Chapter 3: Q14P (page 140)
For the infinite slot (Ex. 3.3), determine the charge density on
the strip at , assuming it is a conductor at constant potential .
Short Answer
Answer
The equation for the charge density on the strip at is .
Chapter 3: Q14P (page 140)
For the infinite slot (Ex. 3.3), determine the charge density on
the strip at , assuming it is a conductor at constant potential .
Answer
The equation for the charge density on the strip at is .
All the tools & learning materials you need for study success - in one app.
Get started for freeUse Green's reciprocity theorem (Prob. 3.50) to solve the following
two problems. [Hint:for distribution 1, use the actual situation; for distribution 2,
removeq,and set one of the conductors at potential .]
(a) Both plates of a parallel-plate capacitor are grounded, and a point charge qis
placed between them at a distance xfrom plate 1. The plate separation is d. Find the induced charge on each plate. [Answer: ;]
(b) Two concentric spherical conducting shells (radii aand b)are grounded, and a point charge is placed between them (at radius r). Find the induced charge on each sphere.
Prove that the field is uniquely determined when the charge density
is given and either V or the normal derivative a is specified on each boundary surface. Do not assume the boundaries are conductors, or that V is constant over any given surface.
In Ex. 3.8 we determined the electric field outside a spherical conductor
(radiusR)placed in a uniform external field . Solve the problem now using
the method of images, and check that your answer agrees with Eq. 3.76. [Hint:Use
Ex. 3.2, but put another charge, -q,diametrically opposite q.Let, withheld constant.]
The potential at the surface of a sphere (radius ) is given by
,
Where is a constant. Find the potential inside and outside the sphere, as well as the surface charge density on the sphere. (Assume there's no charge inside or outside the sphere.)
You can use the superposition principle to combine solutions obtained by separation of variables. For example, in Prob. 3.16 you found the potential inside a cubical box, if five faces are grounded and the sixth is at a constant potential ; by a six-fold superposition of the result, you could obtain the potential inside a cube with the faces maintained at specified constant voltages . In this way, using Ex. 3.4 and Prob. 3.15, find the potential inside a rectangular pipe with two facing sides at potential , a third at . and the last at grounded.
What do you think about this solution?
We value your feedback to improve our textbook solutions.