Imagine a uniform magnetic field, pointing in the zdirection and filling all space (B=B0z). A positive charge is at rest, at the origin. Now somebody turns off the magnetic field, thereby inducing an electric field. In what direction does the charge move?

Short Answer

Expert verified

The direction of the charge is indetermined.

Step by step solution

01

Write the given data from the question.

The uniform magnetic field B=B0z,

The initial magnetic field isB

The positive charge is at rest.

02

Determine the direction of the charge move.

Let assume the charge isqat the rest, and Eis the electric field.

The force experienced by the charges at the rest is given by,

F=qE

The curl of the electric field is given by,

×E=BC^tZ

Since the boundary condition is not mentioned therefore, it is difficult to move the electric field.

The electric field attain the zero value at infinity. Hence the direction of the charge is in determined due to no boundary condition.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A rectangular loop of wire is situated so that one end (height h) is between the plates of a parallel-plate capacitor (Fig. 7.9), oriented parallel to the field E. The other end is way outside, where the field is essentially zero. What is the emf in this loop? If the total resistance is R, what current flows? Explain. [Warning: This is a trick question, so be careful; if you have invented a perpetual motion machine, there's probably something wrong with it.]


A square loop is cut out of a thick sheet of aluminum. It is then placed so that the top portion is in a uniform magnetic field , B and is allowed to fall under gravity (Fig. 7 .20). (In the diagram, shading indicates the field region; points into the page.) If the magnetic field is 1 T (a pretty standard laboratory field), find the terminal velocity of the loop (in m/s ). Find the velocity of the loop as a function of time. How long does it take (in seconds) to reach, say, 90% of the terminal velocity? What would happen if you cut a tiny slit in the ring, breaking the circuit? [Note: The dimensions of the loop cancel out; determine the actual numbers, in the units indicated.]

Question:Calculate the energy stored in the toroidal coil of Ex. 7.11, by applying Eq. 7.35. Use the answer to check Eq. 7.28.

A square loop, side a , resistance R , lies a distance from an infinite straight wire that carries current l (Fig. 7.29). Now someone cuts the wire, so l drops to zero. In what direction does the induced current in the square loop flow, and what total charge passes a given point in the loop during the time this current flows? If you don't like the scissors model, turn the current down gradually:

I(t)={(1-t)I0for0t1/afort>/a

An alternating current l=l0cos(wt)flows down a long straight wire, and returns along a coaxial conducting tube of radius a.

(a) In what direction does the induced electric field point (radial, circumferential, or longitudinal)?

(b) Assuming that the field goes to zero as s, findE=(s,t).

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free