Consider steady one-dimensional heat conduction in a composite plane wall consisting of two layers \(A\) and \(B\) in perfect contact at the interface. The wall involves no heat generation. The nodal network of the medium consists of nodes 0,1 (at the interface), and 2 with a uniform nodal spacing of \(\Delta x\). Using the energy balance approach, obtain the finite difference formulation of this problem for the case of insulation at the left boundary (node 0 ) and radiation at the right boundary (node 2) with an emissivity of \(\varepsilon\) and surrounding temperature of \(T_{\text {surr }}\)

Short Answer

Expert verified
Answer: The finite difference formulation for the temperatures in the composite wall is given by the equation: \(T_1 - T_0 = -q'_0\Delta x/2 - (T_2 - T_1)\Delta x - 4\varepsilon\sigma\Delta x\left(T_2^3 - T_\text{surr}^3\right)/\lambda_B\).

Step by step solution

01

Set up the energy balance equation

Based on the energy balance principle, there is no net energy accumulation at each node. Therefore, the energy coming in should be equal to the outgoing energy: \(\frac{dT}{dx}\bigg|_0 (^{-}) + q'_0\Delta x/2 = -\frac{dT}{dx}\bigg|_1 (^{+}) -\lambda_B\frac{dT}{dx}\bigg|_2 (^{-})\)
02

Set up the temperature derivatives in terms of nodal temperatures

Approximate the temperature derivatives at each node using finite difference approximation, considering the uniform nodal spacing of \(\Delta x\), as shown below, \(\frac{dT}{dx}\bigg|_0 (^{-}) = \frac{T_1 - T_0}{\Delta x}\), and \(\frac{dT}{dx}\bigg|_1 (^{+}) = \frac{T_2 - T_1}{\Delta x}\). For the derivative at node 2, apply the radiation boundary condition, \(\lambda_B\frac{dT}{dx}\bigg|_2 (^{-}) = \varepsilon\sigma\left(T^4_2 - T_\text{surr}^4\right)\), and differentiate it with respect to \(T_2\), resulting in, \(\frac{dT}{dx}\bigg|_2 (^{-}) = \frac{4\varepsilon\sigma}{\lambda_B}\left(T_2^3 - T_\text{surr}^3\right)\).
03

Substitute the derivatives into the energy balance equation

Now, substitute these derivatives into the energy balance equation from Step 1, \(\frac{T_1 - T_0}{\Delta x} + q'_0\Delta x/2 = -\frac{T_2 - T_1}{\Delta x} - \frac{4\varepsilon\sigma}{\lambda_B}\left(T_2^3 - T_\text{surr}^3\right)\)
04

Simplification and rearranging the equation

Simplify and rearrange the equation to get the finite difference formulation for the temperatures in the wall, \(T_1 - T_0 = -q'_0\Delta x/2 - (T_2 - T_1)\Delta x - 4\varepsilon\sigma\Delta x\left(T_2^3 - T_\text{surr}^3\right)/\lambda_B\) So, the finite difference formulation for the temperatures in the composite wall is given by the above equation. Use this equation to calculate the temperature distribution in the wall, considering the boundary conditions of insulation at node 0 and radiation at node 2 with an emissivity of \(\varepsilon\) and surrounding temperature of \(T_\text{surr}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Heat Conduction
Heat conduction is a fundamental concept in thermodynamics and heat transfer that describes the process by which thermal energy is transported from higher to lower temperature regions within a material. It occurs at the molecular level through the collision and interaction of particles within the conducting medium. Materials with higher thermal conductivity, such as metals, facilitate the transfer of heat more readily than materials with lower thermal conductivity, like wood or plastic.

In the context of a composite plane wall, which is a structure composed of two or more distinct layers with different properties, heat conduction occurs through each layer with a thermal gradient driving the flow of heat. The unique nature of this setup involves understanding how heat moves through layered materials each with its own ability to conduct heat, which can greatly impact overall thermal performance.
Composite Plane Wall
A composite plane wall is a structural feature common in the realm of building construction and thermal insulation, applied in various engineering problems including those involving heat transfer. The key to analyzing a composite plane wall is recognizing that it is comprised of different layers (in our example, layers A and B) of materials, each possibly having distinct thermal conductivities, densities, and specific heats.

