A 10 -m-long and 10 -mm-inner-diameter pipe made of commercial steel is used to heat a liquid in an industrial process. The liquid enters the pipe with \(T_{i}=25^{\circ} \mathrm{C}, V=0.8 \mathrm{~m} / \mathrm{s}\). A uniform heat flux is maintained by an electric resistance heater wrapped around the outer surface of the pipe, so that the fluid exits at \(75^{\circ} \mathrm{C}\). Assuming fully developed flow and taking the average fluid properties to be \(\rho=1000 \mathrm{~kg} / \mathrm{m}^{3}, c_{p}=\) \(4000 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}, \mu=2 \times 10^{-3} \mathrm{~kg} / \mathrm{m} \cdot \mathrm{s}, k=0.48 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), and \(\operatorname{Pr}=10\), determine: (a) The required surface heat flux \(\dot{q}_{s}\), produced by the heater (b) The surface temperature at the exit, \(T_{s}\) (c) The pressure loss through the pipe and the minimum power required to overcome the resistance to flow.

Short Answer

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Question: Determine the required surface heat flux, the surface temperature at the exit, the pressure loss through the pipe, and the minimum power required to overcome the resistance to flow in a 10-meter long and 10-mm-inner diameter pipe with an inlet temperature of 25°C and an outlet temperature of 75°C. Answer: 1. Calculate the mass flow rate and Reynolds number: Mass flow rate, \(\dot{m}= \rho AV\) Reynolds number, \(\text{Re}= \frac{\rho V d}{\mu}\) 2. Calculate the Nusselt number and heat transfer coefficient: Nusselt number, \(\text{Nu}= 0.023\; \text{Re}^{0.8}\; \operatorname{Pr}^{n}\) Heat transfer coefficient, \(h= \frac{\text{Nu}\cdot k}{d}\) 3. Calculate the required surface heat flux: Required surface heat flux, \(\dot{q}_{s}= \frac{\dot{m}c_{p}(T_{o}-T_{i})}{L}\) 4. Calculate the surface temperature at the exit: Surface temperature at the exit, \(T_{s}= T_{o}+ \frac{\dot{q}_{s}}{h A_{s}}\) 5. Determine the pressure loss through the pipe and the minimum power required to overcome the resistance to flow: Pressure loss, \(\Delta P= f \frac{L \rho V^{2}}{2 d}\) Friction factor, \(f= 0.079\; \text{Re}^{-0.25}\) Minimum power required, \(P_{\text{min}}= \frac{\Delta P \dot{V}}{\rho}\)

Step by step solution

01

Calculate the mass flow rate and Reynolds number

First, let's find the mass flow rate of the liquid (\(\dot{m}\)). The mass flow rate can be calculated using the formula: $$\dot{m}=\rho A V$$ where \(\rho=1000 \mathrm{~kg} / \mathrm{m}^{3}\) is the density, \(A\) is the cross-sectional area, and \(V=0.8 \mathrm{~m} / \mathrm{s}\) is the velocity. The cross-sectional area can be found using the formula: $$A=\pi r^{2}$$ where \(r\) is the pipe radius, which can be found from the inner diameter of the pipe (10mm). Now find the Reynolds number (\(\text{Re}\)): $$\text{Re}=\frac{\rho V d}{\mu}$$ where \(d\) = diameter and \(\mu=2 \times 10^{-3} \mathrm{~kg} / \mathrm{m} \cdot \mathrm{s}\) is the dynamic viscosity.
02

Calculate the Nusselt number and heat transfer coefficient

For fully developed flow in a circular pipe, we can use Dittus-Boelter correlation to find the Nusselt number: $$\text{Nu}=0.023\; \text{Re}^{0.8}\; \operatorname{Pr}^{n}$$ where \(\operatorname{Pr}=10\) is the Prandtl number, and \(n\) = 0.3 for heating case. The heat transfer coefficient, \(h\), can be calculated from the Nusselt number: $$h=\frac{\text{Nu}\cdot k}{d}$$ where \(k=0.48 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\) is the thermal conductivity.
03

Calculate the required surface heat flux

According to the conservation of energy principle, the energy added to the fluid by the heater is equal to the energy increase of the fluid, which can be represented as: $$\dot{q}_{s}=h A_{s}(T_{s} - T_{o})$$ and using the mass flow rate, we have: $$\dot{m}c_{p}(T_{o}-T_{i})=\dot{q}_{s}L$$ Solving for \(\dot{q}_{s}\), we get: $$\dot{q}_{s}=\frac{\dot{m}c_{p}(T_{o}-T_{i})}{L}$$ where \(c_{p}=4000 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\) is the specific heat capacity, \(T_{i}=25^{\circ} \mathrm{C}\), and \(T_{o}=75^{\circ} \mathrm{C}\) are the inlet and outlet temperatures, and \(L=10\;\mathrm{m}\) is the pipe length.
04

Calculate the surface temperature at the exit

From the heat transfer equation in step 3, find the surface temperature at the exit (\(T_{s}\)) by rearranging the equation: $$T_{s}=T_{o}+\frac{\dot{q}_{s}}{h A_{s}}$$
05

Determine the pressure loss through the pipe and the minimum power required to overcome the resistance to flow

To calculate the pressure loss, we can use the Darcy-Weisbach equation for fully developed flow in a pipe: $$\Delta P=f \frac{L \rho V^{2}}{2 d}$$ We can estimate the friction factor \(f\) using the Blasius correlation for turbulent flow: $$f=0.079\; \text{Re}^{-0.25}$$ From the pressure loss, the minimum power required to overcome the resistance to flow can be calculated as: $$P_{\text{min}}=\frac{\Delta P \dot{V}}{\rho}$$ where \(\dot{V}=AV\) is the volume flow rate. Calculate the values using the found formulas and parameters.

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