Write down the one-dimensional transient heat conduction equation for a long cylinder with constant thermal conductivity and heat generation, and indicate what each variable represents.

Short Answer

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#Short Answer# The one-dimensional transient heat conduction equation for a long cylinder with constant thermal conductivity and internal heat generation is: \(\frac{1}{r}\frac{\partial}{\partial r}(r \frac{\partial T}{\partial r}) + \frac{q_g}{k} = \rho C_p \frac{\partial T}{\partial t}\) where T represents the temperature, r is the radial distance from the center of the cylinder, t is the time, k is the constant thermal conductivity, \(q_g\) denotes heat generation per unit volume, ρ symbolizes material density, and \(C_p\) stands for the specific heat capacity of the material.

Step by step solution

01

1. Heat Conduction Equation for a Long Cylinder

For a long cylinder, we will use the cylindrical coordinate system. The one-dimensional heat conduction equation, considering internal heat generation and constant thermal conductivity, is given by: \(\frac{1}{r}\frac{\partial}{\partial r}(r \frac{\partial T}{\partial r}) + \frac{q_g}{k} = \rho C_p \frac{\partial T}{\partial t}\) where: T: Temperature (of the cylinder) r: Radial distance from the center of the cylinder t: Time k: Thermal conductivity of the material (constant) \(q_g\): Heat generation per unit volume \(\rho\): Density of the material \(C_p\): Specific heat capacity of the material
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2. Explanation of Variables

Each variable in the heat conduction equation represents the following: - T (Temperature): It describes the temperature distribution within the cylinder as a function of radial distance and time. - r (Radial distance): It represents the distance from the center of the cylinder. We are only considering the one-dimensional heat transfer in the radial direction. - t (Time): It represents the time variable and helps us to understand how the temperature distribution is changing with time. - k (Thermal conductivity): It is a material property that determines how efficiently heat is conducted through the material. For a constant thermal conductivity, this value does not change with temperature. - \(q_g\) (Heat generation per unit volume): It represents the rate at which heat is generated within the material per unit volume. For a constant heat generation, this value does not change with temperature, distance, or time. - ρ (Density): It is a material property that represents the mass per unit volume of the material. - \(C_p\) (Specific heat capacity): It is a material property that measures the amount of heat required to raise the temperature of a unit mass of the material by one degree Celsius/Kelvin.

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Most popular questions from this chapter

The temperatures at the inner and outer surfaces of a 15 -cm-thick plane wall are measured to be \(40^{\circ} \mathrm{C}\) and \(28^{\circ} \mathrm{C}\), respectively. The expression for steady, one-dimensional variation of temperature in the wall is (a) \(T(x)=28 x+40\) (b) \(T(x)=-40 x+28\) (c) \(T(x)=40 x+28\) (d) \(T(x)=-80 x+40\) (e) \(T(x)=40 x-80\)

Water flows through a pipe at an average temperature of \(T_{\infty}=90^{\circ} \mathrm{C}\). The inner and outer radii of the pipe are \(r_{1}=\) \(6 \mathrm{~cm}\) and \(r_{2}=6.5 \mathrm{~cm}\), respectively. The outer surface of the pipe is wrapped with a thin electric heater that consumes \(400 \mathrm{~W}\) per \(\mathrm{m}\) length of the pipe. The exposed surface of the heater is heavily insulated so that the entire heat generated in the heater is transferred to the pipe. Heat is transferred from the inner surface of the pipe to the water by convection with a heat transfer coefficient of \(h=85 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Assuming constant thermal conductivity and one-dimensional heat transfer, express the mathematical formulation (the differential equation and the boundary conditions) of the heat conduction in the pipe during steady operation. Do not solve.

In a manufacturing plant, a quench hardening process is used to treat steel ball bearings \((c=500 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}, k=\) \(60 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, \rho=7900 \mathrm{~kg} / \mathrm{m}^{3}\) ) of \(25 \mathrm{~mm}\) in diameter. After being heated to a prescribed temperature, the steel ball bearings are quenched. Determine the rate of heat loss if the rate of temperature decrease in the ball bearing at a given instant during the quenching process is \(50 \mathrm{~K} / \mathrm{s}\).

A plane wall of thickness \(L\) is subjected to convection at both surfaces with ambient temperature \(T_{\infty 1}\) and heat transfer coefficient \(h_{1}\) at inner surface, and corresponding \(T_{\infty 2}\) and \(h_{2}\) values at the outer surface. Taking the positive direction of \(x\) to be from the inner surface to the outer surface, the correct expression for the convection boundary condition is (a) \(\left.k \frac{d T(0)}{d x}=h_{1}\left[T(0)-T_{\mathrm{o} 1}\right)\right]\) (b) \(\left.k \frac{d T(L)}{d x}=h_{2}\left[T(L)-T_{\infty 2}\right)\right]\) (c) \(\left.-k \frac{d T(0)}{d x}=h_{1}\left[T_{\infty 1}-T_{\infty 2}\right)\right]\) (d) \(\left.-k \frac{d T(L)}{d x}=h_{2}\left[T_{\infty 1}-T_{\infty 22}\right)\right]\) (e) None of them

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