The analysis becomes interesting—and complex—when considering the different ways heat can be conducted through these heterogeneous layers. In a composite wall, heat must cross every layer to get from the hot side to the cool side, interacting with each material's properties. The behavior at the interface of two materials is especially critical and the assumpion of perfect contact impacts the overall thermal resistance of the wall, like pieces of a puzzle fitting together to guide the overall heat flow pattern.
Energy Balance Equation
The energy balance equation is essential in the study of heat conduction as it reflects the principle of conservation of energy in a given system. For an object or region under steady-state conditions, the sum of the energy rates flowing into the system must equal the sum of the energy rates flowing out plus any accumulation. However, for steady-state problems, there is no energy accumulation over time. Thus, in and out energy rates must balance exactly.

In the case of the finite difference formulation for a composite wall, an energy balance approach is utilized, involving calculations around each node within the system. The equation considers heat transfer into and out of a control volume around a node, ensuring that the heat conducted into the node is equal to the heat conducted away, minus any heat losses or gains through boundary conditions like insulation or radiation. The finite difference method uses an energy balance to turn the heat conduction equation into algebraic equations that can be solved numerically for temperatures at discrete points, or nodes, within the system.

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Most popular questions from this chapter

Express the general stability criterion for the explicit method of solution of transient heat conduction problems.

Consider transient heat conduction in a plane wall with variable heat generation and constant thermal conductivity. The nodal network of the medium consists of nodes \(0,1,2,3,4\), and 5 with a uniform nodal spacing of \(\Delta x\). The wall is initially at a specified temperature. Using the energy balance approach, obtain the explicit finite difference formulation of the boundary nodes for the case of insulation at the left boundary (node 0 ) and radiation at the right boundary (node 5) with an emissivity of \(\varepsilon\) and surrounding temperature of \(T_{\text {surr }}\).

A plane wall with surface temperature of \(350^{\circ} \mathrm{C}\) is attached with straight rectangular fins \((k=235 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\). The fins are exposed to an ambient air condition of \(25^{\circ} \mathrm{C}\) and the convection heat transfer coefficient is \(154 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Each fin has a length of \(50 \mathrm{~mm}\), a base of \(5 \mathrm{~mm}\) thick, and a width of \(100 \mathrm{~mm}\). For a single fin, using a uniform nodal spacing of \(10 \mathrm{~mm}\), determine \((a)\) the finite difference equations, \((b)\) the nodal temperatures by solving the finite difference equations, and \((c)\) the heat transfer rate and compare the result with analytical solution.

Using EES (or other) software, solve these systems of algebraic equations. (a) \(4 x_{1}-x_{2}+2 x_{3}+x_{4}=-6\) $$ \begin{aligned} x_{1}+3 x_{2}-x_{3}+4 x_{4} &=-1 \\ -x_{1}+2 x_{2}+5 x_{4} &=5 \\ 2 x_{2}-4 x_{3}-3 x_{4} &=-5 \end{aligned} $$ (b) $$ \begin{aligned} 2 x_{1}+x_{2}^{4}-2 x_{3}+x_{4} &=1 \\ x_{1}^{2}+4 x_{2}+2 x_{3}^{2}-2 x_{4} &=-3 \\ -x_{1}+x_{2}^{4}+5 x_{3} &=10 \\ 3 x_{1}-x_{3}^{2}+8 x_{4} &=15 \end{aligned} $$

Consider a stainless steel spoon \((k=15.1 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), \(\varepsilon=0.6\) ) that is partially immersed in boiling water at \(95^{\circ} \mathrm{C}\) in a kitchen at \(25^{\circ} \mathrm{C}\). The handle of the spoon has a cross section of about \(0.2 \mathrm{~cm} \times 1 \mathrm{~cm}\) and extends \(18 \mathrm{~cm}\) in the air from the free surface of the water. The spoon loses heat by convection to the ambient air with an average heat transfer coefficient of \(h=13 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) as well as by radiation to the surrounding surfaces at an average temperature of \(T_{\text {surr }}=\) \(295 \mathrm{~K}\). Assuming steady one- dimensional heat transfer along the spoon and taking the nodal spacing to be \(3 \mathrm{~cm}\), (a) obtain the finite difference formulation for all nodes, (b) determine the temperature of the tip of the spoon by solving those equations, and \((c)\) determine the rate of heat transfer from the exposed surfaces of the spoon.

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