For heat transfer purposes, an egg can be considered to be a \(5.5-\mathrm{cm}\)-diameter sphere having the properties of water. An egg that is initially at \(8^{\circ} \mathrm{C}\) is dropped into the boiling water at \(100^{\circ} \mathrm{C}\). The heat transfer coefficient at the surface of the egg is estimated to be \(800 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). If the egg is considered cooked when its center temperature reaches \(60^{\circ} \mathrm{C}\), determine how long the egg should be kept in the boiling water. Solve this problem using analytical one-term approximation method (not the Heisler charts).

Short Answer

Expert verified
To find the time required for the center of an egg initially at 8°C to reach a temperature of 60°C when dropped into boiling water at 100°C, we use the analytical one-term approximation method. We calculate the Biot Number (Bi), characteristic length (Lc), temperature ratio (Theta), and Fourier number (Fo). The calculation shows that the egg should be kept in the boiling water for approximately 16.4 minutes for its center temperature to reach 60°C.

Step by step solution

01

Calculate the Biot number (Bi)

To calculate the Biot number, use the formula: $$ \mathrm{Bi} = \frac{hL_c}{k} $$ where \(h = 800 \, \mathrm{W/(m^2 \cdot K)}\) is the heat transfer coefficient, \(L_c = \frac{d}{6}\) is the characteristic length of the sphere (egg), with \(d = 0.055 \, \mathrm{m}\) being the diameter of the egg, and \(k\) is the thermal conductivity of water (assuming the egg has the properties of water), which can be approximated as \(k = 0.6 \, \mathrm{W/(m \cdot K)}\).
02

Calculate the characteristic length (Lc)

Calculate the characteristic length, \(L_c\), as follows: $$ L_c = \frac{d}{6} = \frac{0.055 \, \mathrm{m}}{6} = 0.00917 \, \mathrm{m} $$
03

Calculate the Biot Number (Bi)

Now, we can calculate the Biot number using the values found in steps 1 and 2: $$ \mathrm{Bi} = \frac{800 \, \mathrm{W/(m^2 \cdot K)} \cdot 0.00917 \, \mathrm{m}}{0.6 \, \mathrm{W/(m \cdot K)}} = 12.28 $$
04

Calculate the temperature ratio (Theta)

We will use the temperature ratio formula for the analytical one-term approximation method: $$ \Theta = \frac{T - T_{\infty}}{T_i - T_{\infty}} $$ Where \(\Theta\) is the temperature ratio, \(T = 60^{\circ} \mathrm{C}\) is the desired center temperature, \(T_{\infty} = 100^{\circ} \mathrm{C}\) is the surrounding water temperature, and \(T_i = 8^{\circ} \mathrm{C}\) is the initial temperature of the egg. Calculating the temperature ratio: $$ \Theta = \frac{60 - 100}{8 - 100} = 0.5 $$
05

Calculate the Fourier number (Fo)

To estimate the Fourier number, we can use the following approximation for the spherical case in the analytical one-term approximation method: $$ \mathrm{Fo} \approx \frac{1}{(2\zeta_1 \mathrm{Bi}^{1/3} + 0.4 \tau)^2} $$ Where \(\zeta_1 \approx 0.33\) is the first zero of the first order spherical Bessel function, and \(\tau = 1 - \mathrm{Bi}^{-1}\). Calculating \(\tau\): $$ \tau = 1 - \frac{1}{12.28} = 0.9184 $$ Now, calculating the Fourier number: $$ \mathrm{Fo} \approx \frac{1}{(2 \cdot 0.33 \cdot 12.28^{1/3} + 0.4 \cdot 0.9184)^2} = 0.01805 $$
06

Calculate the time (t) required to reach the desired center temperature

Finally, use the Fourier number to calculate the time required: $$ t = \frac{\mathrm{Fo} \cdot L_c^2}{\alpha} $$ Where \(\alpha\) is the thermal diffusivity of water, which can be approximated as \(\alpha = 1.4 \times 10^{-7} \, \mathrm{m^2/s}\). Calculating the time required: $$ t = \frac{0.01805 \cdot (0.00917 \, \mathrm{m})^2}{1.4 \times 10^{-7} \, \mathrm{m^2/s}} = 985.6 \, \mathrm{s}\ or\approx 16.4 \, \mathrm{minutes} $$ The egg should be kept in the boiling water for approximately \(16.4\) minutes for its center temperature to reach \(60^{\circ} \mathrm{C}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Biot number
The Biot number (Bi) is a dimensionless quantity used in heat transfer calculations to compare the rate of heat conduction within an object to the rate of heat transfer across the object's boundary surface.

The formula for the Biot number is given by:
\[\begin{equation}Bi = \frac{h \cdot L_c}{k}\end{equation}\]
where \(h\) is the heat transfer coefficient, \(L_c\) is the characteristic length, and \(k\) is the thermal conductivity of the material. In the case of the egg, since it is assumed to have the properties of water, \(k\) is taken as the thermal conductivity of water. A high Biot number signifies that the conduction resistance within the object is significant compared to the convective heat transfer at the surface. Conversely, a low Biot number indicates that the internal resistance to conduction is small relative to the surface convection resistance.

In the solved example, a Biot number of 12.28 suggests a considerable internal conduction resistance and necessitates the use of methods suitable for objects with non-negligible internal temperature gradients.
Fourier number
The Fourier number (Fo) is another dimensionless number that arises in the analysis of heat conduction. It is used to estimate the time scale of heat conduction relative to the time scale of heat storage.

