Consider an enclosure consisting of five surfaces. How many view factors does this geometry involve? How many of these view factors can be determined by the application of the reciprocity and summation rules?

Short Answer

Expert verified
Answer: In a five-surface enclosure, 14 out of the 20 total view factors can be determined by applying the reciprocity and summation rules.

Step by step solution

01

1. Understand view factors and their properties

View factor, also known as the configuration factor, is a dimensionless quantity that indicates the proportion of the radiation leaving surface A that strikes surface B. In a given enclosure, there can be several view factors between each pair of surfaces. There are two main rules with respect to view factors, which are the reciprocity rule and the summation rule. 1. Reciprocity rule: For any two surfaces A and B, the view factor F(A->B) * A = F(B->A) * B, where A and B are the areas of the surfaces. 2. Summation rule: The sum of view factors from one surface to all other surfaces within the enclosure is equal to 1, i.e., ΣF(i->j) = 1 for all i surfaces.
02

2. Calculate the number of view factors in the enclosure

In an enclosure with 'n' surfaces, there will be n*(n-1) view factors as each surface can have a view factor with all other surfaces, excluding itself. In this case, the enclosure has 5 surfaces, so the total number of view factors will be: Number of view factors = 5 * (5-1) = 5 * 4 = 20
03

3. Determine view factors by applying the rules

The total number of view factors not involving reciprocity will be half of the 20 view factors calculated. This is because the reciprocity rule states that F(A->B) * A = F(B->A) * B, so if we know F(A->B), then we can easily determine F(B->A). Non-reciprocal view factors = 20 / 2 = 10 The summation rule states that the sum of view factors from one surface to all other surfaces within the enclosure is equal to 1. Since there are 5 surfaces, we can apply the summation rule to 5 sets of view factors. However, applying the summation rule to one surface reduces the need to apply the summation rule to the corresponding surface (due to the reciprocity rule). Therefore, the summation rule can be effectively applied to 4 surfaces. So, view factors determined through summation rule = 4
04

4. Calculate the total possible view factors determined

By combining the view factors determined through the reciprocity rule and the summation rule, we can find the total number of view factors that can be determined. Total view factors determined = Non-reciprocal view factors + View factors determined through summation rule = 10 + 4 = 14 Hence, out of the 20 view factors in the geometry, 14 can be determined by applying the reciprocity and summation rules.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Radiation Heat Transfer
Understanding radiation heat transfer is essential for mastering the principles of how energy is exchanged between surfaces without the need for physical contact or a medium. Radiation heat transfer is one of the three modes of heat transfer, the other two being conduction and convection. It involves the emission of energy in the form of electromagnetic waves, primarily in the infrared spectrum.

When radiation occurs, energy emitted by a surface, known as a black body, can be absorbed, reflected, or transmitted by other surfaces. Key to quantifying this energy transfer is the use of view factors: dimensionless quantities that represent the fraction of radiation leaving one surface that directly impinges on another. These factors depend on the geometry of the involved surfaces as well as their relative orientation and distance.

In practical terms, engineers and designers need to calculate these view factors to ensure proper thermal management in various applications, from building design and HVAC systems to spacecraft thermal control.
Reciprocity Rule
The reciprocity rule is a core principle in the calculation of view factors and is pivotal in simplifying complex heat transfer problems. It is mathematically represented as follows: \( F(A \rightarrow B) \cdot A = F(B \rightarrow A) \cdot B \).

In this equation, \( F(A \rightarrow B) \) denotes the view factor from surface A to surface B, and \( A \) and \( B \) are the areas of the respective surfaces. The rule indicates that the radiation leaving surface A and striking surface B, multiplied by the area of A, is equal to the radiation leaving surface B and striking surface A, multiplied by the area of B.

This principle greatly reduces the effort in calculating view factors, as once you determine the view factor in one direction, the reciprocal direction's view factor can be easily calculated without additional complex measurements.
Summation Rule
The summation rule complements the reciprocity rule by ensuring that energy conservation is accounted for within an enclosure. According to this rule, the sum of all view factors from a given surface to all other surfaces within an enclosure, including itself, must equal 1. Mathematically, it is expressed as: \( \sum F(i \rightarrow j) = 1 \), for any surface \( i \).

