For the absorption of a gas (like carbon dioxide) into a liquid (like water) Henry's law states that partial pressure of the gas is proportional to the mole fraction of the gas in the liquid-gas solution with the constant of proportionality being Henry's constant. A bottle of soda pop \(\left(\mathrm{CO}_{2}-\mathrm{H}_{2} \mathrm{O}\right)\) at room temperature has a Henry's constant of \(17,100 \mathrm{kPa}\). If the pressure in this bottle is \(120 \mathrm{kPa}\) and the partial pressure of the water vapor in the gas volume at the top of the bottle is neglected, the concentration of the \(\mathrm{CO}_{2}\) in the liquid \(\mathrm{H}_{2} \mathrm{O}\) is (a) \(0.003 \mathrm{~mol}-\mathrm{CO}_{2} / \mathrm{mol}\) (b) \(0.007 \mathrm{~mol}-\mathrm{CO}_{2} / \mathrm{mol}\) (c) \(0.013 \mathrm{~mol}-\mathrm{CO}_{2} / \mathrm{mol}\) (d) \(0.022 \mathrm{~mol}-\mathrm{CO}_{2} / \mathrm{mol}\) (e) \(0.047 \mathrm{~mol}-\mathrm{CO}_{2} / \mathrm{mol}\)

Short Answer

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Question: Using Henry's Law, find the concentration of CO2 in the liquid in a bottle of soda pop, given Henry's constant for CO2-H2O solution at room temperature is 17,100 kPa and the pressure in the bottle is 120 kPa. The partial pressure of water vapor is neglected. Answer: The concentration of CO2 in the liquid is 0.007 mol CO2/mol.

Step by step solution

01

Understand Henry's Law

Henry's Law states that the partial pressure of a gas (\(P_{\text{gas}}\)) is proportional to the mole fraction of the gas (X) in the liquid-gas solution, with the proportionality constant being Henry's constant (K_H). Mathematically, it can be represented as: \(P_{\text{gas}} = K_H \times X\)
02

Identify the given information

We are given the following information: - Henry's constant (K_H) for CO2-H2O solution at room temperature = 17,100 kPa - The pressure in the bottle (P_bottle) = 120 kPa. Since the partial pressure of water vapor is neglected, we can consider this the partial pressure of CO2.
03

Apply Henry's Law to find the mole fraction of CO2 in the liquid

Using the given information and Henry's Law, we can find the mole fraction of CO2 in the liquid solution: \(P_{\text{CO}_{2}} = K_H \times X_{\text{CO}_{2}}\) Plug in the values: \(120 \,\text{kPa} = 17100\, \text{kPa} \times X_{\text{CO}_{2}}\) Solve for \(X_{\text{CO}_{2}}\): \(X_{\text{CO}_{2}} = \frac{120}{17100}\) \(X_{\text{CO}_{2}} = 0.007 \, \text{mol CO}_{2} \, / \, \text{mol}\)
04

Determine the concentration of CO2 in the liquid

We have now found the mole fraction of CO2 in the liquid, which is also equal to the concentration of CO2 in the liquid: Concentration of CO2 = \(0.007 \, \text{mol CO}_{2} \,/\, \text{mol}\) Thus, the correct answer is (b) \(0.007 \, \text{mol CO}_{2} \,/\, \text{mol}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Partial Pressure
Understanding partial pressure is crucial when studying the behavior of gases. It refers to the pressure that a single gas in a mixture of gases would exert if it occupied the entire volume on its own. In simpler terms, it's the contribution of each gas in a mixture to the total pressure.

When considering Henry's Law, the partial pressure of the gas above a liquid solution is directly related to how much of that gas gets dissolved in the liquid. For instance, in a bottle of soda, the partial pressure of carbon dioxide (CO2) is an indicator of how much CO2 is present in the water as a dissolved gas. In our exercise, by calculating the partial pressure, we can use Henry's Law to determine the concentration of CO2 dissolved in water.
Mole Fraction
The mole fraction is a way of expressing the concentration of a component in a mixture. It is defined as the ratio of the number of moles of one component to the total number of moles of all components in the mixture.