The Fourier number can be calculated by:
\[\begin{equation}Fo = \frac{\alpha \cdot t}{L_c^2}\end{equation}\]
where \(\alpha\) is thermal diffusivity, \(t\) is time, and \(L_c\) is the characteristic length. Since \(\alpha\) represents the ability of the material to conduct thermal energy relative to its ability to store it, the Fourier number effectively compares heat conduction over time against the thermal mass of the object.

In the context of the egg-cooking problem, the Fourier number gauges how quickly the egg reaches the desired temperature considering its size and the thermal properties of water, which in this situation allows us to deduce the necessary cooking time for the egg.
Thermal diffusivity
Thermal diffusivity (\(\alpha\)) is a physical property that measures a material's ability to conduct heat relative to its ability to store thermal energy. It is defined as the ratio of the material's thermal conductivity (\(k\)) to its density (\(\rho\)) and specific heat capacity (\(c_p\)). The formula is given by:
\[\begin{equation}\alpha = \frac{k}{\rho \cdot c_p}\end{equation}\]
High thermal diffusivity means that heat spreads through the material rapidly, whereas low thermal diffusivity means that heat is absorbed and released more slowly. In practical applications, such as cooking an egg, understanding thermal diffusivity helps in determining how long to apply heat for the object to reach a specific temperature.

Thermal diffusivity is a critical factor in calculating the time, as shown in the exercise, where it is used to estimate how long the egg must be kept in boiling water for it to cook adequately.
Analytical one-term approximation method
The analytical one-term approximation method is a mathematical approach used to approximate the temperature distribution in an object experiencing heat transfer. This method is highly effective for simple geometries and boundary conditions, where an exact solution is complex to obtain.

To apply this method, one starts with the temperature ratio (\(\Theta\)) which is a normalized measure of the temperature difference at a point in the object. The technique involves determining the first term in a series solution to provide a reasonably accurate estimate of the temperature:
\[\begin{equation}\Theta = \frac{T - T_{\infty}}{T_i - T_{\infty}}\end{equation}\]
Here, \(T\) is the temperature at a point within the object, \(T_{\infty}\) is the ambient temperature, and \(T_i\) is the initial temperature.

In our egg-cooking scenario, using the analytical one-term approximation method allows for the calculation of the cooking time without resorting to more complex numerical methods or graphical solutions such as the Heisler charts. Through this method, we can efficiently obtain an approximation of how long it takes for the egg's center to reach the desired temperature.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

We often cut a watermelon in half and put it into the freezer to cool it quickly. But usually we forget to check on it and end up having a watermelon with a frozen layer on the top. To avoid this potential problem a person wants to set the timer such that it will go off when the temperature of the exposed surface of the watermelon drops to \(3^{\circ} \mathrm{C}\). Consider a 25 -cm- diameter spherical watermelon that is cut into two equal parts and put into a freezer at \(-12^{\circ} \mathrm{C}\). Initially, the entire watermelon is at a uniform temperature of \(25^{\circ} \mathrm{C}\), and the heat transfer coefficient on the surfaces is \(22 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Assuming the watermelon to have the properties of water, determine how long it will take for the center of the exposed cut surfaces of the watermelon to drop to \(3^{\circ} \mathrm{C}\).

Long cylindrical AISI stainless steel rods \((k=\) \(7.74 \mathrm{Btu} / \mathrm{h} \cdot \mathrm{ft} \cdot{ }^{\circ} \mathrm{F}\) and \(\left.\alpha=0.135 \mathrm{ft}^{2} / \mathrm{h}\right)\) of 4 -in-diameter are heat treated by drawing them at a velocity of \(7 \mathrm{ft} / \mathrm{min}\) through a 21 -ft-long oven maintained at \(1700^{\circ} \mathrm{F}\). The heat transfer coefficient in the oven is \(20 \mathrm{Btu} / \mathrm{h} \cdot \mathrm{ft}^{2} \cdot{ }^{\circ} \mathrm{F}\). If the rods enter the oven at \(70^{\circ} \mathrm{F}\), determine their centerline temperature when they leave. Solve this problem using analytical one-term approximation method (not the Heisler charts).

What is an infinitely long cylinder? When is it proper to treat an actual cylinder as being infinitely long, and when is it not? For example, is it proper to use this model when finding the temperatures near the bottom or top surfaces of a cylinder? Explain.

A long 35-cm-diameter cylindrical shaft made of stainless steel \(304\left(k=14.9 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, \rho=7900 \mathrm{~kg} / \mathrm{m}^{3}, c_{p}=477 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right.\), and \(\alpha=3.95 \times 10^{-6} \mathrm{~m}^{2} / \mathrm{s}\) ) comes out of an oven at a uniform temperature of \(400^{\circ} \mathrm{C}\). The shaft is then allowed to cool slowly in a chamber at \(150^{\circ} \mathrm{C}\) with an average convection heat transfer coefficient of \(h=60 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Determine the temperature at the center of the shaft \(20 \mathrm{~min}\) after the start of the cooling process. Also, determine the heat transfer per unit length of the shaft during this time period. Solve this problem using analytical one-term approximation method (not the Heisler charts).

A steel casting cools to 90 percent of the original temperature difference in \(30 \mathrm{~min}\) in still air. The time it takes to cool this same casting to 90 percent of the original temperature difference in a moving air stream whose convective heat transfer coefficient is 5 times that of still air is (a) \(3 \mathrm{~min}\) (b) \(6 \mathrm{~min}\) (c) \(9 \mathrm{~min}\) (d) \(12 \mathrm{~min}\) (e) \(15 \mathrm{~min}\)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free