Why is the thermal conductivity of superinsulation orders of magnitude lower than the thermal conductivity of ordinary insulation?

Short Answer

Expert verified
Answer: The thermal conductivity of superinsulation is lower than ordinary insulation materials due to the combination of materials used and the presence of a vacuum or extremely low-density gas, which effectively minimizes heat transfer through conduction and convection. Superinsulation materials, such as Vacuum Insulation Panels (VIPs), have a unique structure that reduces heat transfer significantly compared to ordinary insulation materials like fiberglass, cellulose, or mineral wool, making them more effective at insulating spaces and preserving energy.

Step by step solution

01

Thermal Conductivity

Thermal conductivity is a property of materials that describes how well they conduct heat. A material with a high thermal conductivity can quickly transfer heat from one side to the other, whereas a material with a low thermal conductivity will be slower to transfer heat. Insulation materials are designed to have low thermal conductivity to reduce the amount of heat transfer, ultimately conserving energy and providing comfort in living spaces.
02

Ordinary Insulation

Ordinary insulation materials, such as fiberglass, cellulose, or mineral wool, work by trapping pockets of air within their structure. Air has a low thermal conductivity, meaning it is not a good conductor of heat. By trapping air within the insulation, these materials are able to slow down the transfer of heat, thus providing some level of insulation. However, they are not as effective as superinsulation materials at reducing heat transfer due to their differing structures and material properties.
03

Superinsulation

Superinsulation materials are designed to have even lower thermal conductivity than ordinary insulation materials. They achieve this by having multiple layers of materials, each with its own properties, and by employing different mechanisms to minimize heat transfer. One common type of superinsulation is Vacuum Insulation Panels (VIPs), which consist of a rigid core surrounded by an airtight envelope filling with a negligible amount of air or by vacuum. The vacuum significantly decreases heat transfer through conduction and convection, as there is almost no gas present to transfer heat. Additionally, the core material itself is made up of materials, such as silica or expanded polystyrene, with extremely low thermal conductivity.
04

Comparison and Conclusion

The main reason why superinsulation has a thermal conductivity orders of magnitude lower than ordinary insulation is due to the combination of the materials used and the presence of a vacuum or extremely low density gas. This effectively minimizes heat transfer through conduction and convection and results in a significantly lower thermal conductivity compared to ordinary insulation. In conclusion, superinsulation materials have a substantially lower thermal conductivity than ordinary insulation materials due to their unique structure and the mechanisms they employ to reduce heat transfer. This makes them far more effective at insulating spaces and preserving energy, providing both cost savings and improved comfort in various applications.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The rate of heat loss through a unit surface area of a window per unit temperature difference between the indoors and the outdoors is called the \(U\)-factor. The value of the \(U\)-factor ranges from about \(1.25 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) (or \(0.22 \mathrm{Btu} / \mathrm{h} \cdot \mathrm{ft}^{2}{ }^{\circ} \mathrm{F}\) ) for low-e coated, argon-filled, quadruple-pane windows to \(6.25 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) (or \(1.1 \mathrm{Btu} / \mathrm{h} \cdot \mathrm{ft}^{2}{ }^{\circ} \mathrm{F}\) ) for a single-pane window with aluminum frames. Determine the range for the rate of heat loss through a \(1.2-\mathrm{m} \times 1.8-\mathrm{m}\) window of a house that is maintained at \(20^{\circ} \mathrm{C}\) when the outdoor air temperature is \(-8^{\circ} \mathrm{C}\).

A cylindrical fuel rod of \(2 \mathrm{~cm}\) in diameter is encased in a concentric tube and cooled by water. The fuel generates heat uniformly at a rate of \(150 \mathrm{MW} / \mathrm{m}^{3}\). The convection heat transfer coefficient on the fuel rod is \(5000 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), and the average temperature of the cooling water, sufficiently far from the fuel rod, is \(70^{\circ} \mathrm{C}\). Determine the surface temperature of the fuel rod and discuss whether the value of the given convection heat transfer coefficient on the fuel rod is reasonable.

A solid plate, with a thickness of \(15 \mathrm{~cm}\) and a thermal conductivity of \(80 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), is being cooled at the upper surface by air. The air temperature is \(10^{\circ} \mathrm{C}\), while the temperatures at the upper and lower surfaces of the plate are 50 and \(60^{\circ} \mathrm{C}\), respectively. Determine the convection heat transfer coefficient of air at the upper surface and discuss whether the value is reasonable or not for force convection of air.

A \(0.3\)-cm-thick, 12-cm-high, and 18-cm-long circuit board houses 80 closely spaced logic chips on one side, each dissipating \(0.06 \mathrm{~W}\). The board is impregnated with copper fillings and has an effective thermal conductivity of \(16 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\). All the heat generated in the chips is conducted across the circuit board and is dissipated from the back side of the board to the ambient air. Determine the temperature difference between the two sides of the circuit board. Answer: \(0.042^{\circ} \mathrm{C}\)

Consider a 20-cm thick granite wall with a thermal conductivity of \(2.79 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\). The temperature of the left surface is held constant at \(50^{\circ} \mathrm{C}\), whereas the right face is exposed to a flow of \(22^{\circ} \mathrm{C}\) air with a convection heat transfer coefficient of \(15 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Neglecting heat transfer by radiation, find the right wall surface temperature and the heat flux through the wall.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free