To calculate the mole fraction, you would use the formula:\[\begin{equation}X_{component} = \frac{n_{component}}{n_{total}}\end{equation}\]
where \(n_{component}\) is the number of moles of the component of interest, and \(n_{total}\) is the total number of moles of all components in the mixture. This dimensionless quantity helps us understand the composition of the solution without worrying about the actual amounts. In the context of gas absorption, the mole fraction can be used to describe the proportion of gas molecules dissolved in the liquid.
Gas Absorption in Liquid
Gas absorption in liquid involves the transfer of a gas into a liquid medium. The extent to which a gas is absorbed depends on factors like temperature, pressure, and the nature of the gas and liquid. According to Henry's Law, at a constant temperature, the amount of gas that dissolves in a liquid is directly proportional to the partial pressure of that gas in contact with the liquid.

This principle is particularly evident in the creation of carbonated beverages, where CO2 is dissolved under high pressure to create the fizz. When you open a bottle of soda, you decrease the partial pressure of CO2, leading to the release of gas from the liquid and the formation of bubbles.
Concentration Calculation
The concentration calculation is essential in chemistry to determine the amount of substance within a specific volume of a solution. It's often expressed as molarity, which is the number of moles of a solute per liter of solution. In relation to Henry's Law, the concentration of a gas in a liquid can be calculated once the mole fraction is known.

To transition from a mole fraction to concentration, under the assumption that the liquid's composition remains relatively unchanged, the mole fraction can be treated as an actual concentration. This simplification is useful for understanding the solubility of gases in liquids and is fundamental in various fields including environmental engineering, physiology, and beverage production.

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Most popular questions from this chapter

You probably have noticed that balloons inflated with helium gas rise in the air the first day during a party but they fall down the next day and act like ordinary balloons filled with air. This is because the helium in the balloon slowly leaks out through the wall while air leaks in by diffusion. Consider a balloon that is made of \(0.1\)-mm-thick soft rubber and has a diameter of \(15 \mathrm{~cm}\) when inflated. The pressure and temperature inside the balloon are initially \(110 \mathrm{kPa}\) and \(25^{\circ} \mathrm{C}\). The permeability of rubber to helium, oxygen, and nitrogen at \(25^{\circ} \mathrm{C}\) are \(9.4 \times 10^{-13}, 7.05 \times 10^{-13}\), and \(2.6 \times 10^{-13} \mathrm{kmol} / \mathrm{m} \cdot \mathrm{s} \cdot\) bar, respectively. Determine the initial rates of diffusion of helium, oxygen, and nitrogen through the balloon wall and the mass fraction of helium that escapes the balloon during the first \(5 \mathrm{~h}\) assuming the helium pressure inside the balloon remains nearly constant. Assume air to be 21 percent oxygen and 79 percent nitrogen by mole numbers and take the room conditions to be \(100 \mathrm{kPa}\) and \(25^{\circ} \mathrm{C}\).

During a hot summer day, a \(2-L\) bottle drink is to be cooled by wrapping it in a cloth kept wet continually and blowing air to it with a fan. If the environment conditions are \(1 \mathrm{~atm}, 80^{\circ} \mathrm{F}\), and 30 percent relative humidity, determine the temperature of the drink when steady conditions are reached.

A tank with a 2-cm-thick shell contains hydrogen gas at the atmospheric conditions of \(25^{\circ} \mathrm{C}\) and \(90 \mathrm{kPa}\). The charging valve of the tank has an internal diameter of \(3 \mathrm{~cm}\) and extends \(8 \mathrm{~cm}\) above the tank. If the lid of the tank is left open so that hydrogen and air can undergo equimolar counterdiffusion through the 10 -cm- long passageway, determine the mass flow rate of hydrogen lost to the atmosphere through the valve at the initial stages of the process.

Consider a piece of steel undergoing a decarburization process at \(925^{\circ} \mathrm{C}\). The mass diffusivity of carbon in steel at \(925^{\circ} \mathrm{C}\) is \(1 \times 10^{-7} \mathrm{~cm}^{2} / \mathrm{s}\). Determine the depth below the surface of the steel at which the concentration of carbon is reduced to \(40 \%\) from its initial value as a result of the decarburization process for \((a)\) an hour and \((b)\) ten hours. Assume the concentration of carbon at the surface is zero throughout the decarburization process.

Determine the mole fraction of the water vapor at the surface of a lake whose temperature is \(15^{\circ} \mathrm{C}\) and compare it to the mole fraction of water in the lake. Take the atmospheric pressure at lake level to be \(92 \mathrm{kPa}\).

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