Consider steady one-dimensional heat conduction in a plane wall with variable heat generation and constant thermal conductivity. The nodal network of the medium consists of nodes \(0,1,2,3,4\), and 5 with a uniform nodal spacing of \(\Delta x\). The temperature at the right boundary (node 5) is specified. Using the energy balance approach, obtain the finite difference formulation of the boundary node 0 on the left boundary for the case of combined convection, radiation, and heat flux at the left boundary with an emissivity of \(\varepsilon\), convection coefficient of \(h\), ambient temperature of \(T_{\infty}\), surrounding temperature of \(T_{\text {surr }}\), and uniform heat flux of \(\dot{q}_{0}\). Also, obtain the finite difference formulation for the rate of heat transfer at the right boundary.

Short Answer

Expert verified
Answer: In the finite difference equation for node 0, the expressions for the coefficients are: $a_0=\frac{k}{\Delta x}+h+4\varepsilon\sigma T_{0}^3$ $a_1=-\frac{k}{\Delta x}$ $C=\dot{q}_{0}\Delta x+ hT_{\infty}+\varepsilon\sigma T_{\text {surr}}^4$

Step by step solution

01

Consider the energy balance equation

For the energy balance equation, consider a small control volume around node 0. Using Fourier's law of heat conduction and taking into account heat generation, convection, and radiation, the energy balance equation is given by: $$q_{\text{conduction}}+q_{\text{generation}}-q_{\text{convection}}-q_{\text{radiation}}=0$$
02

Express the energy balance equation in terms of finite differences

Now express the energy balance equation in the finite difference form and combine the terms. At node 0, the finite difference equation becomes: $$\frac{k(T_{1}-T_{0})}{\Delta x}+\dot{q}_{0}-h(T_{0}-T_{\infty})-\varepsilon\sigma(T_{0}^4-T_{\text {surr}}^4)=0$$
03

Reorganize the finite difference equation for node 0

Now, reorganize the nodal finite difference equation for node 0 as follows: $$a_0T_{0}+a_1T_{1}=C$$ Where $$a_0=\frac{k}{\Delta x}+h+4\varepsilon\sigma T_{0}^3$$ $$a_1=-\frac{k}{\Delta x}$$ $$C=\dot{q}_{0}\Delta x+ hT_{\infty}+\varepsilon\sigma T_{\text {surr}}^4$$
04

Obtain the rate of heat transfer at the right boundary (node 5)

To find the rate of heat transfer at the right boundary, we need to consider the conduction from node 4 to node 5. Since the boundary condition specifies the temperature at node 5, we can write the heat conduction equation as: $$q_{\text{conducton}}=k\frac{T_{5}-T_{4}}{\Delta x}=k\frac{T_{4}-T_{5}}{\Delta x}$$ In summary, the finite difference formulation for the heat transfer problem with combined convection, radiation, and heat flux at the left boundary (node 0) is: $$a_0T_{0}+a_1T_{1}=C$$ Where $$a_0=\frac{k}{\Delta x}+h+4\varepsilon\sigma T_{0}^3$$ $$a_1=-\frac{k}{\Delta x}$$ $$C=\dot{q}_{0}\Delta x+ hT_{\infty}+\varepsilon\sigma T_{\text {surr}}^4$$ And for the rate of heat transfer at the right boundary (node 5), $$q_{\text{conducton}}=k\frac{T_{4}-T_{5}}{\Delta x}$$

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Energy Balance Equation
The energy balance equation is pivotal when analyzing heat transfer in systems. It is based on the principle of conservation of energy, which states that the total energy in an isolated system remains constant. In the context of heat transfer, the energy balance equation considers the sum of all forms of heat transfer entering and leaving a specific control volume.

For a node in a thermal system, the energy balance can be mathematically represented by the equation:
\[\begin{equation}q_{\text{conduction}} + q_{\text{generation}} - q_{\text{convection}} - q_{\text{radiation}} = 0\end{equation}\]
This equation ensures that the rate of heat addition through conduction, any internal heat generation, and losses through convection and radiation should equate to zero in a steady-state scenario. Applying this concept in the finite difference formulation provides a systematic approach to discretizing the heat transfer process by considering the heat transfer at individual nodes within the medium.
Fourier's Law of Heat Conduction
Fourier's Law is the fundamental principle governing heat conduction, which is the transfer of heat within a body due to a temperature gradient. According to Fourier's law, the rate of heat transfer through a material is proportional to the negative gradient of temperature and the area through which the heat is transferred:
\[\begin{equation}q_{\text{conduction}} = -kA\frac{dT}{dx}\end{equation}\]
Here, 'k' is the material's thermal conductivity, 'A' is the cross-sectional area, and 'dT/dx' is the temperature gradient. The negative sign indicates that heat flows from high to low temperature. In a finite difference approach, the temperature gradient is approximated between discrete points or nodes, allowing us to assess the heat conduction between them.
Boundary Conditions Heat Transfer
Boundary conditions are essential in solving heat transfer problems because they describe how the system interacts with its surroundings. There are primarily three types of boundary conditions: Dirichlet, where temperature is specified; Neumann, where heat flux is specified; and Robin, which is a combination of convection and radiation at the boundary.

