How is the boundary condition on an insulated su face expressed mathematically?

Short Answer

Expert verified
Answer: The mathematical expression for the boundary condition on an insulated surface is \(\nabla T = 0\), implying that there is no temperature gradient and thus no heat transfer at the surface.

Step by step solution

01

Define heat flux and its relationship with temperature gradients and thermal conductivity

Heat flux, denoted by \(\vec{q}\), refers to the rate of heat flow per unit area. It measures the flow of thermal energy across a surface and can be mathematically described through Fourier's law, which states that the heat flux is proportional to the temperature gradient: \(\vec{q} = -k \nabla T\) Here, \(k\) is the thermal conductivity (material property) and \(\nabla T\) is the temperature gradient (rate of change of temperature in space). The negative sign indicates that the heat flow is from higher to lower temperatures.
02

Explain what it means for a surface to be insulated

An insulated surface is a boundary where no heat transfer occurs. This means that the heat flux across the boundary is zero or minimized, typically due to the presence of insulating materials. In practical applications, perfect insulation is rarely achieved but the concept is useful for simplifying certain heat transfer problems.
03

Determine the mathematical expression for an insulated surface boundary condition

Since we know that the heat flux across an insulated surface must be zero, we can set the heat flux expression from Fourier's law to zero: \(\vec{q} = 0\) To express this boundary condition in terms of temperature gradients, we can use Fourier's law and set \(\vec{q}\) to zero: \(0 = -k \nabla T\) Since \(k\) is a non-zero constant (for most materials), this equation indicates that the temperature gradient must be zero: \(\nabla T = 0\) This is the mathematical expression for the boundary condition on an insulated surface. It implies that there is no temperature variation (no temperature gradient) across the surface, and thus no heat transfer occurs at the boundary.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Heat Flux
The concept of heat flux is central to understanding how heat moves through materials. Heat flux, typically denoted as \(\vec{q}\), is essentially the rate at which heat energy transfers through a given area. This heat movement is a way for energy to balance out temperature differences within a material or between materials.

For example, consider a hot coffee cup on a table. The heat from the coffee will transfer through the cup and into the air, with the surrounding area absorbing this energy. The rate at which this energy moves through the cup's surface is the heat flux. In most cases, the goal is either to maximize heat flux to cool something down quickly or to minimize it to maintain temperature, as is the case with an insulated surface.
Fourier's Law
Fourier's law plays a pivotal role in quantifying heat transfer. This principle provides the relationship between heat flux and temperature changes within a material. Mathematically, Fourier's law is expressed as \(\vec{q} = -k \abla T\), where \(\vec{q}\) is the heat flux, \(-k\) is the negative of the material's thermal conductivity, and \(abla T\) denotes the temperature gradient, or how rapidly the temperature changes with distance.

Whenever there's a temperature difference, heat will flow from the warmer to the cooler region. The negative sign in Fourier's law reflects this natural flow of heat from higher to lower temperatures. By understanding Fourier's law, we gain a mathematical way to predict how heat will move in different materials and under various conditions.
Temperature Gradient
A temperature gradient, symbolized as \(abla T\), is a vital concept when dealing with heat transfer as it represents how temperature changes over a distance. Imagine standing near a bonfire; the heat intensity you feel decreases as you step away. That change in sensation is due to the temperature gradient in the air.

A steep temperature gradient means a significant temperature change over a short distance, while a shallow gradient indicates a more gradual change. In an insulated surface, the ideal is to have no temperature gradient across the boundary, signifying that the insulating material is effectively blocking heat flow.
Thermal Conductivity
Thermal conductivity, denoted as \(\ k \), is a measure of a material's ability to conduct heat. It's an intrinsic property of the material and varies widely among different substances. Metals, for example, have a high thermal conductivity, which means they're excellent at transferring heat. Conversely, materials like wood or foam have low thermal conductivity, making them good insulators.

