Is the heat transfer rate through the glazing of a double-pane window higher at the center or edge section of the glass area? Explain.

Short Answer

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Answer: The heat transfer rate is higher at the edge section of the glass area in a double-pane window mainly due to increased convection resulting from larger temperature differences between the inner and outer panes and possible variations in the spacing between them. Convection is more prominent at the edges, while it is minimized at the center section due to a more uniform temperature distribution and reduced air movement.

Step by step solution

01

Identify key factors for heat transfer in double-pane windows

Double-pane windows consist of two glass layers separated by a space filled with an insulating material or gas. Heat transfer through the double-pane window occurs primarily by three mechanisms: conduction through the glass panes, convection within the space between the panes, and radiation between the panes. To determine how the heat transfer rate differs between the center and the edge section of the glass area, these factors need to be analyzed in each area.
02

Evaluate heat transfer rates in the center of the glass area

At the center of the glass area of a double-pane window, the temperature distribution across the glass panes is more uniform. Conduction through the glass panes remains relatively constant across the entire width of the panes, as does radiation between them. Convection within the space between the panes may be present, yet it is greatly minimized due to a homogeneous distance between the panes and reduced air movement. This will result in a relatively low heat transfer rate in the center of the glass area.
03

Evaluate heat transfer rates at the edge of the glass area

At the edge of the double-pane window's glass area, the temperature distribution across the glass panes can vary more significantly than in the center. Conduction through the glass panes might be slightly different at the edges due to possible variations in glass thickness or composition. Convection between the panes is more likely to be prominent at the edge sections, as the temperature difference between the inner and outer panes is usually higher and variations in spacing between the panes might result in better convection currents. Consequently, heat transfer at the edges of the glass area may be higher due to increased convection.
04

Compare and explain the heat transfer rates

Comparing the heat transfer rate in both sections, it can be concluded that the heat transfer rate at the edge section of the glass area of a double-pane window is higher than at the center section. This is mainly due to the increased convection at the edges resulting from larger temperature differences between the inner and outer panes and possible variations in the spacing between them, despite minor differences in conduction or radiation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conduction Through Glass Panes
Understanding how heat is conducted through the glass panes of double-glazed windows is essential to grasp the efficiency of these windows. In a double-pane window, each glass sheet acts as a barrier to heat flow. Heat is transferred through solid materials like glass by the process of conduction, where kinetic energy is passed from molecule to molecule.

The rate of heat conduction through a material is determined by the thermal conductivity of the material and the temperature difference across it, a principle described by Fourier's Law of Heat Conduction, which in its basic form reads: \( q = -k \frac{dT}{dx} \) where \( q \) is the heat transfer rate per unit area, \( k \) is the thermal conductivity, and \( \frac{dT}{dx} \) is the temperature gradient across the material. In double-pane windows, glass panes are of uniform structure and thickness, theoretically leading to uniform conduction. However, at the edges, where the glass may be more exposed to the frame or sealant materials, slight differences in temperature distribution may affect the conduction rate.

As a result, you should consider that while conduction is relatively consistent across the pane, edge effects can influence the overall heat transfer slightly, making understanding the details of conduction crucial for analyzing window performance.
Convection in Insulating Gas
Convection is a significant factor in the heat transfer process in the insulating space between the glass panes of double-glazed windows. This space is filled with air or another gas, which acts as insulation. Convection occurs when this gas is heated and begins to circulate, transferring heat energy. However, the design of double-pane windows aims to restrict convection currents.

The spacer placed between the glass panes keeps them apart and, combined with the sealant, traps the gas to minimize its movement. Restricted gas movement leads to limited convection, which in turn reduces heat transfer, enhancing the window's insulative properties. It's crucial to understand that while convection is reduced, it can still occur, especially at the edges where the sealant or the frame may not be as effective, allowing warmer air to circulate to the colder side, thus slightly increasing the heat transfer rate at the window's perimeter.
Temperature Distribution in Double Glazing
The way in which temperature is distributed across double-glazed windows plays a critical role in how they insulate a room. At the center of the glass area, the temperature distribution is fairly even, primarily because the spacing between the panes is consistent, and there is little to no air movement to disrupt this balance. As a result, the center of the window acts efficiently in minimizing heat transfer.

However, towards the edges, this balance shifts. The frames and sealant materials that hold the glass panes in place may conduct heat differently than the glass itself, leading to a variable temperature distribution. This inconsistency at the edges can give rise to warmer and colder spots, which can influence the efficiency of the window in terms of heat retention or loss. This variability is a crucial concept to understand as it directly correlates with higher heat transfer rates along the window's perimeter.
Radiation Between Glass Panes
Radiation is another mode of heat transfer that affects the thermal performance of double-glazed windows. Thermal radiation, which is heat transfer through electromagnetic waves, can occur between the two glass panes. Glass is partially transparent to certain wavelengths of infrared radiation, which means that some heat in the form of infrared radiation can be transferred directly through the panes.

