculation of least value of d for constructive interference

For constructive interference, the least value of d is given as:

Δxλ=1,2,.(10 m)2+(2d)29.575 m0.850 m=1,2,.(10 m)2+(2d)29.575 m=0.850 m,1.7 m,.(10 m)2+(2d)2=10.425 m,11.275 m,...(10 m)2+(2d)2=108.68 m,127.126 m,..d=1.47 m,2.6 m,...

Solving this, we get the least value of d as:

d=1.47 m

Therefore, the least value of d for which the direct and reflected sounds arrive at D exactly in phase is 1.47 m.

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