Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 14: Problem 65

What are the adverse effects of excess moisture on the wood and metal components of a house and the paint on the walls?

Short Answer

Expert verified
Answer: Excess moisture can cause swelling, warping, and rot in wooden components, rust and corrosion in metal components, and blistering, peeling, or discoloration in paint on the walls. These effects can lead to weakened structures, potential component failure, mold growth, and costly repairs.

Step by step solution

01

Adverse Effects on Wood Components

Excess moisture can cause swelling, warping, and rot in wooden components of a house. When wood absorbs water, it expands, which can lead to deformation of doors, windows, and flooring. Constant exposure to water over time can also result in wood rot, which weakens the wood structure and can even cause it to collapse.
02

Adverse Effects on Metal Components

Excessive moisture can cause rust and corrosion in metal components of the house, such as pipes, nails, and fasteners. Rust occurs when metal comes in contact with water and oxygen, which gradually eats away at the metal. This process can eventually lead to the weakening and potential failure of these components, which may require expensive repairs or replacement.
03

Adverse Effects on Paint on the Walls

Excess moisture can have a negative impact on the paint on the walls, causing it to blister, peel, or become discolored. High humidity levels can prevent the paint from drying correctly, leaving it susceptible to mold and mildew growth. Mold can eat away at the paint and even damage the underlying wall material, requiring costly repairs and repainting.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Consider one-dimensional mass transfer in a moving medium that consists of species \(A\) and \(B\) with \(\rho=\rho_{A}+\rho_{B}=\) constant. Mark these statements as being True or False. (a) The rates of mass diffusion of species \(A\) and \(B\) are equal in magnitude and opposite in direction. (b) \(D_{A B}=D_{B A}\). (c) During equimolar counterdiffusion through a tube, equal numbers of moles of \(A\) and \(B\) move in opposite directions, and thus a velocity measurement device placed in the tube will read zero. (d) The lid of a tank containing propane gas (which is heavier than air) is left open. If the surrounding air and the propane in the tank are at the same temperature and pressure, no propane will escape the tank and no air will enter.

A heated piece of steel, with a uniform initial carbon concentration of \(0.20 \%\) by mass, was exposed to a carburizing atmosphere for an hour. Throughout the entire process, the carbon concentration on the surface was \(0.70 \%\). If the mass diffusivity of carbon in steel in this process was uniform at \(1 \times\) \(10^{-11} \mathrm{~m}^{2} / \mathrm{s}\), determine the percentage of mass concentration of carbon at \(0.2 \mathrm{~mm}\) and \(0.4 \mathrm{~mm}\) below the surface after the process.

Explain how vapor pressure of the ambient air is determined when the temperature, total pressure, and relative humidity of the air are given.

Nitrogen gas at high pressure and \(298 \mathrm{~K}\) is contained in a \(2-\mathrm{m} \times 2-\mathrm{m} \times 2-\mathrm{m}\) cubical container made of natural rubber whose walls are \(4 \mathrm{~cm}\) thick. The concentration of nitrogen in the rubber at the inner and outer surfaces are \(0.067 \mathrm{~kg} / \mathrm{m}^{3}\) and \(0.009 \mathrm{~kg} / \mathrm{m}^{3}\), respectively. The diffusion coefficient of nitrogen through rubber is \(1.5 \times 10^{-10} \mathrm{~m}^{2} / \mathrm{s}\). The mass flow rate of nitrogen by diffusion through the cubical container is (a) \(8.24 \times 10^{-10} \mathrm{~kg} / \mathrm{s}\) (b) \(1.35 \times 10^{-10} \mathrm{~kg} / \mathrm{s}\) (c) \(5.22 \times 10^{-9} \mathrm{~kg} / \mathrm{s}\) (d) \(9.71 \times 10^{-9} \mathrm{~kg} / \mathrm{s}\) (e) \(3.58 \times 10^{-8} \mathrm{~kg} / \mathrm{s}\)

When the ___ is unity, one can expect the momentum and mass transfer by diffusion to be the same. (a) Grashof (b) Reynolds (c) Lewis (d) Schmidt (e) Sherwood
See all solutions

Recommended explanations on Physics Textbooks

Geometrical and Physical Optics

Read Explanation

Fluids

Read Explanation

Electricity

Read Explanation

Engineering Physics

Read Explanation

Linear Momentum

Read Explanation

Waves Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free