Where is Btnonzero in Figure 7.21(b)? Exploit the analogy between Faraday's law and Ampere's law to sketch (qualitatively) the electric field.

Short Answer

Expert verified

The term Btis nonzero along the left and right edges of the shaded rectangle.

Step by step solution

01

Define Faraday's Law.

Faraday's law is the most fundamental law in Electromagnetic induction, which depicts that whenever a conductor is placed in the magnetic field, which is variable in nature, then an EMF will be induced in the conductor if the conductor has been short circuited, then current will flow in the conductor.

02

Determine the nonzero position of ∂B∂t

The figure concludes that the (inward) flux through the strip on the left isincreasing. On the contrary, the (inward) flux passing through the strip on the right decreases, similar to the two current sheets under Ampere's circuital law.

Now, withBE andμ0Iencdt from equation 7.19, the significance of the negative sign is that the current has been flown out to one on the left, so its field is counter clockwise, and the one on the right is like a current flowing in, so it field is clockwise.

The diagram of the above description is shown below:

Therefore, the termBt is nonzero along the left and right edges of the shaded rectangle.

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Most popular questions from this chapter

A metal bar of mass m slides frictionlessly on two parallel conducting rails a distance l apart (Fig. 7 .17). A resistor R is connected across the rails, and a uniform magnetic field B, pointing into the page, fills the entire region.


(a) If the bar moves to the right at speed V, what is the current in the resistor? In what direction does it flow?

(b) What is the magnetic force on the bar? In what direction?

(c) If the bar starts out with speedV0at time t=0, and is left to slide, what is its speed at a later time t?

(d) The initial kinetic energy of the bar was, of course,12mv2Check that the energy delivered to the resistor is exactly 12mv2.

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(a) using Eq. 7.30 (you found L in Prob. 7.24);

(b) using Eq. 7.31 (we worked out A in Ex. 5.12);

(c) using Eq. 7.35;

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An alternating current I(t)=I0cos(ωt) (amplitude 0.5 A, frequency ) flows down a straight wire, which runs along the axis of a toroidal coil with rectangular cross section (inner radius 1cm , outer radius 2 cm , height 1 cm, 1000 turns). The coil is connected to a 500Ω resistor.

(a) In the quasistatic approximation, what emf is induced in the toroid? Find the current, IR(t), in the resistor.

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