In the tropics, the water near the surface is warmer than the deep water. Would an engine operating between these two levels violate the second law? Why?

Short Answer

Expert verified
No, an engine operating between these two levels would not violate the second law because it utilizes a natural temperature gradient.

Step by step solution

01

Understand the Second Law of Thermodynamics

The second law of thermodynamics states that heat naturally flows from a high-temperature region to a low-temperature region. It also implies that no heat engine can be 100% efficient because some energy must always be lost as waste heat.
02

Identify the Temperature Gradient

In the given scenario, the water near the surface of the tropics is warmer than the deep water, creating a temperature gradient. This means there is a difference in temperature between the two levels of water.
03

Evaluate Engine Operation

An engine can theoretically operate between two temperatures by taking in heat energy from the warmer water and expelling some waste heat to the cooler, deep water. This process aligns with the second law of thermodynamics.
04

Conclusion

Since the engine utilizes a natural temperature gradient to convert heat into work while complying with the second law of thermodynamics, it would not violate the second law.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Heat Flow
Heat flow is the movement of thermal energy from one place to another. According to the Second Law of Thermodynamics, heat always moves from a region of higher temperature to a region of lower temperature.
In our scenario, the warmer water near the surface of the tropics and the cooler, deep water create a natural direction for heat flow.
The engine would draw heat from the warmer water and release some of it as waste heat into the cooler water, which complies with the natural flow of heat. By doing so, the engine benefits from the energy contained in the thermal gradient. This transfer of thermal energy enables the engine to perform work. This is why heat engines are often found in environments with clear temperature differences.
Temperature Gradient
A temperature gradient refers to the change in temperature with distance within a system or between two points.
In our example, the surface water of the tropics is warmer compared to the deep water, creating a temperature gradient.
This gradient is crucial for the operation of a heat engine, as it provides the necessary conditions for heat to flow from the hotter region (surface water) to the cooler region (deep water).
The larger the temperature difference, the more potential the engine has to convert heat into work. The temperature gradient is a driving force for the efficient operation of many thermal systems, such as refrigerators and power plants.
Heat Engine Efficiency
Heat engine efficiency describes how well an engine converts the absorbed heat energy into work.
According to the second law of thermodynamics, no engine can be 100% efficient because it is impossible to convert all absorbed heat into useful work; some of it must always be expelled as waste heat.
The efficiency of an engine depends on the temperature difference (temperature gradient) between the heat source and the heat sink.
Higher temperature differences result in higher potential efficiencies. However, practical limitations and engineering constraints generally lower the efficiency of real-world engines compared to their ideal counterparts. Heat engines rely on exploiting temperature gradients to maximize work output and lessen energy loss.
Waste Heat
Waste heat is the portion of heat energy that is not converted into mechanical work within an engine.
According to the second law of thermodynamics, some amount of energy must always be lost in the form of waste heat during the operation of any heat engine. This waste heat is typically released into the cooler environment. In our scenario, the deep cooler water acts as a sink for this waste heat.
The presence of waste heat is a fundamental reason why perfect efficiency is unattainable in heat engines. Engineers constantly seek ways to reduce the amount of waste heat to enhance the overall efficiency of thermal systems. This includes innovations like combined heat and power systems, which reuse portions of waste heat for additional energy applications.

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Most popular questions from this chapter

A vessel contains \(10^{-3} \mathrm{~m}^{3}\) of helium gas at \(3 \mathrm{~K}\) and \(10^{3} \mathrm{~Pa}\). Take the zero of internal energy of helium to be at this state. (a) The temperature is raised at constant volume to \(300 \mathrm{~K}\). Assuming helium to behave like an ideal monatomic gas, how much heat is absorbed, and what is the internal energy of the helium? Can this energy be regarded as the result of heating or working? (b) The helium is now expanded adiabatically to \(3 \mathrm{~K}\). How much work is done, and what is the new internal energy? Has heat been converted to work without compensation, thus violating the second law? (c) The helium is now compressed isothermally to its original volume. What are the quantities of heat and work in this process? What is the thermal efficiency of the cycle? Plot the cycle on a \(P V\) diagram.

Prove that it is impossible for two reversible adiabatics to intersect. (Hint: Assume that they do intersect and complete the cycle with an isothermal. Show that the performance of this cycle violates the second law.)

An imaginary ideal-gas engine operates in a cycle, which forms a rectangle with sides parallel to the axes of a \(P V\) diagram. Call \(P_{1}\) and \(P_{2}\) the lower and higher pressures, respectively; call \(V_{1}\) and \(V_{2}\) the lower and higher volumes, respectively. (a) Calculate the work done in one cycle. (b) Indicate which parts of the cycle involve heat flow into the gas, and calculate the amount of heat flowing into the gas in one cycle. (Assume constant heat capacities.) (c) Show that the efficiency of this engine is $$ \eta=\frac{\gamma-1}{\frac{\gamma P_{2}}{P_{2}-P_{1}}+\frac{V_{1}}{V_{2}-V_{1}}} $$

A storage battery is connected to a motor, which is used to lift a weight. The battery remains at constant temperature by receiving heat from the outside air. Is this a violation of the second law? Why?

There are many paramagnetic solids that have internal energies which depend only on temperature, like an ideal gas. In an isothermal decrease of the magnetic field, heat is absorbed from one reservoir and converted completely into work. Is this a violation of the second law? Explain.

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