Express the general stability criterion for the explicit method of solution of transient heat conduction problems.

Short Answer

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Answer: The general stability criterion for explicit methods in transient heat conduction problems is given by the inequality \(\frac{\alpha\Delta t}{\Delta x^2} \le \frac{1}{2}\), where \(\alpha\) is the thermal diffusivity, \(\Delta t\) is the time step, and \(\Delta x\) is the spatial step. This criterion helps in choosing suitable time and spatial steps for ensuring numerical stability in the explicit finite difference method.

Step by step solution

01

Explicit finite difference method for transient heat conduction problems

The explicit finite difference method is a numerical method used to solve partial differential equations, including those that describe transient heat conduction problems. The heat equation for a one-dimensional transient heat conduction problem can be written as: \(\frac{\partial T}{\partial t} = \alpha\frac{\partial^2 T}{\partial x^2}\) where \(T\) is the temperature, \(t\) is the time, \(\alpha\) is the thermal diffusivity, and \(x\) is the spatial coordinate. We discretize the temperature field \(T\) using a finite difference grid in both time and space: \(T_{i,j} = T(x_i, t_j)\) Now, we approximate the derivatives in the heat equation using finite differences: \(\frac{T_{i,j+1} - T_{i,j}}{\Delta t} = \alpha\frac{T_{i-1,j} - 2T_{i,j} + T_{i+1,j}}{\Delta x^2}\) Solving for \(T_{i,j+1}\), we get the explicit method: \(T_{i,j+1} = T_{i,j} + \frac{\alpha \Delta t}{\Delta x^2}(T_{i-1,j} - 2T_{i,j} + T_{i+1,j})\)
02

Stability criterion using von Neumann stability analysis

Von Neumann stability analysis is a technique used to determine numerical stability in finite difference methods. For an explicit method to be stable, the amplification factor needs to be less than or equal to 1. Let the temperature at time step \(j\) be expressed as a Fourier series: \(T_{i,j} = \sum_{k} \xi_j(k) e^{ikx_i}\) Substituting this expression of \(T_{i,j}\) into the explicit finite difference method, we can define the amplification factor \(G(k)\) as the ratio between \(\xi_{j+1}(k)\) and \(\xi_j(k)\): \(G(k) = \frac{\xi_{j+1}(k)}{\xi_j(k)}\) Solving for \(G(k)\), we get: \(G(k) = 1 + \frac{\alpha\Delta t}{\Delta x^2}(e^{-ik\Delta x} - 2 + e^{ik\Delta x})\) For numerical stability, we need \(|G(k)| \le 1\). Simplifying the expression for \(|G(k)|\): \(|G(k)| = |1 + \frac{\alpha\Delta t}{\Delta x^2}(e^{-ik\Delta x} - 2 + e^{ik\Delta x})|\) Using the identity \(|e^{ix}| = 1\) and applying the triangle inequality, we get: \(|G(k)| \le 1 + \frac{\alpha\Delta t}{\Delta x^2}(1 - 2 + 1) = 1 - 4\frac{\alpha\Delta t}{\Delta x^2}\) To satisfy the stability criterion (\(|G(k)| \le 1\)), we must have: \(1 - 4\frac{\alpha\Delta t}{\Delta x^2} \le 1\) Rearranging this inequality, we get the stability criterion for the explicit method of solution of transient heat conduction problems: \(\frac{\alpha\Delta t}{\Delta x^2} \le \frac{1}{2}\)

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Most popular questions from this chapter

Consider steady one-dimensional heat conduction in a pin fin of constant diameter \(D\) with constant thermal conductivity. The fin is losing heat by convection to the ambient air at \(T_{\infty}\) with a convection coefficient of \(h\), and by radiation to the surrounding surfaces at an average temperature of \(T_{\text {surr }}\). The nodal network of the fin consists of nodes 0 (at the base), 1 (in the middle), and 2 (at the fin tip) with a uniform nodal spacing of \(\Delta x\). Using the energy balance approach, obtain the finite difference formulation of this problem to determine \(T_{1}\) and \(T_{2}\) for the case of specified temperature at the fin base and negligible heat transfer at the fin tip. All temperatures are in \({ }^{\circ} \mathrm{C}\).

