Computer memory chips are mounted on a finned metallic mount to protect them from overheating. A \(152 \mathrm{MB}\) memory chip dissipates \(5 \mathrm{~W}\) of heat to air at \(25^{\circ} \mathrm{C}\). If the temperature of this chip is to not exceed \(50^{\circ} \mathrm{C}\), the overall heat transfer coefficient- area product of the finned metal mount must be at least (a) \(0.2 \mathrm{~W} /{ }^{\circ} \mathrm{C}\) (b) \(0.3 \mathrm{~W} /{ }^{\circ} \mathrm{C}\) (c) \(0.4 \mathrm{~W} /{ }^{\circ} \mathrm{C}\) (d) \(0.5 \mathrm{~W} /{ }^{\circ} \mathrm{C}\) (e) \(0.6 \mathrm{~W} /{ }^{\circ} \mathrm{C}\)

Short Answer

Expert verified
Answer: The minimum overall heat transfer coefficient-area product (UA) required is 0.2 W/°C.

Step by step solution

01

Identify the data

We are given the following information: - Heat transfer rate, \(Q = 5 \mathrm{~W}\) - Temperature of air, \(T_{air} = 25^{\circ} \mathrm{C}\) - Maximum chip temperature, \(T_{max} = 50^{\circ} \mathrm{C}\) From this data, we can find the overall heat transfer coefficient-area product (UA).
02

Calculate the temperature difference

Determine the temperature difference between the chip and the air by subtracting the air temperature from the maximum chip temperature: \(\Delta T = T_{max} - T_{air} = 50^{\circ} \mathrm{C} - 25^{\circ} \mathrm{C} = 25^{\circ} \mathrm{C}\)
03

Apply the heat transfer formula

Use the heat transfer formula to calculate the overall heat transfer coefficient-area product (UA): \(Q = UA \Delta T\) Rearrange to solve for UA: \(UA = \frac{Q}{\Delta T}\)
04

Calculate the required UA

Insert the given values for \(Q\) and \(\Delta T\) into the formula: \(UA = \frac{5 \mathrm{~W}}{25^{\circ} \mathrm{C}} = 0.2 \mathrm{~W} /{ }^{\circ} \mathrm{C}\)
05

Find the answer among the options

From the calculation, we find that the required overall heat transfer coefficient-area product is \(0.2 \mathrm{~W} /{ }^{\circ} \mathrm{C}\). This corresponds to option (a) in the choices given.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Heat Transfer Rate
In the realm of physics, the heat transfer rate is a critical concept defining how quickly heat energy is transferred from one location to another. Specifically, in our given problem, the heat transfer rate (\(Q\)) represents the amount of heat energy a computer memory chip releases into its surroundings per unit of time. The unit used to measure this rate is watts (W), where one watt is equivalent to one joule of energy transferred per second. With a given dissipation of \(5 \text{W}\), the memory chip in the exercise releases energy actively to prevent overheating, a necessity for the stable operation of electronics. This quantitative assessment is foundational in thermal management systems, as it provides the basis for designing effective cooling strategies, such as the finned metallic mount mentioned in the exercise.
Temperature Difference
The temperature difference, often denoted as \(\Delta T\), is a simple but fundamental factor influencing the rate of heat transfer. Within our context, ​\(\Delta T\) is the gradient driving the flow of heat from the hot memory chip to the cooler surrounding air. The larger the temperature difference, the greater the potential for heat to be transferred away from the chip. By calculating the difference between the maximum chip temperature (\(T_{max}\)) and the air temperature (\(T_{air}\)), we established a temperature difference of \(25^\circ C\). This value serves as a crucial component in calculating the overall heat transfer coefficient-area product (UA), as shown in the step-by-step solution, and ensures the chip remains within safe operational temperatures.
Finned Metallic Mount
The finned metallic mount mentioned in the exercise is an engineered solution designed to enhance the dissipation of heat through increased surface area. Fins are added to the mount to create more paths for heat to be transferred to the air, improving the convection process. These fins are typically crafted from metals with high thermal conductivity like aluminum or copper to maximize their effectiveness. The design and structure of the fins are critical; they should be optimized for creating the most surface area without impeding airflow or becoming counterproductive due to added thermal mass. This design principle allows for more efficient heat transfer from electronic components, like memory chips, thereby ensuring performance and longevity.
Thermal Management of Electronics
Effective thermal management of electronics is pivotal in maintaining the reliability and efficiency of electronic devices. The heat generated by electronic components, if not managed properly, can lead to overheating, which may cause a reduction in performance, damage, or even failure. Therefore, understanding and controlling the thermal environment is essential. Various methods are used to dissipate heat, including passive techniques like heat sinks and fins, and active techniques involving fans and liquid cooling systems. The use of a finned metallic mount is a prime example of a passive approach, leveraging the material's thermal properties and design to maintain optimal operating temperatures for electronic components such as memory chips.