Different applications require materials with specific thermal conductivities. Insulation in buildings is designed to have low thermal conductivity to reduce heat loss or gain. On the other hand, parts of an engine may be built from materials with high thermal conductivity to dissipate heat efficiently. Understanding the thermal conductivity of different materials allows engineers and designers to manage heat in various environments effectively.

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Most popular questions from this chapter

When a long section of a compressed air line passes through the outdoors, it is observed that the moisture in the compressed air freezes in cold weather, disrupting and even completely blocking the air flow in the pipe. To avoid this problem, the outer surface of the pipe is wrapped with electric strip heaters and then insulated. Consider a compressed air pipe of length \(L=6 \mathrm{~m}\), inner radius \(r_{1}=3.7 \mathrm{~cm}\), outer radius \(r_{2}=4.0 \mathrm{~cm}\), and thermal conductivity \(k=14 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\) equipped with a 300 -W strip heater. Air is flowing through the pipe at an average temperature of \(-10^{\circ} \mathrm{C}\), and the average convection heat transfer coefficient on the inner surface is \(h=30 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Assuming 15 percent of the heat generated in the strip heater is lost through the insulation, \((a)\) express the differential equation and the boundary conditions for steady one-dimensional heat conduction through the pipe, \((b)\) obtain a relation for the variation of temperature in the pipe material by solving the differential equation, and \((c)\) evaluate the inner and outer surface temperatures of the pipe.

The outer surface of an engine is situated in a place where oil leakage can occur. Some oils have autoignition temperatures of approximately above \(250^{\circ} \mathrm{C}\). When oil comes in contact with a hot engine surface that has a higher temperature than its autoignition temperature, the oil can ignite spontaneously. Treating the engine housing as a plane wall, the inner surface \((x=0)\) is subjected to \(6 \mathrm{~kW} / \mathrm{m}^{2}\) of heat. The engine housing \((k=13.5 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\) has a thickness of \(1 \mathrm{~cm}\), and the outer surface \((x=L)\) is exposed to an environment where the ambient air is \(35^{\circ} \mathrm{C}\) with a convection heat transfer coefficient of \(20 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). To prevent fire hazard in the event the leaked oil comes in contact with the hot engine surface, the temperature of the engine surface should be kept below \(200^{\circ} \mathrm{C}\). Determine the variation of temperature in the engine housing and the temperatures of the inner and outer surfaces. Is the outer surface temperature of the engine below the safe temperature?

What is heat generation? Give some examples.

A circular metal pipe has a wall thickness of \(10 \mathrm{~mm}\) and an inner diameter of \(10 \mathrm{~cm}\). The pipe's outer surface is subjected to a uniform heat flux of \(5 \mathrm{~kW} / \mathrm{m}^{2}\) and has a temperature of \(500^{\circ} \mathrm{C}\). The metal pipe has a variable thermal conductivity given as \(k(T)=k_{0}(1+\beta T)\), where \(k_{0}=7.5 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), \(\beta=0.0012 \mathrm{~K}^{-1}\), and \(T\) is in \(\mathrm{K}\). Determine the inner surface temperature of the pipe.

A \(1200-W\) iron is left on the iron board with its base exposed to ambient air at \(26^{\circ} \mathrm{C}\). The base plate of the iron has a thickness of \(L=0.5 \mathrm{~cm}\), base area of \(A=150 \mathrm{~cm}^{2}\), and thermal conductivity of \(k=18 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\). The inner surface of the base plate is subjected to uniform heat flux generated by the resistance heaters inside. The outer surface of the base plate whose emissivity is \(\varepsilon=0.7\), loses heat by convection to ambient air with an average heat transfer coefficient of \(h=\) \(30 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) as well as by radiation to the surrounding surfaces at an average temperature of \(T_{\text {surr }}=295 \mathrm{~K}\). Disregarding any heat loss through the upper part of the iron, \((a)\) express the differential equation and the boundary conditions for steady one-dimensional heat conduction through the plate, \((b)\) obtain a relation for the temperature of the outer surface of the plate by solving the differential equation, and (c) evaluate the outer surface temperature.

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