Work out the remaining five parts to Eq. 12.118.

Short Answer

Expert verified

All the remaining five parts to equation 12.118 are proved.

Step by step solution

01

Expression for the second rank tensor:

Write an expression for the second rank tensor:

t¯μv=λμλvtλσ

Here, is the Lorentz transformation matrix.

Write the expression for the Lorentz transformation matrix.

=γ-γβ00-γβγ0000100001 …… (1)

Write the expression for the four dimension tensor.

tμv=t00t01t02t03t10t11t12t13t20t21t22t23t30t31t32t33 …… (2)

02

Determine the remaining five parts to equation 12.118:

Using equation 12.118, write the complete set of transformation rules.

t¯02=γt02-βt12t¯03=γt03-βt31t¯23=t23t¯31=γt31+βt03,t¯12=γγ12-βt02

Write the expression fort¯02.

t¯02=λ0σ2tλσ

Expand the above expression.

t¯02=0001t00+0012t01+0022t02+1002t10+1012t11+1022t12+0002t20+2012t21+2022t22

From equations (1) and (2),

t¯02=0+0+γt02+0+0+-γβt12+0+0+0t¯02=γt02-βt12

Write the expression for t¯03.

t¯03=λ0σ3tλσ

Expand the above expression.

t¯03=0003t00+0013t01+0023t02+0033t03+1003t10+1013t11+1023t12+1033t13+2003t20+2013t21+2023t22+0033t23+3003t30+3013t31+3023t32+3033t33

From equations (1) and (2),

role="math" localid="1653998733519" t¯03=0+0+0+γt03+0+0+0+-γβt13+0+0+0+0+0+0+0+0t¯03=γt03-γβt13t¯03=γt03-βt13

Write the expression for t¯23.

t¯23=λ2σ3tλσ

Expand the above expression.

t¯23=2223t22+2233t23+3223t32+3233t33

From equations (1) and (2),

t¯23=0+1t23+0+0t¯23=t23

Write the expression for t¯31.

t¯31=λ3σ1tλσ

Expand the above expression.

t¯31=1301t10+1311t11+1321t12+2301t20+2313t21+2321t22+3301t30+3311t31+3321t32

From equations (1) and (2),

t¯31=0+0+0+0+0+0+-γβt30+γt31+0t¯31=-γβt30+γt31t¯31=γt31-βt30

Write the expression for t¯12.

t¯12=λ1σ2tλσ

Expand the above expression.

t¯12=0102t00+0112t01+0022t02+1102t10+1112t11+1122t12+1102t20+2112t21+2123t22

From equations (1) and (2),

t¯12=0+0+-γβt02+0+0+γt12+0+0+0t¯12=-γβt02+γt12t¯12=γt12-βt02

Therefore, all the remaining five parts to equation 12.118 is proved.

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