Using solubility data of a solid in a specified liquid, explain how you would determine the mass fraction of the solid in the liquid at the interface at a specified temperature.

Short Answer

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Answer: To calculate the mass fraction of a solid in a liquid, use the following steps: 1. Obtain the solubility data for the solid in the liquid at the specified temperature 2. Convert the solubility data to mass fraction by expressing it in terms of mass of solute per total mass of the solution, using the density of the solvent 3. Calculate the mass fraction using the formula: Mass fraction = Mass of solute / (Mass of solute + Mass of solvent) Using the specific solubility data and the density of the solvent, follow the steps above to find the mass fraction of the solid in the liquid at the given temperature.

Step by step solution

01

Obtain the solubility data

Consult a table or other source for the solubility of the given solid in the specified liquid at the given temperature. Solubility data is usually expressed in terms of mass of solute per volume or mass of solvent (e.g., g/100 mL or g/100 g).
02

Convert solubility data to mass fraction

To calculate the mass fraction of the solid in the liquid, we need to express the solubility data in terms of mass of solute per total mass of the solution. If the solubility is in g/100 mL (grams of solute per 100 mL of solvent), we will first need to convert it to g/100 g (grams of solute per 100 g of solvent) by using the density of the solvent: Mass of solvent = Volume of solvent * Density of solvent For example, if the solubility data is given as 20 g/100 mL and the density of the solvent is 1 g/mL, then: Mass of solvent = 100 mL * 1 g/mL = 100 g Now we have the solubility as 20 g of solute per 100 g of solvent.
03

Calculate the mass fraction of the solid

To calculate the mass fraction of the solid in the liquid, we use this formula: Mass fraction = Mass of solute / (Mass of solute + Mass of solvent) Using the solubility data from Step 2 (20 g/100 g), we can determine the mass fraction: Mass fraction = (20 g) / (20 g + 100 g) = 20/120 = 1/6 So, the mass fraction of the solid in the liquid at the given temperature is 1/6 or approximately 0.167 (16.7%). Remember to replace the values in these calculations with the specific solubility data and the density of the solvent for the given solid and liquid.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solubility Data Interpretation
Understanding solubility data is crucial for scientists and engineers working with solutions. Solubility indicates how much of a solute can dissolve in a solvent at a specific temperature to form a saturated solution. It is often found in handbooks or experimental data sources and is expressed in various units like grams per 100 milliliters (g/100 mL) or grams per 100 grams (g/100g).

To interpret this data accurately, you'll need to consider the units provided and the context of the problem. For instance, solubility in g/100mL implies a volume-based measurement which requires knowledge of the density of the solvent to convert to a mass-based metric if needed. The latter, g/100g, directly relates to the mass of the substance and is used in mass fraction calculations without further conversions.

When you're given solubility data, ensure you've adjusted for temperature, which can significantly impact the amount of solute that will dissolve. Knowing how to interpret and correctly manipulate solubility data is the foundation for calculating mass fractions and understanding the effects of temperature on solubility.
Mass Fraction Calculation
The mass fraction, an essential concept in many scientific and engineering disciplines, represents the ratio of a solute's mass to the total mass of the solution (the sum of the solute's mass and the solvent's mass).

To compute the mass fraction of a solid solute in a liquid solvent, one must employ the equation:
\[ \text{Mass fraction} = \frac{\text{Mass of solute}}{(\text{Mass of solute} + \text{Mass of solvent})} \]

For practical exercises where solubility data is provided, typically, you'd convert this data into a mass-on-mass basis if it isn’t already. After conversion, use the formula above, dividing the solute's mass by the total mass of the solution. The result is a dimensionless number ranging from 0 (no solute present) to 1 (pure solute), which can also be expressed as a percentage.

Calculating mass fractions accurately is critical in industries such as pharmaceuticals, where precise concentrations of ingredients are required for safety and efficacy. This calculation helps in formulating mixtures with proper concentrations and is vital for quality control processes.
Temperature Influence on Solubility
Temperature plays a pivotal role in the solubility of substances, generally causing an increase in solubility for solid solutes as it rises. However, this isn't a uniform rule; some substances decrease in solubility with an increase in temperature.

In a typical solubility curve, which plots solubility against temperature, one can observe how a substance’s solubility changes as temperature varies. For many solids, the curve slopes upward indicating greater solubility at higher temperatures – a fact crucial when dealing with solutions in chemical reactions, food preparations, and manufacturing processes.