Consider a large uranium plate of thickness \(L=9 \mathrm{~cm}\), thermal conductivity \(k=28 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), and thermal diffusivity \(\alpha=12.5 \times 10^{-6} \mathrm{~m}^{2} / \mathrm{s}\) that is initially at a uniform temperature of \(100^{\circ} \mathrm{C}\). Heat is generated uniformly in the plate at a constant rate of \(\dot{e}=10^{6} \mathrm{~W} / \mathrm{m}^{3}\). At time \(t=0\), the left side of the plate is insulated while the other side is subjected to convection with an environment at \(T_{\infty}=20^{\circ} \mathrm{C}\) with a heat transfer coefficient of \(h=35 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Using the explicit finite difference approach with a uniform nodal spacing of \(\Delta x=1.5 \mathrm{~cm}\), determine \((a)\) the temperature distribution in the plate after \(5 \mathrm{~min}\) and \((b)\) how long it will take for steady conditions to be reached in the plate.

Quench hardening is a mechanical process in which the ferrous metals or alloys are first heated and then quickly cooled down to improve their physical properties and avoid phase transformation. Consider a \(40 \mathrm{~cm} \times 20 \mathrm{~cm}\) block of copper alloy \(\left(k=120 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, \alpha=3.91 \times 10^{-6} \mathrm{~m}^{2} / \mathrm{s}\right)\) being heated uniformly until it reaches a temperature of \(800^{\circ} \mathrm{C}\). It is then suddenly immersed into the water bath maintained at \(15^{\circ} \mathrm{C}\) with \(h=100 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) for quenching process. However, the upper surface of the metal is not submerged in the water and is exposed to air at \(15^{\circ} \mathrm{C}\) with a convective heat transfer coefficient of \(10 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Using an explicit finite difference formulation, calculate the temperature distribution in the copper alloy block after \(10 \mathrm{~min}\) have elapsed using \(\Delta t=10 \mathrm{~s}\) and a uniform mesh size of \(\Delta x=\Delta y=10 \mathrm{~cm}\).

Consider a large plane wall of thickness \(L=0.4 \mathrm{~m}\), thermal conductivity \(k=2.3 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), and surface area \(A=20 \mathrm{~m}^{2}\). The left side of the wall is maintained at a constant temperature of \(95^{\circ} \mathrm{C}\), while the right side loses heat by convection to the surrounding air at \(T_{\infty}=15^{\circ} \mathrm{C}\) with a heat transfer coefficient of \(h=18 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Assuming steady one-dimensional heat transfer and taking the nodal spacing to be \(10 \mathrm{~cm},(a)\) obtain the finite difference formulation for all nodes, \((b)\) determine the nodal temperatures by solving those equations, and (c) evaluate the rate of heat transfer through the wall.

Consider a long concrete dam \((k=0.6 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), (es \(\alpha_{s}=0.7\) ) of triangular cross section whose exposed surface is subjected to solar heat flux of \(\dot{q}_{s}=\) \(800 \mathrm{~W} / \mathrm{m}^{2}\) and to convection and radiation to the environment at \(25^{\circ} \mathrm{C}\) with a combined heat transfer coefficient of \(30 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). The \(2-\mathrm{m}\)-high vertical section of the dam is subjected to convection by water at \(15^{\circ} \mathrm{C}\) with a heat transfer coefficient of \(150 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), and heat transfer through the 2-m-long base is considered to be negligible. Using the finite difference method with a mesh size of \(\Delta x=\Delta y=1 \mathrm{~m}\) and assuming steady two-dimensional heat transfer, determine the temperature of the top, middle, and bottom of the exposed surface of the dam.

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