(a) Show that the quadrupole term in the multipole expansion can be written as

Vquad(r)=14πε01r3i,j-13ri^rj^Qij ............(1)

(in the notation of Eq. 1.31) where

Qij=12[3r'jr'j-(r')2δij]ρ(r')dτ' ..........(2)

Here

δij={10ifi=jifij ..........(3)

is the Kronecker Delta and Qijis the quadrupole moment of the charge distribution. Notice the hierarchy

Vmon=14πε0Qr;Vdip=14πε0rjpj^r2;Vquad(r^)=14πε01r3ij-13rirj^^Qij;......

The monopole moment (Q) is a scalar, the dipole moment p is a vector, the quadrupole moment Qij is a second rank tensor, and so on.

(b) Find all nine componentsQij of for the configuration given in Fig. 3.30 (assume the square has side and lies in the x-y plane, centered at the origin).

(c) Show that the quadrupole moment is independent of origin if the monopole and

dipole moments both vanish. (This works all the way up the hierarchy-the

lowest nonzero multipole moment is always independent of origin.)

(d) How would you define the octopole moment? Express the octopole term in the multipole expansion in terms of the octopole moment.

Short Answer

Expert verified

Answer

(a) We have proved that the quadrupole term in the multipole expansion can be written in terms of the quadrupole moment as

Vquadr^=18πε01r3ρr'dτ'3cos2θ'-1r'2.

(b) For the charge configuration shown in Fig. 3.30, we have found out the nine components of the quadrupole moment. We have obtainedQxy=Qyx=3qa22. The rest of the terms are zero.

(c) We have proved that the quadrupole moment is independent of the choice of origin if the monopole and dipole moments vanish.

(d) We have derived an expression for the octopole moment as

Step by step solution

01

Given data

The quadrupole moment can be written as

.

The Kronecker Delta function can be defined as

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