A short cylinder, of radius a and length L, carries a "frozen-in" uniform polarization P, parallel to its axis. Find the bound charge, and sketch the electric field (i) for La, (ii) for La, and (iii) for La. [This is known as a bar electret; it is the electrical analog to a bar magnet. In practice, only very special materials-barium titanate is the most "familiar" example-will hold a permanent electric polarization. That's why you can't buy electrets at the toy store.]

Short Answer

Expert verified

(a) In the event that La, the field will roughly resemble that of a physical dipole, with "point charges" of magnitude ±PAspaced Lapart.

(b) The field between the top and bottom of the cylinder in the case Lawill roughly resemble that of a parallel-plate capacitor with surface charge densities ±Pon the top and bottom.

(c) Simply take a look at the preceding two situations; they both have surface charge densities ±Pon the top/bottom. About as the photo depicts, the field looks.

Step by step solution

01

Write the given data from the question.

Consider a short cylinder, of radius aand length L, carries a "frozen-in" uniform polarization P, parallel to its axis .

02

(a) Determine for L≫a.

Draw the circuit diagram of electric field forLa .

Figure 1

ForLa .

In the event that La, the field will roughly resemble that of a physical dipole, with "point charges" of magnitude±PA spaced apart.

03

(b) Determine for L≪a.

Draw the circuit diagram of electric field for La.

Figure 2

The field between the top and bottom of the cylinder in the case Lawill roughly resemble that of a parallel-plate capacitor with surface charge densities±P on the top and bottom.

04

(b) Determine for L≈a.

Draw the circuit diagram of electric field for La

Figure 3

Simply take a look at the preceding two situations; they both have surface charge densities±P on the top/bottom. About as the photo depicts, the field looks.

The surface bound charge is the only bound charge present in all three scenarios since the polarisation is constant, ρb=0.

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