Consider steady heat conduction in a plane wall with variable heat generation and constant thermal conductivity. The nodal network of the medium consists of nodes \(0,1,2,3\), and 4 with a uniform nodal spacing of \(\Delta x\). Using the energy balance approach, obtain the finite difference formulation of the boundary nodes for the case of uniform heat flux \(\dot{q}_{0}\) at the left boundary (node 0 ) and convection at the right boundary (node 4) with a convection coefficient of \(h\) and an ambient temperature of \(T_{\infty}\).

Short Answer

Expert verified
Answer: The finite difference formulations for the boundary nodes are as follows: 1. For node 0: \(T_0 = T_1 - \frac{\Delta x}{k} \cdot \dot{q}_0\) 2. For node 4: \(T_4 = \left(\frac{\Delta x}{k} \cdot h + \Delta x \cdot \frac{1}{k}\right) T_{3} - \Delta x \cdot \frac{1}{k} \cdot T_{\infty}\)

Step by step solution

01

Write energy balance equation for node 0

Write the energy balance equation for node 0: $$\dot{q}_0 - k \frac{T_1 - T_0}{\Delta x} = 0$$ Rearrange this equation to obtain the finite difference formulation for node 0: $$T_0 = T_1 - \frac{\Delta x}{k} \cdot \dot{q}_0$$
02

Write energy balance equation for node 4

Write the energy balance equation for node 4: $$k \frac{T_{3} - T_{4}}{\Delta x} - h \cdot (T_{4} - T_{\infty}) = 0$$ Rearrange this equation to obtain the finite difference formulation for node 4: $$T_4 = \left(\frac{\Delta x}{k} \cdot h + \Delta x \cdot \frac{1}{k}\right) T_{3} - \Delta x \cdot \frac{1}{k} \cdot T_{\infty}$$

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