Show that the energy of an ideal dipole p in an electric field E isgiven by

U=pE

Short Answer

Expert verified

Thepotential energy for the dipole moment ispE .

Step by step solution

01

Determine the formulas

Consider the formula for the torque on the dipole moment as

τ=pEsinθ

Here, pis the dipole moment and E is the electric field.

02

Determine the formula for the energy of the dipole moment 

Consider the formula for work done in the rotating dipole moment as:

dw=τdθ

Substitute the values and solve as

dw=pEsinθdθw=a1a2pEsinθdθw=pE(cosθ1cosθ2)

Consider the change in the potential for the two dipole positions and the corresponding working done as

w=U(θ2)U(θ1)=pE(cosθ2θ1)=pEcosθ=pE

Therefore, the potential energy for the dipole moment is pE.

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Most popular questions from this chapter

A very long cylinder of linear dielectric material is placed in an otherwise uniform electric fieldE0 .Find the resulting field within the cylinder. (The radius is a , the susceptibilityχe . and the axis is perpendicular toE0.)

When you polarize a neutral dielectric, the charge moves a bit, but the total remains zero. This fact should be reflected in the bound charges σb and ρb· Prove from Eqs. 4.11 and 4.12 that the total bound charge vanishes.

A dipole p is a distancer from a point charge q, and oriented so thatp makes an angle θ with the vectorr fromq to p.

(a) What is the force on p?

(b) What is the force on q?

The Clausius-Mossotti equation (Prob. 4.41) tells you how to calculatethe susceptibility of a nonpolar substance, in terms of the atomic polariz-ability. The Langevin equation tells you how to calculate the susceptibility of apolar substance, in terms of the permanent molecular dipole moment p. Here's howit goes:

(a) The energy of a dipole in an external field E isu=-p·Ecosθ

(Eq. 4.6), whereθ is the usual polar angle, if we orient the z axis along E.

Statistical mechanics says that for a material in equilibrium at absolute temperature

T, the probability of a given molecule having energy u is proportional to

the Boltzmann factor,

exp(-u/kT)

The average energy of the dipoles is therefore

<u>=ue-(u/kt)e-(u/kT)

where =sinθdθdϕ, and the integration is over all orientations θ:0π;ϕ:02πUse this to show that the polarization of a substance

containing N molecules per unit volume is

P=Np[cothpE/kT-kT/pE] (4.73)

That's the Langevin formula. Sketch as a function ofPE/KT .

(b) Notice that for large fields/low temperatures, virtually all the molecules arelined up, and the material is nonlinear. Ordinarily, however, kT is much greaterthan p E. Show that in this regime the material is linear, and calculate its susceptibility,in terms of N, p, T, and k. Compute the susceptibility of water at 20°C,and compare the experimental value in Table 4.2. (The dipole moment of wateris 6.1×10-30C·m) This is rather far off, because we have again neglected thedistinction between E and Eelse· The agreement is better in low-density gases,for which the difference between E and Eelse is negligible. Try it for water vapor

at 100°C and 1 atm.

An electric dipole p, pointing in the ydirection, is placed midwaybetween two large conducting plates, as shown in Fig. 4.33. Each plate makes a small angle θwith respect to the xaxis, and they are maintained at potentials ±V.What is the directionof the net force onp?(There's nothing to calculate,here, butdo explain your answer qualitatively.)

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