A \(1.5-\mathrm{m}\)-long vertical tube is used for condensing saturated steam at \(60^{\circ} \mathrm{C}\). The surface temperature of the tube is maintained at a uniform temperature of \(40^{\circ} \mathrm{C}\) by flowing coolant inside the tube. Determine the heat transfer rate to the tube and the required tube diameter to condense \(12 \mathrm{~kg} / \mathrm{h}\) of steam during the condensation process. Assume wavy-laminar flow and that the tube diameter is large relative to the thickness of the liquid film at the bottom of the tube. Are these good assumptions?

Short Answer

Expert verified
Answer: To calculate the heat transfer rate, first calculate the temperature difference (∆T) between the steam and the tube surface. Then, use the Nusselt number relation for laminar film condensation to determine the heat transfer coefficient (h), Reynolds and Prandtl numbers. Use Newton's Law of Cooling to find the heat transfer rate (Q). To find the required tube diameter (D), calculate the mass flow rate of steam and the condensation rate (G). Finally, use the Reynolds and Prandtl numbers to solve for the tube diameter.

Step by step solution

01

Calculate the temperature difference

We know the surface temperature of the tube is \(40^{\circ} \mathrm{C}\) and the steam temperature is \(60^{\circ} \mathrm{C}\). The temperature difference (∆T) is: ∆T = \(60^{\circ} \mathrm{C}\) - \(40^{\circ} \mathrm{C}\) = \(20^{\circ} \mathrm{C}\)
02

Calculate the heat transfer coefficient (h)

Given that the tube diameter is large relative to the thickness of the liquid film, we can use the following Nusselt number relation for laminar film condensation: Nu = \(0.943 \times (RePr)^{\frac{1}{3}}\) Now, find the Reynolds and Prandtl numbers: Re = \(\frac{4G}{\pi \mu D}\) Pr = \(\frac{c_p \mu}{k}\)
03

Calculate heat transfer rate (Q)

Using Newton's Law of Cooling and knowing the area of the tube's outer surface (A) and the temperature difference (∆T), we can calculate the heat transfer rate (Q) as follows: Q = h A ∆T 2. Finding the tube diameter
04

Calculate mass flow rate of steam

We are given that \(12 \mathrm{~kg} / \mathrm{h}\) of steam must be condensed. Calculate the mass flow rate in \( \mathrm{kg} / \mathrm{s}\): \(\dot{m} = \frac{12 \mathrm{~kg}}{3600 \mathrm{~s}}\)
05

Calculate condensation rate

Now, calculate the condensation rate (G) in \(\mathrm{kg} / \mathrm{m^2\cdot s}\): G = \(\frac{\dot{m}}{A}\)
06

Solve for tube diameter (D)

With G known, Re and Pr can be calculated. Then h can be determined using the Nusselt number relation, and finally, the tube diameter (D) can be calculated: D = \(\frac{4G}{\pi \mu Re}\) Now we have found the heat transfer rate to the tube and the required tube diameter to condense the desired amount of steam. To assess the quality of the assumptions, we can observe the chosen Nusselt number relation and the given tube diameter with respect to the liquid film thickness. If the tube diameter is indeed large relative to the liquid film thickness, then the wavy-laminar flow assumption is reasonable.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Film Condensation
Film condensation is a heat transfer process where a vapor comes into contact with a cooler surface and condenses to form a liquid film. This liquid film then flows down the surface under the influence of gravity in a laminar or turbulent manner depending on various conditions like surface temperature and vapor flow. In the example above, a vertical tube is cooling saturated steam, leading to the formation of a liquid film on its surface.

The effectiveness of condensation is influenced by the mode of condensation (wavy or laminar flow), thickness of the condensate film, temperature difference between the vapor and the surface, and properties of the condensate. Typically, a thinner film provides better heat transfer due to less thermal resistance. When assuming wavy-laminar flow, it indicates a mix of laminar flow with some disturbances that do not fully transition into turbulent flow, which can be a reasonable approximation when the liquid film is relatively thin compared to the tube's diameter.
Nusselt Number
The Nusselt number (Nu) is a dimensionless quantity used in heat transfer calculations and indicates the ratio of convective to conductive heat transfer across a fluid boundary. In the context of condensation, it's a measure of the efficiency of heat transfer from the condensing steam to the cooling surface.

