Warm air is blown over the inner surface of an automobile windshield to defrost ice accumulated on the outer surface of the windshield. Consider an automobile windshield \(\left(k_{w}=\right.\) \(0.8 \mathrm{Btu} / \mathrm{h} \cdot \mathrm{ft} \cdot \mathrm{R})\) with an overall height of 20 in and thickness of \(0.2\) in. The outside air ( \(1 \mathrm{~atm})\) ambient temperature is \(8^{\circ} \mathrm{F}\) and the average airflow velocity over the outer windshield surface is \(50 \mathrm{mph}\), while the ambient temperature inside the automobile is \(77^{\circ} \mathrm{F}\). Determine the value of the convection heat transfer coefficient for the warm air blowing over the inner surface of the windshield, necessary to cause the accumulated ice to begin melting. Assume the windshield surface can be treated as a flat plate surface.

Short Answer

Expert verified
Based on the given information, determine the convection heat transfer coefficient of the warm air blowing over the inner surface of the windshield to initiate melting of the ice accumulated on the outer surface. Overall temperature difference across the windshield: ΔT = Tin - Tout = 77°F - 8°F = 69°F

Step by step solution

01

Determine the overall temperature difference across the windshield

Given the ambient temperature inside the automobile as \(T_{in} = 77^{\circ}F\) and the outside ambient temperature as \(T_{out} = 8^{\circ}F\). The overall temperature difference across the windshield is given by: \(\Delta T = T_{in} - T_{out}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Heat Transfer
Heat transfer is a phenomenon wherein thermal energy moves from one object or material to another due to a temperature difference between them. It occurs in three primary forms: conduction, convection, and radiation. In the context of defrosting an automobile windshield, convection plays an essential role.

Convection is the movement of heat through fluids (which include liquids and gases) accompanied by the motion of the fluid itself. When warm air is blown over the inner surface of a windshield, it causes the transfer of heat from the air to the windshield. This process is designed to raise the temperature of the windshield above the freezing point of water, resulting in the ice melting.

In creating content for students, it's important to acknowledge that understanding these heat transfer mechanisms can deeply influence the effectiveness of real-world applications, such as the defrosting process in vehicles.
Thermal Conductivity
Thermal conductivity, denoted as 'k', is a material's ability to conduct heat. It is often measured in terms of energy transferred per unit time over a unit area with a unit temperature gradient. In the exercise, the thermal conductivity of the windshield is given as \(0.8 \mathrm{Btu} / \mathrm{h} \cdot \mathrm{ft} \cdot \mathrm{R}\).

The higher the thermal conductivity, the more efficiently a material can transfer heat. For a windshield, this means that thermal conductivity will affect how quickly the heat from the warm air inside the car can defrost the ice on the outer surface. Materials like metals generally have high thermal conductivity, while insulating materials like glass have lower thermal conductivity, which must be taken into account when designing defrosting systems.
Defrosting Process
The defrosting process refers to the removal of frost or ice from a surface, which can be crucial for an automobile windshield to ensure visibility and safety. The process can be initiated by increasing the temperature of the surface above the melting point of ice, usually achieved through convection heat transfer. Warm air is blown across the surface, causing the ice to absorb heat and undergo a phase change from solid to liquid.

To ensure a smooth defrosting process, understanding the properties of the windshield material, such as its thermal conductivity, and the effectiveness of the heating mechanism, is important. Effective defrosting systems also depend on an adequately high convection heat transfer coefficient, which determines the rate at which heat is transferred from the warm air to the windshield surface.
Temperature Difference
Temperature difference is a driving force for heat transfer. In the given exercise, it's crucial to determine the temperature difference across the windshield to understand how the defrosting will occur. The difference between the inside ambient temperature (\(77^{\text{\small \degree}}F\)) and the outside ambient temperature (\(8^{\text{\small \degree}}F\)) gives us the overall temperature gradient that affects heat transfer. This gradient, \(\Delta T = T_{in} - T_{out}\), represents the 'push' needed to move thermal energy from the warmer interior to the colder exterior.

A larger temperature difference typically results in a higher rate of heat transfer, assuming other conditions remain constant. Hence, for efficient defrosting, the temperature of the warm air inside the automobile should not only be above the melting point of ice but should also create a sufficient temperature difference to facilitate quick melting.

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Most popular questions from this chapter

Define frontal area of a body subjected to external flow. When is it appropriate to use the frontal area in drag and lift calculations?

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Solar radiation is incident on the glass cover of a solar collector at a rate of \(700 \mathrm{~W} / \mathrm{m}^{2}\). The glass transmits 88 percent of the incident radiation and has an emissivity of \(0.90\). The entire hot water needs of a family in summer can be met by two collectors \(1.2 \mathrm{~m}\) high and \(1 \mathrm{~m}\) wide. The two collectors are attached to each other on one side so that they appear like a single collector \(1.2 \mathrm{~m} \times 2 \mathrm{~m}\) in size. The temperature of the glass cover is measured to be \(35^{\circ} \mathrm{C}\) on a day when the surrounding air temperature is \(25^{\circ} \mathrm{C}\) and the wind is blowing at \(30 \mathrm{~km} / \mathrm{h}\). The effective sky temperature for radiation exchange between the glass cover and the open sky is \(-40^{\circ} \mathrm{C}\). Water enters the tubes attached to the absorber plate at a rate of \(1 \mathrm{~kg} / \mathrm{min}\). Assuming the back surface of the absorber plate to be heavily insulated and the only heat loss to occur through the glass cover, determine \((a)\) the total rate of heat loss from the collector, \((b)\) the collector efficiency, which is the ratio of the amount of heat transferred to the water to the solar energy incident on the collector, and \((c)\) the temperature rise of water as it flows through the collector.

Air at \(25^{\circ} \mathrm{C}\) flows over a 5 -cm-diameter, 1.7-m-long smooth pipe with a velocity of \(4 \mathrm{~m} / \mathrm{s}\). A refrigerant at \(-15^{\circ} \mathrm{C}\) flows inside the pipe and the surface temperature of the pipe is essentially the same as the refrigerant temperature inside. The drag force exerted on the pipe by the air is (a) \(0.4 \mathrm{~N}\) (b) \(1.1 \mathrm{~N}\) (c) \(8.5 \mathrm{~N}\) (d) \(13 \mathrm{~N}\) (e) \(18 \mathrm{~N}\) (For air, use \(\nu=1.382 \times 10^{-5} \mathrm{~m}^{2} / \mathrm{s}, \rho=1.269 \mathrm{~kg} / \mathrm{m}^{3}\) )

Air is flowing in parallel over the upper surface of a flat plate with a length of \(4 \mathrm{~m}\). The first half of the plate length, from the leading edge, has a constant surface temperature of \(50^{\circ} \mathrm{C}\). The second half of the plate length is subjected to a uniform heat flux of \(86 \mathrm{~W} / \mathrm{m}^{2}\). The air has a free stream velocity and temperature of \(2 \mathrm{~m} / \mathrm{s}\) and \(10^{\circ} \mathrm{C}\), respectively. Determine the local convection heat transfer coefficients at \(1 \mathrm{~m}\) and \(3 \mathrm{~m}\) from the leading edge. Evaluate the air properties at a film temperature of \(30^{\circ} \mathrm{C}\). Is the film temperature \(T_{f}=30^{\circ} \mathrm{C}\) applicable at \(x=3 \mathrm{~m}\) ?

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