Manufacturers often apply coatings to glass surfaces to reduce radiative heat transfer. These low-emissivity (low-E) coatings reflect infrared radiation, thereby limiting the amount of heat that is radiated from the warm pane to the cooler pane. It's important to note, however, that radiation is less sensitive to the small differences in the spacing between the panes than convection is, but it still plays a role in the overall heat transfer, especially when considering the complete thermal profile of the window.

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Most popular questions from this chapter

A 0.1-W small cylindrical resistor mounted on a lower part of a vertical circuit board is \(0.3\) in long and has a diameter of \(0.2 \mathrm{in}\). The view of the resistor is largely blocked by another circuit board facing it, and the heat transfer through the connecting wires is negligible. The air is free to flow through the large parallel flow passages between the boards as a result of natural convection currents. If the air temperature at the vicinity of the resistor is \(120^{\circ} \mathrm{F}\), determine the approximate surface temperature of the resistor. Evaluate air properties at a film temperature of \(170^{\circ} \mathrm{F}\) and \(1 \mathrm{~atm}\) pressure. Is this a good assumption? Answer: \(211^{\circ} \mathrm{F}\)

The overall \(U\)-factor of a fixed wood-framed window with double glazing is given by the manufacturer to be \(U=\) \(2.76 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) under the conditions of still air inside and winds of \(12 \mathrm{~km} / \mathrm{h}\) outside. What will the \(U\)-factor be when the wind velocity outside is doubled? Answer: \(2.88 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\)

A \(1.5\)-m-diameter, 4-m-long cylindrical propane tank is initially filled with liquid propane, whose density is \(581 \mathrm{~kg} / \mathrm{m}^{3}\). The tank is exposed to the ambient air at \(25^{\circ} \mathrm{C}\) in calm weather. The outer surface of the tank is polished so that the radiation heat transfer is negligible. Now a crack develops at the top of the tank, and the pressure inside drops to \(1 \mathrm{~atm}\) while the temperature drops to \(-42^{\circ} \mathrm{C}\), which is the boiling temperature of propane at \(1 \mathrm{~atm}\). The heat of vaporization of propane at \(1 \mathrm{~atm}\) is \(425 \mathrm{~kJ} / \mathrm{kg}\). The propane is slowly vaporized as a result of the heat transfer from the ambient air into the tank, and the propane vapor escapes the tank at \(-42^{\circ} \mathrm{C}\) through the crack. Assuming the propane tank to be at about the same temperature as the propane inside at all times, determine how long it will take for the tank to empty if it is not insulated.

A 3 -mm-diameter and 12-m-long electric wire is tightly wrapped with a \(1.5-\mathrm{mm}\)-thick plastic cover whose thermal conductivity and emissivity are \(k=0.20 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\) and \(\varepsilon=0.9\). Electrical measurements indicate that a current of \(10 \mathrm{~A}\) passes through the wire and there is a voltage drop of \(7 \mathrm{~V}\) along the wire. If the insulated wire is exposed to calm atmospheric air at \(T_{\infty}=30^{\circ} \mathrm{C}\), determine the temperature at the interface of the wire and the plastic cover in steady operation. Take the surrounding surfaces to be at about the same temperature as the air. Evaluate air properties at a film temperature of \(40^{\circ} \mathrm{C}\) and \(1 \mathrm{~atm}\) pressure. Is this a good assumption?

A 4-m-diameter spherical tank contains iced water at \(0^{\circ} \mathrm{C}\). The tank is thin-shelled and thus its outer surface temperature may be assumed to be same as the temperature of the iced water inside. Now the tank is placed in a large lake at \(20^{\circ} \mathrm{C}\). The rate at which the ice melts is (a) \(0.42 \mathrm{~kg} / \mathrm{s}\) (b) \(0.58 \mathrm{~kg} / \mathrm{s}\) (c) \(0.70 \mathrm{~kg} / \mathrm{s}\) (d) \(0.83 \mathrm{~kg} / \mathrm{s}\) (e) \(0.98 \mathrm{~kg} / \mathrm{s}\) (For lake water, use \(k=0.580 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, \operatorname{Pr}=9.45, v=\) \(0.1307 \times 10^{-5} \mathrm{~m}^{2} / \mathrm{s}, \beta=0.138 \times 10^{-3} \mathrm{~K}^{-1}\) )

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