Lumped system analysis of transient heat conduction situations is valid when the Biot number is (a) very small (b) approximately one (c) very large (d) any real number (e) cannot say unless the Fourier number is also known.

Short Answer

Expert verified
Question: For lumped system analysis to be valid, the Biot number should be: Answer: (a) very small

Step by step solution

01

Understand the Biot Number

The Biot number (Bi) is a dimensionless quantity that relates the rate of heat conduction within an object to the rate of heat convection at the surface of the object. It is defined as the ratio of the thermal resistance inside the object to the thermal resistance at the surface of the object. Mathematically, the Biot number is given by: Bi = \frac{h L_{c}}{k} Where, h = convective heat transfer coefficient (W/m²K) L_c = characteristic length of the object (m) k = thermal conductivity of the object (W/mK)
02

Analyzing the Biot Number values

Lumped system analysis assumes that the temperature within the object is uniform, which means the effects of heat conduction within the object can be neglected. This is only possible when the effects of convection at the surface of the object dominate heat conduction within the object. When Bi << 1 (the Biot number is very small), heat conduction within the object is much faster than surface heat convection. In this case, any temperature differences within the object are rapidly equalized, supporting the assumption of a uniform temperature within the object. Hence, lumped system analysis is valid when the Biot number is very small. Now let's see the given options and find the correct one based on our understanding: (a) very small: This is the correct answer, as explained above. (b) approximately one: Lumped system analysis is not valid when the Biot number is approximately one, as this implies comparable rates of heat conduction within the object and surface heat convection. (c) very large: When the Biot number is very large, heat conduction within the object becomes dominant, contradicting the assumption of a uniform temperature in lumped system analysis. (d) any real number: Lumped system analysis is not valid for any real number, as explained in options (b) and (c). (e) cannot say unless the Fourier number is also known: The Fourier number is related to the rate of heat conduction, but the validity of lumped system analysis primarily depends on the Biot number. So, the correct answer is (a) very small.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Conduct the following experiment at home to determine the combined convection and radiation heat transfer coefficient at the surface of an apple exposed to the room air. You will need two thermometers and a clock. First, weigh the apple and measure its diameter. You can measure its volume by placing it in a large measuring cup halfway filled with water, and measuring the change in volume when it is completely immersed in the water. Refrigerate the apple overnight so that it is at a uniform temperature in the morning and measure the air temperature in the kitchen. Then take the apple out and stick one of the thermometers to its middle and the other just under the skin. Record both temperatures every \(5 \mathrm{~min}\) for an hour. Using these two temperatures, calculate the heat transfer coefficient for each interval and take their average. The result is the combined convection and radiation heat transfer coefficient for this heat transfer process. Using your experimental data, also calculate the thermal conductivity and thermal diffusivity of the apple and compare them to the values given above.

In a production facility, 3-cm-thick large brass plates \(\left(k=110 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, \rho=8530 \mathrm{~kg} / \mathrm{m}^{3}, c_{p}=380 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right.\), and \(\left.\alpha=33.9 \times 10^{-6} \mathrm{~m}^{2} / \mathrm{s}\right)\) that are initially at a uniform temperature of \(25^{\circ} \mathrm{C}\) are heated by passing them through oven maintained at \(700^{\circ} \mathrm{C}\). The plates remain in the oven for a period of \(10 \mathrm{~min}\). Taking the convection heat transfer coefficient to be \(h=80 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), determine the surface temperature of the plates when they come out of the oven. Solve this problem using analytical one-term approximation method (not the Heisler charts). Can this problem be solved using lumped system analysis? Justify your answer.

An experiment is to be conducted to determine heat transfer coefficient on the surfaces of tomatoes that are placed in cold water at \(7^{\circ} \mathrm{C}\). The tomatoes \((k=0.59 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, \alpha=\) \(\left.0.141 \times 10^{-6} \mathrm{~m}^{2} / \mathrm{s}, \rho=999 \mathrm{~kg} / \mathrm{m}^{3}, c_{p}=3.99 \mathrm{~kJ} / \mathrm{kg} \cdot \mathrm{K}\right)\) with an initial uniform temperature of \(30^{\circ} \mathrm{C}\) are spherical in shape with a diameter of \(8 \mathrm{~cm}\). After a period of 2 hours, the temperatures at the center and the surface of the tomatoes are measured to be \(10.0^{\circ} \mathrm{C}\) and \(7.1^{\circ} \mathrm{C}\), respectively. Using analytical one-term approximation method (not the Heisler charts), determine the heat transfer coefficient and the amount of heat transfer during this period if there are eight such tomatoes in water.

A thick wood slab \((k=0.17 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\) and \(\alpha=1.28 \times\) \(10^{-7} \mathrm{~m}^{2} / \mathrm{s}\) ) that is initially at a uniform temperature of \(25^{\circ} \mathrm{C}\) is exposed to hot gases at \(550^{\circ} \mathrm{C}\) for a period of \(5 \mathrm{~min}\). The heat transfer coefficient between the gases and the wood slab is \(35 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). If the ignition temperature of the wood is \(450^{\circ} \mathrm{C}\), determine if the wood will ignite.

A long iron \(\operatorname{rod}\left(\rho=7870 \mathrm{~kg} / \mathrm{m}^{3}, c_{p}=447 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right.\), \(k=80.2 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), and \(\left.\alpha=23.1 \times 10^{-6} \mathrm{~m}^{2} / \mathrm{s}\right)\) with diameter of \(25 \mathrm{~mm}\) is initially heated to a uniform temperature of \(700^{\circ} \mathrm{C}\). The iron rod is then quenched in a large water bath that is maintained at constant temperature of \(50^{\circ} \mathrm{C}\) and convection heat transfer coefficient of \(128 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Determine the time required for the iron rod surface temperature to cool to \(200^{\circ} \mathrm{C}\). Solve this problem using analytical one- term approximation method (not the Heisler charts).

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free