To calculate the Nusselt number, a relation that considers both the Reynolds (Re) and Prandtl (Pr) numbers is used. The formula provided in the original problem, Nu = 0.943×(RePr)^(1/3), takes into account the flow conditions of the condensate film. It assumes a certain correlation between the heat transfer, the momentum transfer (Reynolds number), and the thermal properties of the fluid (Prandtl number), which are crucial to estimating the heat transfer coefficient (h) that is applied to determine the heat transfer rate.
Reynolds Number
The Reynolds number (Re) is a dimensionless value that represents the ratio of inertial forces to viscous forces within a fluid flow. It helps determine the flow regime, characterizing the flow as laminar, transitional, or turbulent. Calculated as Re = (4G)/(πμD) in the textbook solution, where G is the mass flux, μ is the dynamic viscosity, and D is the tube diameter, it is essential for evaluating the behavior of the fluid on the surface while condensing.

A lower Reynolds number corresponds to a smoother, more orderly flow, which suits the film condensation process. In applications like the vertical tube in the given problem, maintaining a certain range for Reynolds number ensures that the wavy-laminar flow assumption remains valid, and thereby the heat transfer coefficient can be calculated more precisely.
Prandtl Number
The Prandtl number (Pr) is another dimensionless number in fluid mechanics that expresses the ratio of momentum diffusivity (kinematic viscosity) to thermal diffusivity. It is given by Pr = (cpμ)/k, where cp is the specific heat at constant pressure, μ is the fluid's dynamic viscosity, and k is the thermal conductivity. The Prandtl number gives insight into the relative thickness of the velocity boundary layer to the thermal boundary layer.

In the process of condensation, a higher Prandtl number would mean the thermal boundary layer is thinner compared to the velocity boundary layer, which can affect the rate of heat transfer. For the steam condensing on the tube surface, the Prandtl number helps ascertain the effect of thermal properties on the condensation process and, along with the Nusselt and Reynolds numbers, determines the heat transfer rate during the condensation.

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Most popular questions from this chapter

Saturated steam at \(55^{\circ} \mathrm{C}\) is to be condensed at a rate of \(10 \mathrm{~kg} / \mathrm{h}\) on the outside of a \(3-\mathrm{cm}\)-outer-diameter vertical tube whose surface is maintained at \(45^{\circ} \mathrm{C}\) by the cooling water. Determine the required tube length. Assume wavylaminar flow, and that the tube diameter is large, relative to the thickness of the liquid film at the bottom of the tube. Are these good assumptions?

When a saturated vapor condenses on a vertical, isothermal flat plate in a continuous film, the rate of heat transfer is proportional to (a) \(\left(T_{s}-T_{\text {sat }}\right)^{1 / 4}\) (b) \(\left(T_{s}-T_{\mathrm{sat}}\right)^{1 / 2}\) (c) \(\left(T_{s}-T_{\text {sat }}\right)^{3 / 4}\) (d) \(\left(T_{s}-T_{\text {sat }}\right)\) (e) \(\left(T_{s}-T_{\mathrm{sat}}\right)^{2 / 3}\)

A manufacturing facility requires saturated steam at \(120^{\circ} \mathrm{C}\) at a rate of \(1.2 \mathrm{~kg} / \mathrm{min}\). Design an electric steam boiler for this purpose under these constraints: \- The boiler will be in cylindrical shape with a heightto-diameter ratio of \(1.5\). The boiler can be horizontal or vertical. \- The boiler will operate in the nucleate boiling regime, and the design heat flux will not exceed 60 percent of the critical heat flux to provide an adequate safety margin. \- A commercially available plug-in type electrical heating element made of mechanically polished stainless steel will be used. The diameter of the heater cannot be between \(0.5 \mathrm{~cm}\) and \(3 \mathrm{~cm}\). \- Half of the volume of the boiler should be occupied by steam, and the boiler should be large enough to hold enough water for \(2 \mathrm{~h}\) supply of steam. Also, the boiler will be well insulated. You are to specify the following: (a) The height and inner diameter of the tank, \((b)\) the length, diameter, power rating, and surface temperature of the electric heating element, \((c)\) the maximum rate of steam production during short periods of overload conditions, and how it can be accomplished.

What is the difference between pool boiling and flow boiling?

A cylindrical rod is used for boiling water at 1 atm. The rod has a diameter of \(1 \mathrm{~cm}\) and its surface has an emissivity of \(0.3\). Determine the film boiling convection heat transfer coefficient at the burnout point. Evaluate the properties of vapor at \(1150^{\circ} \mathrm{C}\). Discuss whether \(1150^{\circ} \mathrm{C}\) is a reasonable film temperature for the vapor properties.

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