When calculating the mass fraction of a solute at a specific temperature, it's imperative to use the solubility data corresponding to that temperature. If you're working with scenarios that involve temperature fluctuations, you’ll have to account for these changes in your calculations. Knowledge about temperature influence on solubility ensures successful processes in temperature-sensitive applications, reinforcing the importance of thermodynamics in chemistry and material science.

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Most popular questions from this chapter

A recent attempt to circumnavigate the world in a balloon used a helium-filled balloon whose volume was \(7240 \mathrm{~m}^{3}\) and surface area was \(1800 \mathrm{~m}^{2}\). The skin of this balloon is \(2 \mathrm{~mm}\) thick and is made of a material whose helium diffusion coefficient is \(1 \times 10^{-9} \mathrm{~m}^{2} / \mathrm{s}\). The molar concentration of the helium at the inner surface of the balloon skin is \(0.2 \mathrm{kmol} / \mathrm{m}^{3}\) and the molar concentration at the outer surface is extremely small. The rate at which helium is lost from this balloon is (a) \(0.26 \mathrm{~kg} / \mathrm{h}\) (b) \(1.5 \mathrm{~kg} / \mathrm{h}\) (c) \(2.6 \mathrm{~kg} / \mathrm{h}\) (d) \(3.8 \mathrm{~kg} / \mathrm{h}\) (e) \(5.2 \mathrm{~kg} / \mathrm{h}\)

Air flows in a 4-cm-diameter wet pipe at \(20^{\circ} \mathrm{C}\) and \(1 \mathrm{~atm}\) with an average velocity of \(4 \mathrm{~m} / \mathrm{s}\) in order to dry the surface. The Nusselt number in this case can be determined from \(\mathrm{Nu}=0.023 \mathrm{Re}^{0.8} \mathrm{Pr}^{0.4}\) where \(\mathrm{Re}=10,550\) and \(\operatorname{Pr}=0.731\). Also, the diffusion coefficient of water vapor in air is \(2.42 \times\) \(10^{-5} \mathrm{~m}^{2} / \mathrm{s}\). Using the analogy between heat and mass transfer, the mass transfer coefficient inside the pipe for fully developed flow becomes (a) \(0.0918 \mathrm{~m} / \mathrm{s}\) (b) \(0.0408 \mathrm{~m} / \mathrm{s}\) (c) \(0.0366 \mathrm{~m} / \mathrm{s}\) (d) \(0.0203 \mathrm{~m} / \mathrm{s}\) (e) \(0.0022 \mathrm{~m} / \mathrm{s}\)

Consider a glass of water in a room at \(20^{\circ} \mathrm{C}\) and \(97 \mathrm{kPa}\). If the relative humidity in the room is 100 percent and the water and the air are in thermal and phase equilibrium, determine (a) the mole fraction of the water vapor in the air and \((b)\) the mole fraction of air in the water.

The diffusion of water vapor through plaster boards and its condensation in the wall insulation in cold weather are of concern since they reduce the effectiveness of insulation. Consider a house that is maintained at \(20^{\circ} \mathrm{C}\) and 60 percent relative humidity at a location where the atmospheric pressure is \(97 \mathrm{kPa}\). The inside of the walls is finished with \(9.5\)-mm-thick gypsum wallboard. Taking the vapor pressure at the outer side of the wallboard to be zero, determine the maximum amount of water vapor that will diffuse through a \(3-\mathrm{m} \times 8-\mathrm{m}\) section of a wall during a 24-h period. The permeance of the \(9.5\)-mm-thick gypsum wallboard to water vapor is \(2.86 \times 10^{-9} \mathrm{~kg} / \mathrm{s} \cdot \mathrm{m}^{2} \cdot \mathrm{Pa}\).

When handling corrosive and toxic substances, chemical resistant gloves should be worn. When selecting gloves to handle a substance, the suitability of the gloves should be considered. Depending on the material of the gloves, they could be easily permeable by some substances. An employee is handling tetrachloroethylene solution for a metal-cleaning process. Dermal exposure to tetrachloroethylene can cause skin irritation, and long-term exposure to it can have adverse neurological effects on humans. As a protective measure, the employee wears rubber-blend gloves while handling the tetrachloroethylene solution. The average thickness of the gloves is \(0.67 \mathrm{~mm}\), and the mass diffusivity of tetrachloroethylene in the gloves is \(3 \times 10^{-8} \mathrm{~m}^{2} / \mathrm{s}\). Estimate how long can the employee's hand be in contact with the tetrachloroethylene solution before the concentration of the solution at the inner glove surface reaches \(1 \%\) of the concentration at the outer surface. Is this type of glove suitable for handling tetrachloroethylene solution?

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