In the given exercise, the left boundary experiences combined convection, radiation, and a uniform heat flux, leading to a complex boundary condition described by a Robin type. This must be considered when setting up the energy balance for node 0 and makes the formulation specific to the heat transfer mechanisms present at that boundary.
One-Dimensional Heat Conduction
One-dimensional heat conduction simplifies the complexity of heat transfer problems by assuming that the temperature varies only in one direction and is uniform in the perpendicular directions. It's a valid assumption when the thermal conductivity in one direction dominates or the geometry of the system enforces such a condition.

In practice, this assumption enables us to concentrate on the heat transfer along a single path, as is the case with the finite difference formulation in the provided exercise. This approach reduces a potentially complex three-dimensional problem to a more manageable one-dimensional analysis, focussing purely on the temperature difference and thermal conductivity along the direction of interest.
Nodal Network Analysis
Nodal network analysis breaks down a continuous system into a discrete system of nodes interconnected by elements representing the heat transfer between nodes. In the context of heat conduction, this method is greatly facilitated by the use of finite difference equations.

Each node represents a point in the medium and is associated with a temperature. The nodes are connected by thermal resistances that model the conduction or convection between nodes. By performing an energy balance on each node, and considering the appropriate boundary conditions, a set of algebraic equations is formulated which, once solved, gives an approximation for the temperature distribution in the entire medium.

The finite difference formulations, as seen in the exercise, when applied to each node (including boundary nodes) and collectively solved, enable the calculation of temperature distribution and heat transfer rates across the one-dimensional system.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Two 3-m-long and 0.4-cm-thick cast iron \((k=\) \(52 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, \varepsilon=0.8)\) steam pipes of outer diameter \(10 \mathrm{~cm}\) are connected to each other through two \(1-\mathrm{cm}\)-thick flanges of outer diameter \(20 \mathrm{~cm}\). The steam flows inside the pipe at an average temperature of \(200^{\circ} \mathrm{C}\) with a heat transfer coefficient of \(180 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). The outer surface of the pipe is exposed to convection with ambient air at \(8^{\circ} \mathrm{C}\) with a heat transfer coefficient of \(25 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) as well as radiation with the surrounding surfaces at an average temperature of \(T_{\text {surr }}=290 \mathrm{~K}\). Assuming steady one-dimensional heat conduction along the flanges and taking the nodal spacing to be \(1 \mathrm{~cm}\) along the flange \((a)\) obtain the finite difference formulation for all nodes, \((b)\) determine the temperature at the tip of the flange by solving those equations, and \((c)\) determine the rate of heat transfer from the exposed surfaces of the flange.

Consider transient heat conduction in a plane wall with variable heat generation and constant thermal conductivity. The nodal network of the medium consists of nodes \(0,1,2,3\), and 4 with a uniform nodal spacing of \(\Delta x\). The wall is initially at a specified temperature. The temperature at the right boundary (node 4) is specified. Using the energy balance approach, obtain the explicit finite difference formulation of the boundary node 0 for the case of combined convection, radiation, and heat flux at the left boundary with an emissivity of \(\varepsilon\), convection coefficient of \(h\), ambient temperature of \(T_{\infty}\), surrounding temperature of \(T_{\text {surr }}\), and uniform heat flux of \(\dot{q}_{0}\) toward the wall. Also, obtain the finite difference formulation for the total amount of heat transfer at the right boundary for the first 20 time steps.

What are the limitations of the analytical solution methods?

The unsteady forward-difference heat conduction for a constant area, \(A\), pin fin with perimeter, \(p\), exposed to air whose temperature is \(T_{0}\) with a convection heat transfer coefficient of \(h\) is $$ \begin{aligned} T_{m}^{*+1}=& \frac{k}{\rho c_{p} \Delta x^{2}}\left[T_{m-1}^{*}+T_{m+1}^{*}+\frac{h p \Delta x^{2}}{A} T_{0}\right] \\\ &-\left[1-\frac{2 k}{\rho c_{p} \Delta x^{2}}-\frac{h p}{\rho c_{p} A}\right] T_{m}^{*} \end{aligned} $$ In order for this equation to produce a stable solution, the quantity \(\frac{2 k}{\rho c_{p} \Delta x^{2}}+\frac{h p}{\rho c_{p} A}\) must be (a) negative (b) zero (c) positive (d) greater than 1 (e) less than 1

Consider transient two-dimensional heat conduction in a rectangular region that is to be solved by the explicit method. If all boundaries of the region are either insulated or at specified temperatures, express the stability criterion for this problem in its simplest form.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free