What is permeability? How is the permeability of a gas in a solid related to the solubility of the gas in that solid?

Short Answer

Expert verified
Answer: The permeability of a gas in a solid is related to the solubility of the gas in that solid. A higher solubility indicates stronger interactions between the gas and the solid, which can lead to a higher permeability. The permeability of a gas in a solid can be quantified using a diffusion coefficient, and the equation that relates permeability, solubility, and diffusion coefficient is: Permeability = Solubility × Diffusion Coefficient.

Step by step solution

01

Define permeability

Permeability is the measure of the ability of a material to allow the passage of a fluid (in this case, a gas) through it. It depends on the nature of the material, the size of the gas molecules, and the interaction between the gas molecules and the material. In the context of a gas permeating through a solid, permeability is influenced by factors such as the porosity of the solid and the affinity between the gas and the solid.
02

Define solubility

Solubility is the ability of a substance (a solute) to dissolve in another substance (a solvent) to form a homogenous mixture (a solution). In this case, solubility refers to the ability of a gas to dissolve in a solid. This depends on the nature of both the gas and the solid, as well as the temperature and pressure conditions.
03

Understand the relationship between permeability and solubility

The permeability of a gas in a solid is related to the solubility of the gas in that solid. A higher solubility of the gas in the solid indicates that there's a stronger interaction between the gas molecules and the solid, which can lead to a higher permeability. In other words, if a gas dissolves easily within the solid, it's more likely to permeate through the solid.
04

Consider the diffusion coefficient

The permeability of a gas in a solid can be quantified using a diffusion coefficient, which describes how fast the gas molecules move through the solid. The diffusion coefficient depends on factors such as the size of the gas molecules, the porosity of the solid, and the affinity between the gas and the solid. In general, a higher diffusion coefficient leads to higher permeability.
05

Apply the relationship between permeability, solubility, and diffusion coefficient

To understand the relationship between the permeability, solubility, and diffusion coefficient, we can use the following equation: Permeability = Solubility × Diffusion Coefficient This equation shows that the permeability of a gas in a solid is directly proportional to both the solubility and the diffusion coefficient. In summary, the permeability of a gas in a solid is related to the solubility of the gas in that solid. A higher solubility indicates stronger interactions between the gas and the solid, which can lead to a higher permeability. The permeability of a gas in a solid can be quantified using a diffusion coefficient, and the equation that relates permeability, solubility, and diffusion coefficient is: Permeability = Solubility × Diffusion Coefficient.

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Most popular questions from this chapter

Benzene-free air at \(25^{\circ} \mathrm{C}\) and \(101.3 \mathrm{kPa}\) enters a 5 -cm-diameter tube at an average velocity of \(5 \mathrm{~m} / \mathrm{s}\). The inner surface of the \(6-m\)-long tube is coated with a thin film of pure benzene at \(25^{\circ} \mathrm{C}\). The vapor pressure of benzene \(\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)\) at \(25^{\circ} \mathrm{C}\) is \(13 \mathrm{kPa}\), and the solubility of air in benezene is assumed to be negligible. Calculate \((a)\) the average mass transfer coefficient in \(\mathrm{m} / \mathrm{s},(b)\) the molar concentration of benzene in the outlet air, and \((c)\) the evaporation rate of benzene in \(\mathrm{kg} / \mathrm{h}\).

A tank with a 2-cm-thick shell contains hydrogen gas at the atmospheric conditions of \(25^{\circ} \mathrm{C}\) and \(90 \mathrm{kPa}\). The charging valve of the tank has an internal diameter of \(3 \mathrm{~cm}\) and extends \(8 \mathrm{~cm}\) above the tank. If the lid of the tank is left open so that hydrogen and air can undergo equimolar counterdiffusion through the 10 -cm- long passageway, determine the mass flow rate of hydrogen lost to the atmosphere through the valve at the initial stages of the process.

Saturated water vapor at \(25^{\circ} \mathrm{C}\left(P_{\text {sat }}=3.17 \mathrm{kPa}\right)\) flows in a pipe that passes through air at \(25^{\circ} \mathrm{C}\) with a relative humidity of 40 percent. The vapor is vented to the atmosphere through a \(7-\mathrm{mm}\) internal-diameter tube that extends \(10 \mathrm{~m}\) into the air. The diffusion coefficient of vapor through air is \(2.5 \times 10^{-5} \mathrm{~m}^{2} / \mathrm{s}\). The amount of water vapor lost to the atmosphere through this individual tube by diffusion is (a) \(1.02 \times 10^{-6} \mathrm{~kg}\) (b) \(1.37 \times 10^{-6} \mathrm{~kg}\) (c) \(2.28 \times 10^{-6} \mathrm{~kg}\) (d) \(4.13 \times 10^{-6} \mathrm{~kg}\) (e) \(6.07 \times 10^{-6} \mathrm{~kg}\)

A thick wall made of natural rubber is exposed to pure oxygen gas on one side of its surface. Both the wall and oxygen gas are isothermal at \(25^{\circ} \mathrm{C}\), and the oxygen concentration at the wall surface is constant. Determine the time required for the oxygen concentration at \(x=5 \mathrm{~mm}\) to reach \(5 \%\) of its concentration at the wall surface.

Show that for an ideal gas mixture maintained at a constant temperature and pressure, the molar concentration \(C\) of the mixture remains constant but this is not necessarily the case for the density \(\rho\) of the mixture.

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