Show that [Aeikx+Be-ikx] and [Ccos(kx)+Dsin(kx)] are equivalent ways of writing the same function of x, and determine the constants C and D in terms of Aand B, and vice versa.

Short Answer

Expert verified

The constants Cand Din terms of Aand B, and vice versa are,

(i) C=A+Band D=i(A-B)

(ii)A=12(C-iD);B=12(C+iD)

Step by step solution

01

Step 1:Formulae used

The required formula are

eikx=(cos(kx)+isin(kx))

e-ikx=(cos(kx)-isin(kx))

cos(kx)=(eikx+e-ikx2)

sin(kx)=D(eikx-e-ikx2)

02

Compute C and D in terms of A and B and vice versa

Apply Euler's formula,

Aeikx+Be-ikx=A(cos(kx)+isin(kx))+B(cos(kx)-isin(kx))

=(A+B)cos(kx)+i(A-B)sin(kx)

=Ccos(kx)+Dsin(kx)

Thus, Cand Dexpressed in terms of arbitrary constants Aand B, C=A+B

D=i(A-B)

Now, Solve both the equations for Aand B and get,

Ccos(kx)+Dsin(kx)=Ceikx+eikx2+Deikx-ekx2i

=12(C-iD)eikx+12(C+iD)eikx

=AeAx+Beixx

Therefore, the values of A and B are,

A=12(C-iD)B=12(C+iD)

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