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Most popular questions from this chapter

Consider a house with a flat roof whose outer dimensions are \(12 \mathrm{~m} \times 12 \mathrm{~m}\). The outer walls of the house are \(6 \mathrm{~m}\) high. The walls and the roof of the house are made of \(20-\mathrm{cm}-\) thick concrete \((k=0.75 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\). The temperatures of the inner and outer surfaces of the house are \(15^{\circ} \mathrm{C}\) and \(3^{\circ} \mathrm{C}\), respectively. Accounting for the effects of the edges of adjoining surfaces, determine the rate of heat loss from the house through its walls and the roof. What is the error involved in ignoring the effects of the edges and corners and treating the roof as a \(12 \mathrm{~m} \times 12 \mathrm{~m}\) surface and the walls as \(6 \mathrm{~m} \times 12 \mathrm{~m}\) surfaces for simplicity?

The plumbing system of a house involves a \(0.5-\mathrm{m}\) section of a plastic pipe \((k=0.16 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\) of inner diameter \(2 \mathrm{~cm}\) and outer diameter \(2.4 \mathrm{~cm}\) exposed to the ambient air. During a cold and windy night, the ambient air temperature remains at about \(-5^{\circ} \mathrm{C}\) for a period of \(14 \mathrm{~h}\). The combined convection and radiation heat transfer coefficient on the outer surface of the pipe is estimated to be \(40 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), and the heat of fusion of water is \(333.7 \mathrm{~kJ} / \mathrm{kg}\). Assuming the pipe to contain stationary water initially at \(0^{\circ} \mathrm{C}\), determine if the water in that section of the pipe will completely freeze that night.

A 0.6-m-diameter, 1.9-m-long cylindrical tank containing liquefied natural gas (LNG) at \(-160^{\circ} \mathrm{C}\) is placed at the center of a 1.9-m-long \(1.4-\mathrm{m} \times 1.4-\mathrm{m}\) square solid bar made of an insulating material with \(k=0.0002 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\). If the outer surface temperature of the bar is \(12^{\circ} \mathrm{C}\), determine the rate of heat transfer to the tank. Also, determine the LNG temperature after one month. Take the density and the specific heat of LNG to be \(425 \mathrm{~kg} / \mathrm{m}^{3}\) and \(3.475 \mathrm{~kJ} / \mathrm{kg} \cdot{ }^{\circ} \mathrm{C}\), respectively.

Consider a stainless steel spoon \(\left(k=8.7 \mathrm{Btu} / \mathrm{h} \cdot \mathrm{ft} \cdot{ }^{\circ} \mathrm{F}\right)\) partially immersed in boiling water at \(200^{\circ} \mathrm{F}\) in a kitchen at \(75^{\circ} \mathrm{F}\). The handle of the spoon has a cross section of \(0.08\) in \(\times\) \(0.5\) in, and extends 7 in in the air from the free surface of the water. If the heat transfer coefficient at the exposed surfaces of the spoon handle is \(3 \mathrm{Btu} / \mathrm{h} \cdot \mathrm{ft}^{2} \cdot{ }^{\circ} \mathrm{F}\), determine the temperature difference across the exposed surface of the spoon handle. State your assumptions. Answer: \(124.6^{\circ} \mathrm{F}\)

Consider a 25-m-long thick-walled concrete duct \((k=\) \(0.75 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\) of square cross section. The outer dimensions of the duct are \(20 \mathrm{~cm} \times 20 \mathrm{~cm}\), and the thickness of the duct wall is \(2 \mathrm{~cm}\). If the inner and outer surfaces of the duct are at \(100^{\circ} \mathrm{C}\) and \(30^{\circ} \mathrm{C}\), respectively, determine the rate of heat transfer through the walls of the duct. Answer: \(47.1 \mathrm{~kW}\)

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