What are the heat transfer mechanisms involved during heat transfer in a liquid-to-liquid heat exchanger from the hot to the cold fluid?

Short Answer

Expert verified
Answer: The primary heat transfer mechanisms involved in a liquid-to-liquid heat exchanger are conduction through the solid wall and forced convection on both sides of the wall. Natural convection may also contribute if there is a significant temperature difference and the setup allows it, while radiation has a negligible impact in this scenario.

Step by step solution

01

Understand the heat exchanger system

A liquid-to-liquid heat exchanger is a device designed to transfer heat from one fluid to another in an efficient manner. Typically, one fluid is hot and the other is cold. The purpose is to heat up the cold fluid while cooling down the hot fluid.
02

Recalling heat transfer mechanisms

There are three main heat transfer mechanisms: conduction, convection, and radiation. Let's briefly describe each mechanism: 1. \textbf{Conduction:} It is the transfer of heat within a medium or between two mediums in direct contact due to the motion of atoms, molecules, or electrons. The energy is transferred between the particles without any bulk motion of the medium. 2. \textbf{Convection:} It is the transfer of heat within a fluid due to the movement of fluid particles, caused by differences in temperature or density. Convection can be categorized into two types: natural (or free) convection and forced convection. 3. \textbf{Radiation:} It is the transfer of heat via electromagnetic waves, mainly in the form of infrared radiation. This mechanism does not require a medium or contact between materials to transfer heat.
03

Identifying heat transfer mechanisms in the liquid-to-liquid heat exchanger

In a liquid-to-liquid heat exchanger, the hot and cold fluids are separated by a solid wall (e.g., metal pipe), which prevents them from mixing. The heat will transfer from the hot fluid to the cold fluid through the following mechanisms: 1. \textbf{Conduction:} The solid wall separating the two fluids conducts heat from the hot side to the cold side. This is a major contributor to the heat transfer in this process, as the wall's material is typically a good conductor of heat (e.g., metals). 2. \textbf{Convection:} There are two types of convection mechanisms present in a liquid-to-liquid heat exchanger: a. \textbf{Forced convection} on both hot and cold sides: The fluids flow through the heat exchanger pipes, driven by external forces such as pumps. The forced movement of the fluids causes convective heat exchange on both the hot and cold sides of the solid wall. b. \textbf{Natural convection} (if applicable): If the heat exchanger is placed vertically and has a large temperature difference between the fluids, natural (free) convection may also contribute to the heat transfer process, as fluid density changes cause circulation due to buoyancy forces. 3. \textbf{Radiation:} Although radiation is a fundamental heat transfer mechanism, it has a negligible contribution to the heat transfer in this liquid-to-liquid heat exchange process. Heat exchangers are often insulated to minimize heat loss to the surroundings, so radiation has minimal impact on the energy transfer between the hot and cold fluids.
04

Conclusion

The primary heat transfer mechanisms involved during heat transfer in a liquid-to-liquid heat exchanger from the hot to the cold fluid are conduction through the solid wall and forced convection on both sides of the wall. Natural convection may also contribute to the process if there is a significant temperature difference and the setup allows it. Radiation has a negligible impact on the heat transfer in this scenario.

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Most popular questions from this chapter

A shell-and-tube heat exchanger with 2-shell passes and 12 -tube passes is used to heat water \(\left(c_{p}=4180 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)\) with ethylene glycol \(\left(c_{p}=2680 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)\). Water enters the tubes at \(22^{\circ} \mathrm{C}\) at a rate of \(0.8 \mathrm{~kg} / \mathrm{s}\) and leaves at \(70^{\circ} \mathrm{C}\). Ethylene \(\mathrm{glycol}\) enters the shell at \(110^{\circ} \mathrm{C}\) and leaves at \(60^{\circ} \mathrm{C}\). If the overall heat transfer coefficient based on the tube side is \(280 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), determine the rate of heat transfer and the heat transfer surface area on the tube side.

Saturated water vapor at \(100^{\circ} \mathrm{C}\) condenses in the shell side of a 1 -shell and 2-tube heat exchanger with a surface area of \(0.5 \mathrm{~m}^{2}\) and an overall heat transfer coefficient of \(2000 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Cold water \(\left(c_{p c}=4179 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)\) flowing at \(0.5 \mathrm{~kg} / \mathrm{s}\) enters the tube side at \(15^{\circ} \mathrm{C}\), determine the outlet temperature of the cold water and the heat transfer rate for the heat exchanger.

A cross-flow heat exchanger with both fluids unmixed has an overall heat transfer coefficient of \(200 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), and a heat transfer surface area of \(400 \mathrm{~m}^{2}\). The hot fluid has a heat capacity of \(40,000 \mathrm{~W} / \mathrm{K}\), while the cold fluid has a heat capacity of \(80,000 \mathrm{~W} / \mathrm{K}\). If the inlet temperatures of both hot and cold fluids are \(80^{\circ} \mathrm{C}\) and \(20^{\circ} \mathrm{C}\), respectively, determine the exit temperature of the cold fluid.

Cold water \(\left(c_{p}=4180 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)\) enters the tubes of a heat exchanger with 2 -shell passes and 23 -tube passes at \(14^{\circ} \mathrm{C}\) at a rate of \(3 \mathrm{~kg} / \mathrm{s}\), while hot oil \(\left(c_{p}=2200 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)\) enters the shell at \(200^{\circ} \mathrm{C}\) at the same mass flow rate. The overall heat transfer coefficient based on the outer surface of the tube is \(300 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) and the heat transfer surface area on that side is \(20 \mathrm{~m}^{2}\). Determine the rate of heat transfer using \((a)\) the LMTD method and \((b)\) the \(\varepsilon-\mathrm{NTU}\) method.

Can the temperature of the hot fluid drop below the inlet temperature of the cold fluid at any location in a heat exchanger? Explain.

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