Evaluate the following integrals:

(a)-3+1(x3-3x2+2x-1)δ(x+2)dx.

(b).0[cos(3x)+2]δ(x-π)dx

(c)_1+1exp(lxl+3)δ(x-2)dx

Short Answer

Expert verified
  • -3+1(x3-3x2+2x-1)δ(x+2)dx=-25
  • 0[cos(3x)+2]δ(x-π)dx=1
  • _1+1exp(lxl+3)δ(x-2)dx=0

Step by step solution

01

Significance of the integral

In mathematics, an integral lends numerical values to functions to represent concepts like volume, area, and displacement that result from combining infinitesimally small amounts of data. In mathematics, an integral lends numerical values to functions to represent concepts like volume, area, and displacement that result from combining infinitesimally small amounts of data.

02

(a) Evaluating the integral

Let,

-3+1x3-3x2+2x-1δx+2dx

According to impulse property,

x+2=0x=-2

In given function, substitutex=-2.

x3-3x2+2x-1=(-2)3-3(-2)2+2(-2)-1=-8-12-4-1=-25

Hence the value of is -3+1(x3-3x2+2x-1)δ(x+2)dx=-25.

03

:(b) Evaluating the integral

Let,

0cos3x+2δx-πdx

In given function, substitute x=π, x-π=0x=π.

Then,

cos3π+2=-1+2=1

Hence the value of 0cos3x+2δx-πdxis, 1.

04

(c) Evaluating the integral

Let,

-1+exp(l×l+3)δ(x-2)dx

Then,

-1+1expl×l+3δx-2dx=0

0 (x=2is outside the domain of integration).

Because x=2 is out of the integration interval.

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