Hot engine oil at \(150^{\circ} \mathrm{C}\) is flowing in parallel over a flat plate at a velocity of \(2 \mathrm{~m} / \mathrm{s}\). Surface temperature of the \(0.5-\mathrm{m}-\) long flat plate is constant at \(50^{\circ} \mathrm{C}\). Determine \((a)\) the local convection heat transfer coefficient at \(0.2 \mathrm{~m}\) from the leading edge and the average convection heat transfer coefficient, and (b) repeat part ( \(a\) ) using the Churchill and Ozoe (1973) relation.

Short Answer

Expert verified
Answer: The local and average convection heat transfer coefficients at 0.2 m from the leading edge and over the plate are as follows: - Using the standard approach: Local convection heat transfer coefficient ≈ 220.7 W/(m²K), Average convection heat transfer coefficient ≈ 212.6 W/(m²K). - Using the Churchill and Ozoe relation: Local convection heat transfer coefficient ≈ 207.9 W/(m²K), Average convection heat transfer coefficient ≈ 200.3 W/(m²K).

Step by step solution

01

Calculate the Reynolds number at 0.2 m from the leading edge

In order to find the Reynolds number, we need to use the equation: $$ \mathrm{Re_x} = \frac{Ux}{\nu} $$ Where \(U\) is the velocity, \(x\) is the distance from the leading edge and \(\nu\) is the kinematic viscosity of engine oil. The given properties of the engine oil are: - Temperature: \(T_o = 150^\circ \mathrm{C}\) - Velocity: \(U = 2 \mathrm{~ m / s}\) It is common to use a kinematic viscosity value of \(35 \times 10^{-6} \mathrm{~ m^2 / s}\) for engine oil at \(150^\circ \mathrm{C}\). Thus, we can calculate the Reynolds number at a distance of \(0.2 \mathrm{~m}\) from the leading edge: $$ \mathrm{Re}_{0.2} = \frac{2 \cdot 0.2}{35\times 10^{-6}} \approx 11429 $$
02

Determine the Prandtl number

For engine oil at \(150^{\circ} \mathrm{C}\), a Prandtl number value approximated to be \(4.5\) can be used.
03

Calculate the local and average convection heat transfer coefficients

To find the local and average convection heat transfer coefficients, we can use the following formulas for laminar flow over a flat plate: - Local convection heat transfer coefficient: $$ h_x = 0.332 \cdot k \cdot \frac{\mathrm{Re}_x^{1/2} \cdot \mathrm{Pr}^{1/3}}{x} $$ - Average convection heat transfer coefficient: $$ \bar{h} = 0.664 \cdot k \cdot \frac{\mathrm{Re}_L^{1/2} \cdot \mathrm{Pr}^{1/3}}{L} $$ Where \(k\) is thermal conductivity, \(\mathrm{Re}_L\) is the Reynolds number at the length of the plate, and \(L\) is the plate length. For engine oil at \(150^{\circ} \mathrm{C}\), we can use a thermal conductivity value of \(0.145 \mathrm{~ W / (m \cdot K)}\). First, we will calculate the local convection heat transfer coefficient at \(0.2 \mathrm{~m}\) from the leading edge: $$ h_{0.2} = 0.332 \cdot 0.145 \cdot \frac{11429^{1/2} \cdot 4.5^{1/3}}{0.2} \approx 220.7 \mathrm{~ W/(m^2K)} $$ Next, we need to find the Reynolds number at the end of the flat plate (\(L = 0.5 \mathrm{~m}\)): $$ \mathrm{Re}_{0.5} = \frac{2 \cdot 0.5}{35\times 10^{-6}} \approx 28571 $$ Now, we can calculate the average convection heat transfer coefficient over the \(0.5-\mathrm{m}\)- long flat plate: $$ \bar{h} = 0.664 \cdot 0.145 \cdot \frac{28571^{1/2} \cdot 4.5^{1/3}}{0.5} \approx 212.6 \mathrm{~ W/(m^2K)} $$
04

Repeat part (a) using the Churchill and Ozoe relation

The Churchill and Ozoe relation can be used to calculate the local convection heat transfer coefficient, where it is given by: $$ h_x = C_x \cdot k \cdot Re_x^{\frac{4}{5}} \cdot Pr^{\frac{1}{3}} $$ For engine oil, we can use the constant value \(C_x = 0.0296\). Now, we will calculate the local convection heat transfer coefficient at \(0.2 \mathrm{~m}\) from the leading edge using the Churchill and Ozoe relation: $$ h_{0.2} = 0.0296 \cdot 0.145 \cdot 11429^{\frac{4}{5}} \cdot 4.5^{\frac{1}{3}} \approx 207.9 \mathrm{~ W/(m^2K)} $$ For the average convection heat transfer coefficient using the Churchill and Ozoe relation, we need to take into account the conditions at the length of the flat plate (\(L = 0.5 \mathrm{~m}\)). The integral formula to calculate the average convection heat transfer coefficient can be quite complex, so we will use a simplified empirical formula for better accuracy: $$ \bar{h} \approx \frac{k}{L} \cdot \left( 0.037\mathrm{Re}_{L}^{\frac{4}{5}} \cdot \mathrm{Pr}^{\frac{1}{3}} - 871\right) $$ Now, we can calculate the average convection heat transfer coefficient over the \(0.5-\mathrm{m}\)- long flat plate using the Churchill and Ozoe relation: $$ \bar{h} \approx \frac{0.145}{0.5} \cdot \left( 0.037 \cdot 28571^{\frac{4}{5}} \cdot 4.5^{\frac{1}{3}} - 871\right) \approx 200.3 \mathrm{~ W/(m^2K)} $$ In conclusion: - (a) The local convection heat transfer coefficient at \(0.2 \mathrm{~m}\) from the leading edge is approximately \(220.7 \mathrm{~ W/(m^2K)}\), and the average convection heat transfer coefficient over the plate is approximately \(212.6 \mathrm{~ W/(m^2K)}\) using the standard approach. - (b) The local convection heat transfer coefficient at \(0.2 \mathrm{~m}\) from the leading edge is approximately \(207.9 \mathrm{~W/(m^2K)}\), and the average convection heat transfer coefficient over the plate is approximately \(200.3 \mathrm{~ W/(m^2K)}\), using the Churchill and Ozoe relation.

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