This rule becomes particularly useful when we consider complex enclosures with multiple surfaces because it lets us find unknown view factors mathematically without directly measuring them. By ensuring that the total radiative exchange is conserved, the summation rule enable a systematic approach to problems involving radiation heat transfer within an enclosure. Using a combination of the summation and reciprocity rules, one can effectively decrease the total number of independent view factors needed to define the radiation exchange in an enclosure.
Enclosure Analysis
Enclosure analysis is critical for understanding how radiation heat transfer computes within a space bounded by surfaces, such as rooms, furnaces, or spacecraft. It's essentially about mapping out the view factors between every combination of surfaces within the enclosure and applying the summation and reciprocity rules to simplify and solve for the unknowns.

For example, in an enclosure with five surfaces, the calculation begins with the acknowledgment that theoretically there are 20 potential view factors (\( 5 \times (5-1) \) ). However, by applying the reciprocity and summation rules, we can reduce the number of independent view factors we need to solve for. This not only streamlines the process but also minimizes the potential for error. With careful application of the rules and understanding the interactions between surfaces, enclosure analysis can effectively predict thermal behavior, ensuring the successful design of a system or structure's thermal management.

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Most popular questions from this chapter

A cylindrical container whose height and diameter are \(8 \mathrm{~m}\) is filled with a mixture of \(\mathrm{CO}_{2}\) and \(\mathrm{N}_{2}\) gases at \(600 \mathrm{~K}\) and \(1 \mathrm{~atm}\). The partial pressure of \(\mathrm{CO}_{2}\) in the mixture is \(0.15 \mathrm{~atm}\). If the walls are black at a temperature of \(450 \mathrm{~K}\), determine the rate of radiation heat transfer between the gas and the container walls.

What is operative temperature? How is it related to the mean ambient and radiant temperatures? How does it differ from effective temperature?

13-59 This question deals with steady-state radiation heat transfer between a sphere \(\left(r_{1}=30 \mathrm{~cm}\right)\) and a circular disk \(\left(r_{2}=120 \mathrm{~cm}\right)\), which are separated by a center-to- center distance \(h=60 \mathrm{~cm}\). When the normal to the center of disk passes through the center of the sphere, the radiation view factor is given by $$ F_{12}=0.5\left\\{1-\left[1+\left(\frac{r_{2}}{h}\right)^{2}\right]^{-0.5}\right\\} $$ Surface temperatures of the sphere and the disk are \(600^{\circ} \mathrm{C}\) and \(200^{\circ} \mathrm{C}\), respectively; and their emissivities are \(0.9\) and \(0.5\), respectively. (a) Calculate the view factors \(F_{12}\) and \(F_{21}\). (b) Calculate the net rate of radiation heat exchange between the sphere and the disk. (c) For the given radii and temperatures of the sphere and the disk, the following four possible modifications could increase the net rate of radiation heat exchange: paint each of the two surfaces to alter their emissivities, adjust the distance between them, and provide an (refractory) enclosure. Calculate the net rate of radiation heat exchange between the two bodies if the best values are selected for each of the above modifications.

Consider a circular grill whose diameter is \(0.3 \mathrm{~m}\). The bottom of the grill is covered with hot coal bricks at \(950 \mathrm{~K}\), while the wire mesh on top of the grill is covered with steaks initially at \(5^{\circ} \mathrm{C}\). The distance between the coal bricks and the steaks is \(0.20 \mathrm{~m}\). Treating both the steaks and the coal bricks as blackbodies, determine the initial rate of radiation heat transfer from the coal bricks to the steaks. Also, determine the initial rate of radiation heat transfer to the steaks if the side opening of the grill is covered by aluminum foil, which can be approximated as a reradiating surface.

A solid sphere of \(1 \mathrm{~m}\) diameter at \(600 \mathrm{~K}\) is kept in an evacuated equilateral triangular enclosure (a tetrahedron) whose side length is \(L\). Note that for the sphere to touch the tetrahedron's_surfaces, the tetrahedron's side length should be \(L=D \sqrt{6}\). The emissivity of the sphere is \(0.45\) and the temperature of the enclosure is \(420 \mathrm{~K}\). If heat is generated uniformly within the sphere at a rate of \(3100 \mathrm{~W}\), determine (a) the view factor from the enclosure to the sphere and \((b)\) the emissivity of the enclosure.

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