When you polarize a neutral dielectric, the charge moves a bit, but the total remains zero. This fact should be reflected in the bound charges σb and ρb· Prove from Eqs. 4.11 and 4.12 that the total bound charge vanishes.

Short Answer

Expert verified

The value of total charge of a piece of neutral dielectricQtotal is 0.

Step by step solution

01

Write the given data from the question

Consider thereflected in the bound charges σband ρb·

Consider when you polarize a neutral dielectric, the charge moves a bit, but the total remains zero.

02

Determine the formula of total charge of a piece of neutral dielectric Qtotal.

Write the formula of total charge of a piece of neutral dielectric Qtotal.

Qtotal=SσbdS+νρbdτ …… (1)

Here, σb and ρb are the reflected in the bound charges.

03

 Determine the value of total charge of a piece of neutral dielectric Qtotal.

Determine thetotal charge of a piece of neutral dielectric.

SubstitutePn^ for σandP forρ into equation (1).

Qtotal=SσdS+νPdτ

However, according to divergence law, the two terms are equivalent and cancel one another out.

Qtotal=0

Therefore, the value of total charge of a piece of neutral dielectricQtotal is 0.

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Most popular questions from this chapter

A thick spherical shell (inner radius a, outer radius b) is made of dielectric material with a "frozen-in" polarization

P(r)=krr^

Where a constant and is the distance from the center (Fig. 4.18). (There is no free charge in the problem.) Find the electric field in all three regions by two different methods:

Figure 4.18

(a) Locate all the bound charge, and use Gauss's law (Eq. 2.13) to calculate the field it produces.

(b) Use Eq. 4.23 to find D, and then getE from Eq. 4.21. [Notice that the second method is much faster, and it avoids any explicit reference to the bound charges.]

At the interface between one linear dielectric and another, the electric field lines bend (see Fig. 4.34). Show that

tanθ2/tanθ1=ε2/ε1

Assuming there is no free charge at the boundary. [Comment: Eq. 4.68 is reminiscent of Snell's law in optics. Would a convex "lens" of dielectric material tend to "focus’’ or "defocus," the electric field?]

A point charge qis imbedded at the center of a sphere of linear dielectric material (with susceptibilityχeand radius R).Find the electric field, the polarization, and the bound charge densities,ρb and σb.What is the total bound charge on the surface? Where is the compensating negative bound charge located?

E2Find the field inside a sphere of linear dielectric material in an otherwise uniform electric field E0(Ex. 4.7) by the following method of successive approximations: First pretend the field inside is just E0, and use Eq. 4.30 to write down the resulting polarization P0. This polarization generates a field of its own, E1 (Ex. 4.2), which in turn modifies the polarization by an amount P1. which further changes the field by an amount E2, and so on. The resulting field is E0+E1+E2+.... . Sum the series, and compare your answer with Eq. 4.49.

A very long cylinder, of radius a, carries a uniform polarization P perpendicular to its axis. Find the electric field inside the cylinder. Show that the field outside the cylinder can be expressed in the form

E(r)=a22ε0s2[2P-s^s^-P]

[Careful: I said "uniform," not "radial"!]

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