Chapter 5: Problem 123
Can the global (accumulated) discretization error be less than the local error during a step? Explain.
Chapter 5: Problem 123
Can the global (accumulated) discretization error be less than the local error during a step? Explain.
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Get started for freeConsider steady one-dimensional heat conduction in a pin fin of constant diameter \(D\) with constant thermal conductivity. The fin is losing heat by convection to the ambient air at \(T_{\infty}\) with a convection coefficient of \(h\), and by radiation to the surrounding surfaces at an average temperature of \(T_{\text {surr }}\). The nodal network of the fin consists of nodes 0 (at the base), 1 (in the middle), and 2 (at the fin tip) with a uniform nodal spacing of \(\Delta x\). Using the energy balance approach, obtain the finite difference formulation of this problem to determine \(T_{1}\) and \(T_{2}\) for the case of specified temperature at the fin base and negligible heat transfer at the fin tip. All temperatures are in \({ }^{\circ} \mathrm{C}\).
For a one dimensional steady state variable thermal conductivity heat conduction with uniform internal heat generation, develop a generalized finite difference formulation for the interior nodes, with left surface boundary node exposed to constant heat flux and right surface boundary node exposed to convective environment. The variable conductivity is modeled such that the thermal conductivity varies linearly with the temperature as \(k(T)=k_{o}(1+\beta T)\) where \(T\) is the average temperature between the two nodes.
The wall of a heat exchanger separates hot water at \(T_{A}=90^{\circ} \mathrm{C}\) from cold water at \(T_{B}=10^{\circ} \mathrm{C}\). To extend the heat transfer area, two-dimensional ridges are machined on the cold side of the wall, as shown in Fig. P5-76. This geometry causes non-uniform thermal stresses, which may become critical for crack initiation along the lines between two ridges. To predict thermal stresses, the temperature field inside the wall must be determined. Convection coefficients are high enough so that the surface temperature is equal to that of the water on each side of the wall. (a) Identify the smallest section of the wall that can be analyzed in order to find the temperature field in the whole wall. (b) For the domain found in part \((a)\), construct a twodimensional grid with \(\Delta x=\Delta y=5 \mathrm{~mm}\) and write the matrix equation \(A T=C\) (elements of matrices \(A\) and \(C\) must be numbers). Do not solve for \(T\). (c) A thermocouple mounted at point \(M\) reads \(46.9^{\circ} \mathrm{C}\). Determine the other unknown temperatures in the grid defined in part (b).
The explicit finite difference formulation of a general interior node for transient heat conduction in a plane wall is given by $$ T_{m-1}^{i}-2 T_{m}^{i}+T_{m+1}^{i}+\frac{\dot{e}_{m}^{i} \Delta x^{2}}{k}=\frac{T_{m}^{i+1}-T_{m}^{i}}{\tau} $$ Obtain the finite difference formulation for the steady case by simplifying the relation above.
What are the basic steps involved in solving a system of equations with Gauss- Seidel method?
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