What is the no-slip condition? What causes it?

Short Answer

Expert verified
Answer: The no-slip condition is a fundamental principle in fluid mechanics, stating that the fluid velocity is zero at a solid boundary due to molecular adhesion and fluid viscosity. It leads to the formation of a boundary layer with a velocity gradient over the solid surface.

Step by step solution

01

Definition of No-Slip Condition

The no-slip condition is an essential assumption in fluid mechanics, stating that the fluid velocity is zero at a solid boundary, i.e., at any surface in contact with the fluid, the fluid molecules have the same velocity as the solid. This is due to the viscous nature of fluids, and it leads to the formation of a boundary layer adjacent to the surface where the fluid velocity changes from zero to the free-stream velocity.
02

Causes of No-Slip Condition

The no-slip condition is caused by two primary factors: molecular adhesion and fluid viscosity. 1. Molecular Adhesion: When a fluid comes into contact with a solid surface, adhesive forces between the fluid molecules and the solid's molecules cause the fluid to "stick" to the surface. This means that the fluid molecules in direct contact with the surface have the same velocity as the solid. 2. Fluid Viscosity: Viscosity is a measure of a fluid's resistance to deformation. As the fluid flows over the solid surface, the fluid layers in direct contact with the surface are slowed down due to molecular adhesion. The neighboring fluid layers experience shear forces from the slowed-down layers, causing them to slow down as well. This intermolecular interaction within the fluid due to its viscous nature establishes a velocity gradient from the surface (zero-velocity) to the outer layers of the fluid. In summary, the no-slip condition is a fundamental principle in fluid mechanics that is a consequence of molecular adhesion and fluid viscosity. It states that the fluid velocity is zero at a solid boundary, leading to the formation of a boundary layer with a velocity gradient over the solid surface.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

What is turbulent thermal conductivity? What is it caused by?

A long steel strip is being conveyed through a 3 -m long furnace to be heat treated at a speed of \(0.01 \mathrm{~m} / \mathrm{s}\). The steel strip \(\left(k=21 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, \rho=8000 \mathrm{~kg} / \mathrm{m}^{3}\right.\), and \(c_{p}=570 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\) ) has a thickness of \(5 \mathrm{~mm}\), and it enters the furnace at an initial temperature of \(20^{\circ} \mathrm{C}\). Inside the furnace, the air temperature is maintained at \(900^{\circ} \mathrm{C}\) with a convection heat transfer coefficient of \(80 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Using EES (or other) software, determine the surface temperature gradient of the steel strip as a function of location inside the furnace. By varying the location in the furnace for \(0 \leq x \leq 3 \mathrm{~m}\) with increments of \(0.2 \mathrm{~m}\), plot the surface temperature gradient of the strip as a function of furnace location. Hint: Use the lumped system analysis to calculate the plate surface temperature. Make sure to verify the application of this method to this problem.

What is viscosity? What causes viscosity in liquids and in gases? Is dynamic viscosity typically higher for a liquid or for a gas?

In an effort to prevent the formation of ice on the surface of a wing, electrical heaters are embedded inside the wing. With a characteristic length of \(2.5 \mathrm{~m}\), the wing has a friction coefficient of \(0.001\). If the wing is moving at a speed of \(200 \mathrm{~m} / \mathrm{s}\) through air at 1 atm and \(-20^{\circ} \mathrm{C}\), determine the heat flux necessary to keep the wing surface above \(0^{\circ} \mathrm{C}\). Evaluate fluid properties at \(-10^{\circ} \mathrm{C}\).

Air at \(5^{\circ} \mathrm{C}\), with a convection heat transfer coefficient of \(30 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), is used for cooling metal plates coming out of a heat treatment oven at an initial temperature of \(300^{\circ} \mathrm{C}\). The plates \((k=180 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), \(\rho=2800 \mathrm{~kg} / \mathrm{m}^{3}\), and \(c_{p}=880 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\) ) have a thickness of \(10 \mathrm{~mm}\). Using EES (or other) software, determine the effect of cooling time on the temperature gradient in the metal plates at the surface. By varying the cooling time from 0 to \(3000 \mathrm{~s}\), plot the temperature gradient in the plates at the surface as a function of cooling time. Hint: Use the lumped system analysis to calculate the plate surface temperature. Make sure to verify the application of this method to this problem.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free