A \(0.2 \mathrm{~m} \times 0.2 \mathrm{~m}\) street sign surface has an absorptivity of \(0.6\) and an emissivity of \(0.7\), while the street sign is subjected to a cross flow wind at \(20^{\circ} \mathrm{C}\) with a velocity of \(1 \mathrm{~m} / \mathrm{s}\). Solar radiation is incident on the street sign at a rate of \(1100 \mathrm{~W} / \mathrm{m}^{2}\), and the surrounding temperature is \(20^{\circ} \mathrm{C}\). Determine the surface temperature of the street sign. Evaluate the air properties at \(30^{\circ} \mathrm{C}\). Treat the sign surface as a vertical plate in cross flow.

Short Answer

Expert verified
Question: Determine the temperature on the surface of a street sign subjected to solar radiation and cross-flow wind, given that the sign dimensions are \(0.2m \times 0.2m\), sign surface absorptivity is \(\alpha = 0.6\), sign surface emissivity is \(\varepsilon = 0.7\), wind temperature is \(T_{wind} = 20^{\circ}C\), wind velocity is \(1 m/s\), solar radiation is \(1100 \, W/m^2\), surrounding temperature is \(20^{\circ}\)C, and air properties are evaluated at \(30^{\circ}\)C. Answer: To determine the temperature on the surface of the street sign, follow these steps: 1. Find the radiative heat transfer: \(q''_{rad} = 660 \, W/m^2\). 2. Find the convective heat transfer coefficient using the empirical correlation for a vertical plate in cross-flow. 3. Calculate the convective heat transfer: \(q''_{conv} = h(T_s-T_{wind})\). 4. Apply the energy balance equation: \(q''_{rad} = q''_{conv}\). 5. Evaluate air properties at the specified temperature, \(30^{\circ}\)C. 6. Solve for the surface temperature, \(T_s\), of the street sign.

Step by step solution

01

Gather given information

We are given following data - Sign dimensions: \(0.2m \times 0.2m\) - Sign surface absorptivity: \(\alpha = 0.6\) - Sign surface emissivity: \(\varepsilon = 0.7\) - Wind temperature: \(T_{wind} = 20^{\circ}C\) - Wind velocity: \(1 m/s\) - Solar radiation: \(1100 \, W/m^2\) - Surrounding temperature: \(20^{\circ}\)C - Air properties to be evaluated at \(30^{\circ}\)C
02

Find the radiative heat transfer

The absorbed solar radiation (radiative heat gain) on the street sign can be represented as \(q''_{rad} = \alpha G_s\), where: - \(q''_{rad}\) - Radiative heat transfer per unit area - \(G_s\) - Incident solar radiation \(q''_{rad} = 0.6 \times 1100 = 660 \, W/m^2\)
03

Find the convective heat transfer coefficient

As the surface is treated as a vertical plate in cross-flow, we can use the following empirical correlation (assuming turbulent flow) for calculating the convective heat transfer coefficient \(h\): \(h = 0.664\sqrt{Re_{x}}\times Pr^{(1/3)}\times \frac{\left(\frac{\mu}{\mu_w}\right)^a}{fRe_x Pr}\) where, - \(Re_x\) - Reynold's number based on length x - \(Pr\) - Prandtl number - \(\mu\) and \(\mu_w\) - Dynamic viscosities of fluid and near-wall fluid, respectively - \(f\) - 0.037 to 0.047 in turbulent flow - \(a\) - 0.14 to 0.17 in turbulent flow Note: We can use the heat transfer charts to determine the Reynolds number, Prandtl number, fluid, and wall dynamic viscosity at the specified temperature.
04

Calculate the convective heat transfer

The convective heat transfer per unit area between the wind and the sign surface can be represented as \(q''_{conv} = h(T_s-T_{wind})\), where: - \(q''_{conv}\) - Convective heat transfer per unit area - \(T_s\) - Surface temperature of the sign
05

Apply the energy balance equation

Now, let's apply the energy balance equation for radiative and convective heat transfer: \(q''_{rad} = q''_{conv}\) Plug in the expressions found above: \(660 \, W/m^2 = h(T_s-20)\) Solve for \(T_s\).
06

Evaluate air properties

Evaluate the air properties such as viscosity and Prandtl number or use the heat transfer charts at the specified temperature, \(30^{\circ}\)C.
07

Final Calculation

After plugging in the values of \(h\) and the air properties, we can solve for the surface temperature \((T_s)\) of the street sign, which is the temperature we're trying to determine in this problem.

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Most popular questions from this chapter

A heated long cylindrical rod is placed in a cross flow of air at \(20^{\circ} \mathrm{C}(1 \mathrm{~atm})\) with velocity of \(10 \mathrm{~m} / \mathrm{s}\). The rod has a diameter of \(5 \mathrm{~mm}\) and its surface has an emissivity of \(0.95\). If the surrounding temperature is \(20^{\circ} \mathrm{C}\) and the heat flux dissipated from the rod is \(16000 \mathrm{~W} / \mathrm{m}^{2}\), determine the surface temperature of the rod. Evaluate the air properties at \(70^{\circ} \mathrm{C}\).

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