Suppose there did exist magnetic monopoles. How would you modifyMaxwell's equations and the force law to accommodate them? If you think thereare several plausible options, list them, and suggest how you might decide experimentally which one is right.

Short Answer

Expert verified

The correctly modified Maxwell’s equation isF=α04πqm1qm2r2r^ .

Step by step solution

01

Determine the Maxwell’s equation

Write the Maxwell’s equation.

E=ρÎ0    (Gausslaw)×E=0B=0

Write the amperes law

B=μ0J

02

Determine the right Maxwell’s equation 

As the magnetic monopole exists then there will be no change in Ampere’s law and gauss law.

Actually B=0implies there will be no magnetic monopoles.Then if magnetic monopoles exist, then

B=α0ρm

Hereρm,is the density of magnetic change andα0is the same constant.

Rewrite the Maxwell’s equation as

×E=β0Jm

Here, Jmis the magnetic current density andβ0is another constant.

Thus, magnetic charge is conserved. Hence, ρmandJmsatisfy continuity equation and is written as

Jm+ρmt=0

Write the expression for force on magnetic monopole.

F=qm[B+(υ×E)]

Consider both the equation directionally not correct.

Here, Ehas same units asυB .

Hence, divide υ×Ewith dimensions of velocity squared and rewrite the equation as

F=qe[E+(υ×B)]+qm[B1c2(υ×E)]

Now, write the expression for magnetic field along the lines ofCoulomb’s law.

.

F=α04πqm1qm2r2r^

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Most popular questions from this chapter

Consider the motion of a particle with mass m and electric charge qein the field of a (hypothetical) stationary magnetic monopole qmat the origin:

B=μ04qmr2r^

(a) Find the acceleration of qe, expressing your answer in terms of localid="1657533955352" q, qm, m, r (the position of the particle), and v(its velocity).

(b) Show that the speed v=|v|is a constant of the motion.

(c) Show that the vector quantity

Q=m(r×v)-μ0qeqm4πr^

is a constant of the motion. [Hint: differentiate it with respect to time, and prove-using the equation of motion from (a)-that the derivative is zero.]

(d) Choosing spherical coordinates localid="1657534066650" (r,θ,ϕ), with the polar (z) axis along Q,

(i) calculate , localid="1657533121591" Qϕ^and show that θis a constant of the motion (so qemoves on the surface of a cone-something Poincare first discovered in 1896)24;

(ii) calculate Qr^, and show that the magnitude of Qis

Q=μ04π|qeqmcosθ|;

(iii) calculate Qθ^, show that

dt=kr2,

and determine the constant k .

(e) By expressing v2in spherical coordinates, obtain the equation for the trajectory, in the form

drdϕ=f(r)

(that is: determine the function )f(r)).

(t) Solve this equation for .r(ϕ)

The magnetic field on the axis of a circular current loop (Eq. 5.41) is far from uniform (it falls off sharply with increasing z). You can produce a more nearly uniform field by using two such loops a distanced apart (Fig. 5.59).

(a) Find the field (B) as a function of z, and show that Bz is zero at the point midway between them (z = 0)

(b) If you pick d just right, the second derivative of B will also vanish at the midpoint. This arrangement is known as a Helmholtz coil; it's a convenient way of producing relatively uniform fields in the laboratory. Determine d such that 2B/z2=0 at the midpoint, and find the resulting magnetic field at the center. [Answer:8μ0I55R ]

What current density would produce the vector potential, A=kϕ^(where kis a constant), in cylindrical coordinates?

A thin glass rod of radius Rand length Lcarries a uniform surfacecharge δ .It is set spinning about its axis, at an angular velocity ω.Find the magnetic field at a distances sR from the axis, in the xyplane (Fig. 5.66). [Hint:treat it as a stack of magnetic dipoles.]

Magnetostatics treats the "source current" (the one that sets up the field) and the "recipient current" (the one that experiences the force) so asymmetrically that it is by no means obvious that the magnetic force between two current loops is consistent with Newton's third law. Show, starting with the Biot-Savart law (Eq. 5.34) and the Lorentz force law (Eq. 5.16), that the force on loop 2 due to loop 1 (Fig. 5.61) can be written as

F2=μ04πl1l2r^r2dl1dl2

Figure 5.60

Figure 5.61

In this form, it is clear that F2=-F1, since role="math" localid="1657622030111" r^changes direction when the roles of 1 and 2 are interchanged. (If you seem to be getting an "extra" term, it will help to note thatdl2r^=dr.)

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